AS 121 Gleim 11

Fig 68 The line from point A to point B of the wind triangle represents true heading and airspeed. true course and groundspeed. groundspeed and true heading.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The line connecting point A to point B on the wind triangle represents the true heading and airspeed line.

Fig 68 The line from point C to point A of the wind triangle represents wind direction and velocity. true course and groundspeed. true heading and groundspeed.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The line from point C to point A on the wind triangle represents the wind direction and velocity line.

Fig 25 Estimate the time en route from Addison (area 2) to Dallas Executive (area 3). The wind is from 300° at 15 knots, the true airspeed is 120 knots, and the magnetic variation is 7° east. 8 minutes. 11 minutes. 14 minutes.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. To find the en route time from Addison (south of 2) to Dallas Executive (area 3), use Fig. 25. 2. Using the associated scale on the side of the chart, measure the distance to be 18 NM. 3. TC = 186°. 4. Mark up 15 kt. with 300° under true index. 5. Put TC of 186° under true index. 6. Slide the grid so the pencil mark is on TAS of 120 kt. 7. Read the groundspeed of 125 kt. under the grommet. 8. On the calculator side, place 125 kt. on the outer scale over 60 min. 9. Read 8.5 min. on the inner scale below 18 NM on the outer scale.

Fig 25 What is the estimated time en route for a flight from Denton (area 1) to Addison (area 2)? The wind is from 200° at 20 knots, the true airspeed is 110 knots, and the magnetic variation is 7° east. 13 minutes. 16 minutes. 19 minutes.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. To find the en route time from Denton (southwest of 1) to Addison (south of 2), use Fig. 25. 2. Using the associated scale on the side of the chart, measure the distance to be 22 NM. 3. TC = 128°. 4. Mark up 20 knots with 200° under true index. 5. Put TC of 128° under true index. 6. Slide the grid so the pencil mark is on TAS of 110 knots. 7. Read the groundspeed of 102 knots under the grommet. 8. On the calculator side, place 102 knots on the outer scale over 60 minutes. 9. Read 13 minutes on the inner scale below 22 NM on the outer scale.

Fig 24 Estimate the time en route from Majors Airport (area 1) to Winnsboro Airport (area 2). The wind is from 340° at 12 knots and the true airspeed is 136 knots. Magnetic variation is 5° east. 17 minutes 30 seconds. 14 minutes 30 seconds. 19 minutes.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. Measure the distance between Majors Airport and Winnsboro Airport using the associated scale located on the side of the chart. You should find the distance to be about 41 NM. Use your plotter to find a true course of 100°. Using your flight computer, place 340° under the true index and mark a wind speed of 12 knots. Place 100° under the true index and slide the card so the true airspeed arc of 136 knots is under the wind dot. The flight computer should indicate a groundspeed of approximately 140 knots. Turn the flight computer over and place the pointer on 14 for 140 knots groundspeed. Follow the outer scale to 41 for 41 NM and read a time of approximately 17:30 below the 41 on the outer scale.

How far will an aircraft travel in 7.5 minutes with a ground speed of 114 knots? 14.25 NM. 15.00 NM. 14.50 NM.

Answer (A) is correct. (FAA-H-8083-25B Chap 16) ( ? ) To determine the distance traveled in 7.5 minutes at 114 knots, first determine the distance traveled per minute (114 ÷ 60 = 1.9). In 1 minute, the aircraft travels 1.9 NM. Thus, in 7.5 minutes, the plane will have traveled 14.25 NM (1.9 × 7.5 = 14.25). Alternatively, put 114 on the outer scale of your flight computer over the index on the inner scale. Find 7.5 minutes on the inner scale, above which is 14.25 miles.

Fig 62 In flying the rectangular course, when would the aircraft be turned less than 90°? Corners 1 and 4. Corners 1 and 2. Corners 2 and 4.

Answer (A) is correct. (FAA-H-8083-3B Chap 6) ( ? ) When doing a rectangular course, think in terms of traffic pattern descriptions of the various legs. In Fig. 62, note that the airplane is going counterclockwise about the rectangular pattern. While on the base leg (between corners 3 and 4), the airplane is crabbed to the inside of the course. Thus, on corner 4, less than a 90° turn is required. Similarly, when the airplane proceeds through corner 1, it should roll out such that it is crabbed into the wind, and, again, a less-than-90° angle is required.

