ANSWERS QR

9th problem = C

$6 per day for let's say, 5 days = $6(5) plus the $2.50 for cleaning. This is what 6w + $2.50 says.

36th problem = B

column A = 29 Column B = 30 - remember you must multiply first

5th problem = C

2 times ANY number creates an even number.

26th problem = C

48 books divided into groups of 12 would give you 4 groups or 4 boxes.

11th problem = D

5 X 5 = 25 plus 2 = 27/5

2nd problem = D

8 is the square root of 64 and 9 is the square root of 81. 75 is between 64 and 81.

25th problem = C

All equilateral triangles are triangles and all triangles have 3 sides.

22nd problem = B

All sides of a square are equal. To obtain the area, you multiply two of the sides together. So, each side would have to be 5 because 5 x 5 = 25.

19th problem =D

D - none of those statements are true.

27th problem = I

Expressions 2 and 3 are going to give you positive numbers. 2 = 6 and 3 = 3. Expressions 1 and 4 will give you negative numbers so, you must decide which one is smallest. Expression 1 = - 0.5453 and expression 4 = -27 which is less than expression 1 because it is further away from 0 on the negative side of the number line.

14th problem = B

For every $1 Tamika sells, she gets 12% or $0.12. If she sold $3740, we multiply .12 x 3740 and we get $449. However, you can rule out all the other answers without doing this math. 12% is less than half so, C and D don't work. 12% is also more than 10% which would be $374, so this rules out A.

7th problem = B

If 200 people donated let's say, $5 each, then the total amount donated would be $1000 because 200 $5 bills is $1000. So, you have multiplied in order to obtain your answer.

6th problem = D

If R = 9, then 3P - 9 = 23 and 3P = 32. Then P = 10.667. Although this makes P greater than zero, it makes P something other than an integer.

3rd problem = A

If a number is prime (divisible by 1 and itself only) it can not also be divisible by 4.

15th problem = A

If the entire rectangle is worth 60 and it is divided into 15 regions, each region is worth 4. 60 divided by 15 = 4.

29th problem = I

If the mean of 6 numbers is 235, then the sum of the 6 numbers must = 235 times 6 which is 1410. The sum of the first 5 scores = 1145. 1410 - 1145 = 265. So, he needs 265 points to reach his goal.

28th problem = C

If the median (the number in the middle of the list after the numbers have been put in numerical order) does not change, the number that is in the middle of the 1st list will be the same as the number in the middle of the second list. So, the median of the first list is 89 which means if you add 2 more numbers, one has to be greater than 89 and one has to be smaller so that there are 4 numbers larger and 4 numbers smaller than 89.

24th problem = B

If there are 18 boys, there are 30 girls. The ratio of girls (30) to the class (48) is 30/48 (divide both by 6) = 5/8.

34th problem = C

In one and one fourth hours (between 1 and 1.5), she walked 1 mile. In the next half hour she walked .6 miles ( the downward line), then she walked .4 miles (upward line) and last (the other downward line) she walked .8 miles. 1 + .6 + .4 + .8 = 2.8

21st problem = C

It doesn't matter whether you are looking for 1/4 or 3 times the expressions. What you really want is to find the largest expression. If X > Y, then 1/4 of X is greater than 1/4 of Y and 3X is greater than 3Y. So, let's give a value to A and say it is = to 9. A-1 = 8, A = 9, A + 3 = 12, and (A/3) +1 = 4. So, A + 3 is the largest. This is also true if A would have been a negative number.

10th problem = D

It rained a total of 4 cm between 7 and 8. 0 -4 was 2 cm, 4 - 6 was 0 cm, and 6 -7 was 1 cm.

31st problem = A

Karla was successful 1/3 of the time (24 divided by 8 = 3). Becky was successful 1/4 of the time (20 divided by 5 = 4). After 180 throws, Karla should have 60 (180 divided by 3) and Becky should have 45 (180 divided by 4). 60-45=15

17th problem = A

Let's look at D. If Jordan has 16 toys then Paige has 21. Oops, too much. C would give Jordan 11 toys and Paige 16. Too much again. B would give Jordan 8 toys and Paige would then have 13 and that's still too much. So, Jordan has 6 toys, Paige has 11 which gives Bill 3. 6 + 11 + 3 = 20. If you started at D and saw it was way too big, go back to the smallest and compare. That way you don't have to use all of the numbers and it will save you time.

16th problem = B

Let's play the rule out game again. 90 squared is 8100 - way too big so it's not D. 9 squared is only 81, way too small. That leaves only B and C. 20 squared is 400, still not close. 10 squared is 100 which is the closest.

4th problem = D

M = 7. 6 times 7 = 42 - 8 = 34. So, 7 + 10 = 17

8th problem = B

Sandy has worked 64 hours so she has 36 more hours to go (100-64 = 36). 36 divided by 9 hours per week = 4 weeks.

