algebra equation

(50+5)(50+5)

(50+5)(50+5) = 2500+250+250+25 = 2500+250+250+25 = 3025

1/3 x+1/4 = x - 1/6

12[4x+3 = 12x -2] 5 = 8x 5/8 = x

Elimination method/addition method 2x + 3y = 8 5x - 3y = -1

2x + 3y = 8 5x - 3y = -1 eliminate the y 7x = 7 7x/7 = 7/7 X = 1 subtitute the x to get the value of y 2(1) + 3y = 8 2 + 3y = 8 3y = 8-2 3y = 6 3y/3 = 6/3 Y = 2 (1,2)

4x +2y =14 3x - 5y = -22

2y/2 = 14/2 - 4x/2 Y = 7 - 2x 3x -5(7 -2x) = -22 3x -35 +10x = -22 13x = 35 -22 13x = 13 X = 1 Y = +7 - 2(1) Y = +7 -2 Y = 5

Y = 5 - 2x 4x + 3y = 13

4x + 3 (5-2x) = 13 4x + 15 -6x = 13 -2x = -2 -2x/-2 = -2/-2 X = 1 Y = 5 - 2(1) Y = 5 -2 Y = 3 (1,3)

6 = x + 2x

6 = 3x 6/3 = 3x/3 2 = x

Y = 3x + 2 Y = 7x - 6

7x - 6 = 3x + 2 4x = 8 4x/4 = 8/4 X = 2 y = 3(2) + 2 y = 6 + 2 y = 8 (2,8)

Elimination method >> combination method>>substitution method 2x + 5y = 19 X - 2y = -4

This simultaneous equation need to modify by multiplying what is missing to combine 2x + 5y = 19 (x - 2y = -4)-2 2x + 5y = 19 -2x +4y = 8 9y = 27 9y/9 = 27/9 Y = 3 Now substitute the y to get x X - 2 (3) = -4 X -6 = -4 X = -4+6 X = 2 or 2x + 15 = 19 2x = 19 -15 2x = 4 X =2 (2,3)

[3/x^2-7x+10] +2 = [x-4/x-5]

X^2 - 7x +10 factor this first =(x-2) (x-5) (x-2) (x-5)[3/x^2-7x+10] +2 = [x-4/x-5] 3 + 2(x-2)(x-5) = (x-2)(x-4) 3 + 2(x^2-5x-2x+10) = x^2-4x-2x+8 3 + 2x^2 -10x-4x+20 = x^2 -6x + 8 2x^2 - 10x-4x +23 = x^2 -6x+8 x^2 -8x +15 = 0 (x-5)(x-3)=0 {X=5} {x=3}

x(1/2)6 = 18

x/2(6) = 18 x/2 6 3x = 18 x = 6

1/6 + 1/3 = 1/x

you need to multiply every fraction that something that will get rid of all the denominator of each fraction like 6x because both two fraction can be divide by it 6x[1/6 + 1/3 = 1/x] 1x + 2x = 6 3x = 6 3x/3 = 6/3 x = 2