On a cross-country flight, point A is crossed at 1500 hours and the plan is to reach point B at 1530 hours. Use the following information to determine the indicated airspeed required to reach point B on schedule. Distance between A and B 70 NM Forecast wind 310° at 15 kt. Pressure altitude 8,000 ft. Ambient temperature -10°C True course 270° The required indicated airspeed would be approximately 126 knots. 137 knots. 152 knots.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) First determine the required groundspeed to reach point B at 1530 by placing 70 NM on the outer scale over 30 minutes on the inner scale to determine a groundspeed of 140 kt. On the wind side of the computer, put the wind direction of 310° under the true index and put a pencil mark 15 kt. up from the grommet. Next, turn the inner scale so the 270° true course is under the true index and put the grommet over the groundspeed. Note that to obtain the 140-kt. groundspeed, you need a 152-kt. true airspeed. Next, on the computer side, put the air temperature of -10°C over 8,000 ft. altitude. Then find the true airspeed of 152 kt. on the outer scale, which lies over approximately 137 kt. indicated airspeed on the inner scale.

Fig 23 While en route on Victor 185, a flight crosses the 248° radial of Allendale VOR at 0953 and then crosses the 216° radial of Allendale VOR at 1000. What is the estimated time of arrival at Savannah VORTAC? 1023. 1028. 1036.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The first step is to find the three points involved. V185 runs southeast from the top left of Fig. 23. The first intersection (V70 and V185) is about 1 in. from the top of the chart. The second intersection (V157 and V185) is about 1-1/2 in. farther along V185. The Savannah VORTAC is about 6 in. farther down V185. Use the sectional scale located at the top of the chart. From the first intersection (V70 and V185), it is about 10 NM to the intersection of V185 and V157. From there it is 40 NM to Savannah VORTAC. On your flight computer, place the 7 min. the first leg took (1000 - 0953) on the inner scale under 10 NM on the outer scale. Then find 40 NM on the outer scale. Read 28 min. on the inner scale, which is the time en route from the V185 and V157 intersection to the Savannah VORTAC. Arrival time over Savannah VORTAC is therefore 1028.

Fig 68 The line from point C to point B of the wind triangle represents airspeed and heading. groundspeed and true course. true heading and groundspeed.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The line from point C to point B, on the wind triangle, represents the true course and groundspeed line.

Fig 22 What is the estimated time en route for a flight from St. Maries Airport (area 4) to Priest River Airport (area 1)? The wind is from 300° at 14 knots and the true airspeed is 90 knots. Add 3 minutes for climb-out. 38 minutes. 43 minutes. 48 minutes.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. Time en route from St. Maries Airport (southeast of 4) to Priest River Airport (upper left corner) on Fig. 22. 2. Using the scale at the top of the chart, measure the distance to be 54 NM. 3. TC = 346°. 4. Mark up 14 knots with 300° under true index. 5. Put TC of 346° under true index. 6. Slide the grid so the pencil mark is on TAS of 90 knots. 7. Read the groundspeed of 80 knots under the grommet. 8. On the calculator side, place 80 knots on the outer scale over 60 minutes. 9. Find 54 NM on the outer scale and read 40 minutes on the inner scale. 10. Add 3 minutes for climb-out to get time en route of 43 minutes.

Figure 21 What is the estimated time en route from Mercer County Regional Airport (area 3) to Minot International (area 1)? The wind is from 330° at 25 knots and the true airspeed is 100 knots. Add 3-1/2 minutes for departure and climb-out. 45 minutes. 48 1/2 minutes. 52 minutes.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. Using Fig. 21, the time en route from Mercer Co. Reg. Airport (lower left corner) to Minot (right of 1) is determined by measuring the distance (60 NM measured with the associated scale at the bottom of the chart), determining the time based on groundspeed, and adding 3.5 minutes for takeoff and climb. The TC is 012° as measured with a plotter. The wind is from 330° at 25 knots. On the wind side of your flight computer, place the wind direction 330° under the true index and mark 25 knots up. Rotate TC of 012° under the true index. Slide the grid so the pencil mark is on the arc for TAS of 100 knots. Read 80 knots groundspeed under the grommet. Turn to the calculator side and place the groundspeed of 80 knots on the outer scale over 60 minutes. Find 60 NM on outer scale and note 45 minutes on the inner scale. Add 3.5 minutes to 45 minutes for climb for en route time of 48.5 minutes.