18th problem = B

Since we are looking for all of these multiplied by 600, we only need to know which of the 1st numbers is largest. It isn't 1/4 because it is smaller than 1/3 so rule out D right away. Change the other 3 to decimals and you have .30, .33, and .333.....(it never ends). Of these three, .333... is the largest. Not by much, but still larger.

23rd problem = C

Start by comparing the numerators to their denominators. Look at 3/7. 3 is less than 1/2 of 7 so 3/7 < 1/2. Same with 4/9, 4 is less than 1/2 of 9 so 4/9 < 1/2. 5 IS 1/2 of 10 so 5/10 = 1/2, and 6/is less than half of 13 so 6/13 is less than 1/2. Therefore A, B and D are all less than 1/2 which is what C is equal to.

49th problem = D

The $50 would be more if say x = 10 - it would then sell for $45 which would be more than the other no matter what the discount was. However, if x = 50 and y = 10, then the first sweater would sell for $25 and the second for $36.

1st problem = C

The 1st commercial got 25% or 1/4 of the votes which is 250. The 2nd commercial got 2/5 of the 1000 votes which is 400. 1000 - 250 - 400 = 350.

13th problem = C

The CD is about $13. You can tell from the answers, that's where it has been rounded to. So, 25% is = .25, therefore the answer is C

33rd problem = B

The candy is divided into 12 pieces. If he gave his sister 1/4 that would be 3 pieces and he would have 9 pieces left. If he ate 1/3 of the 9 pieces (which is 3) he would have 6 pieces left. B has 6 pieces.

20th problem = B

The employee sold 36 televisions. In 2006, there were 12 Jack's televisions sold. 12 is 1/3 of 36 (36 divided by 12 = 3)

30th problem = B

The median the number in the middle after the numbers are in numerical order. They are already in order and there are 3 numbers lower than 25 and 3 that are greater than 25. Note that there are 2 X's on 28, so your numbers are 18, 19. 20, 25, 26, 28, 28.

35th problem = A

The smiley face and the arrow are beside each other in the right direction. The arrow in C would be on top of the box or if it pointed downward, the smiley face would be on its side. In D, the arrow would be on the right side of the sun instead of the left and B, like C, the arrow is pointing the wrong direction.

12th problem = C

There are 4 rows or 4 cubes in the base of the figure. There are an additional 4 cubes on top of these 16 cubes that are in the base. There are 20 total cubes.

48th problem = D

There are no measurements or ratios to compare the two.

45th problem = D you can not tell

You can not find the length of BC. Draw the line and look at the segments.

32nd problem = I

You need to divide the total cost by the number of bulbs purchased to find the cost for each light bulb. 147.60 divided by 90 = 1.64 - the smallest of the 4.

51st problem = B

column A = $24 column B = $25. 50 apples at .50 each = $25.

50th problem = A

column A = -1/5 column B = -1. If 5x + 10y = 12 then y = 12/10 - 5/10x (slope is coefficient of x). (3,4) (6,1) slope = (1-4) / (6-3) = -3/3 = -1

44th problem = C - they are equal

column A = 1/10 column B = 1/10. The probability of choosing a yellow first is 3/15 then a red is 7/14 (there are only 14 left). The probability of choosing a red first is 7/15 then a yellow is 3/14. In each case you must multiply the two fractions and then reduce them both to 1/10.

47th problem = B

column A = 1/12 column B = 1/4 Flipping tails on a coin is 1/2 AND rolling a 3 is 1/6. 1/2 x 1/6 = 1/12. Rolling an even number is 1/2 AND rolling an odd number is 1/2. 1/2 x 1/2 = 1/4 which is larger than 1/12

37th problem = A

column A = 11/3 column B = 11/8 - if you divide something by a larger number the answer is smaller

46th problem = B

column A = 12 column B = 16. 1/5 of the 15 shots is 3. 4 of those is 12. If he makes 4/5 of his shots then he misses 1/5. So, 1/5 of 80 = 16

40th problem = B

column A = 33 1/3 column B = 35 (the average miles per hour is 30 + 30 + 40 = 100 - there were two hours at 30 - and divided by 3 hours = 33 1/3

52nd problem = C

column A = 4 column B = 4

42nd problem - oops I skipped # 41

column A = 5 column B = 3. The slope of the line is the coefficient of X in the equation. If X = 3, then Y = 15 - 12

43rd problem = C - they are equal

column A = 6 column B = 3 You need four of the 5 cm cubes, one of the 4 cm cubes and one of the 3 cm cubes to = 27

38th problem = A

column A = 8 (the square root of 64) column B = 4 (10-6)

39th problem = A

column A is 11 column B is 10 (the 3 consecutive integers are 9, 10, and 11)