Fig 23 What is the estimated time en route for a flight from Claxton-Evans County Airport (area 2) to Hampton Varnville Airport (area 1)? The wind is from 290° at 18 knots and the true airspeed is 85 knots. Add 2 minutes for climb-out. 35 minutes. 39 minutes. 43 minutes.

Answer (B) is correct. (FAA-H-8083-25B Chap 16) ( ? ) Using the sectional scale located at the top of the chart, you will find the distance en route from Claxton-Evans (southwest of 2) to Hampton Varnville (east of 1 on Fig. 23) is approximately 57 NM. Use your plotter to determine that the TC is 045°. The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. Using the wind side of your computer, turn your true index to the wind direction of 290° and mark 18 knots above the grommet with your pencil. Then turn the inner scale so that the true index is above the TC of 045°. Place the pencil mark on the TAS of 85 knots and note the groundspeed of 91 knots. Turn your flight computer over and set the speed of 91 knots above the 60-minutes index on the inner scale. Then find the distance of 57 NM on the outer scale to determine a time en route of 37 minutes. Add 2 minutes for climb-out, and the en route time is 39 minutes.

What should be expected when making a downwind landing? The likelihood of undershooting the intended landing spot and a faster airspeed at touchdown. overshooting the intended landing spot and a faster groundspeed at touchdown. undershooting the intended landing spot and a faster groundspeed at touchdown.

Answer (B) is correct. (FAA-H-8083-25B, AC 91-79A) The effect of a downwind landing is an increased groundspeed, which can increase the likelihood of overshooting the intended landing spot.

Fig 66 While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is not completed before crossing the road or reference line. This would most likely occur in turn 1-2-3 because the bank is decreased too rapidly during the latter part of the turn. 4-5-6 because the bank is increased too rapidly during the early part of the turn. 4-5-6 because the bank is increased too slowly during the latter part of the turn.

Answer (B) is correct. (FAA-H-8083-3B Chap 6) ( ? ) Note that the wind in Fig. 66 is coming up from the bottom rather than from the top. The consistently smaller half-circle is made when on the upwind side of the road, i.e., 4-5-6. The initial bank is increased too rapidly, resulting in a smaller half-circle. Then an attempt is made to widen the turn out in the latter stages. Thus, the recrossing of the road is done at less than a 90° angle.

Fig 62 In flying the rectangular course, when should the aircraft bank vary from a steep bank to a medium bank? Corner 1. Corner 3. Corner 2 and 3.

Answer (B) is correct. (FAA-H-8083-3B Chap 6) ( ? ) When flying a rectangular course, imagine that the course is a traffic pattern at an airport. On the downwind leg, the wind is a tailwind and results in an increased groundspeed. Accordingly, the turn on the next leg requires a fast roll-in with a steep bank. When the tailwind component diminishes, the bank angle is reduced.

To minimize the side loads placed on the landing gear during touchdown, the pilot should keep the direction of motion of the aircraft parallel to the runway. longitudinal axis of the aircraft parallel to the direction of its motion. downwind wing lowered sufficiently to eliminate the tendency for the aircraft to drift.

Answer (B) is correct. (FAA-H-8083-3B Chap 8) ( ? ) At touchdown when landing, the longitudinal axis of the airplane should be parallel to the direction of its motion, i.e., no side loads to stress the landing gear.

Fig 20 En route to First Flight Airport (area 5), your flight passes over Hampton Roads Airport (area 2) at 1456 and then over Chesapeake Regional at 1501. At what time should your flight arrive at First Flight? 1516. 1521. 1526.

Answer (C) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The distance between Hampton Roads Airport (north of 2) and Chesapeake Regional (northeast of 2) is 10 NM. It took 5 min. (1501 - 1456) to go 10 NM. On your flight computer, place the 5 min. the first leg took on the inner scale under 10 NM on the outer scale. Then find 50 NM (60 NM total distance - 10 NM of the first leg) on the outer scale and read 25 min. on the inner scale for the time from Chesapeake Regional to First Flight Airport. The distance from Chesapeake Regional to First Flight Airport (right of 5) is 50 NM. Add 25 min. to the time you passed Chesapeake Regional (1501) to get 1526.

Fig 23 What is the estimated time en route for a flight from Allendale County Airport (area 1) to Claxton-Evans County Airport (area 2)? The wind is from 100° at 18 knots and the true airspeed is 115 knots. Add 2 minutes for climb-out. 33 minutes. 27 minutes. 30 minutes.

Answer (C) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. To find the en route time from Allendale County (north of 1) to Claxton-Evans (southeast of 2), use Fig. 23. 2. Using the sectional scale located at the top of the chart, measure the distance to be 55 NM. 3. TC = 212°. 4. Mark up 18 knots with 100° under true index. 5. Put TC of 212° under true index. 6. Slide the grid so the pencil mark is on TAS of 115 knots. 7. Read the groundspeed of 120 knots under the grommet. 8. On the calculator side, place 120 knots on the outer scale over 60 minutes. 9. Read 28 minutes on the inner scale below 55 NM on the outer scale. 10. Add 2 minutes for climb-out and the en route time is 30 minutes.

Fig 22 Determine the estimated time en route for a flight from Priest River Airport (area 1) to Shoshone County Airport (area 3). The wind is from 030 at 12 knots and the true airspeed is 95 knots. Add 2 minutes for climb-out. 29 minutes. 27 minutes. 31 minutes.

Answer (C) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. To find the en route time from Priest River Airport (west of area 1) to Shoshone County Airport (area 3) use Fig. 22. 2. Using the scale at the top of the chart, measure the distance to be 48 NM. 3. TC = 143°. 4. Mark up 12 knots with 030° under true index. 5. Put TC of 143° under true index. 6. Slide the grid so the pencil mark is on TAS of 95 knots. 7. Read the groundspeed of 99 knots under the grommet. 8. On the calculator side, place 99 knots on the outer scale over 60 minutes. 9. Read 29 minutes on the inner scale below 48 NM on the outer scale. 10. Add 2 minutes for climb-out and the en route time is 31 minutes.

Fig 22 What is the estimated time en route from Sandpoint Airport (area 1) to St. Maries Airport (area 4)? The wind is from 215° at 25 knots, and the true airspeed is 125 knots. 38 minutes. 30 minutes. 34 minutes.

Answer (C) is correct. (FAA-H-8083-25B Chap 16) ( ? ) The requirement is time en route and not magnetic heading, so there is no need to convert TC to MC. 1. You are to find the en route time from Sandpoint Airport (north of 1) to St. Maries Airport (southeast of 4) on Fig. 22. 2. Using the scale at the top of the chart, measure the distance to be 59 NM. 3. TC = 181°. 4. Mark up 25 knots with 215° under true index. 5. Put TC of 181° under true index. 6. Slide the grid so the pencil mark is on TAS of 125 knots. 7. Read the groundspeed of 104 knots under the grommet. 8. On the calculator side, place 104 knots on the outer scale over 60 minutes. 9. Find 59 NM on the outer scale and read 34 minutes on the inner scale.

How far will an aircraft travel in 2-1/2 minutes with a groundspeed of 98 knots? 2.45 NM. 3.35 NM. 4.08 NM.

Answer (C) is correct. (FAA-H-8083-25B Chap 16) ( ? ) To determine the distance traveled in 2-1/2 minutes at 98 knots, note that 98 knots is 1.6 NM/minute (98 ÷ 60 = 1.633). Thus, in 2-1/2 minutes, you will have traveled a total of 4.08 NM (1.633 × 2.5 = 4.08). Alternatively, put 98 on the outer scale of your flight computer over the index on the inner scale. Find 2.5 minutes on the inner scale, above which is 4.1 NM.

Select the four flight fundamentals involved in maneuvering an aircraft. Aircraft power, pitch, bank, and trim. Starting, taxiing, takeoff, and landing. Straight-and-level flight, turns, climbs, and descents.

Answer (C) is correct. (FAA-H-8083-3B Chap 3) ( ? ) Maneuvering an airplane is generally divided into four flight fundamentals: straight-and-level flight, turns, climbs, and descents. All controlled flight consists of one or a combination of more than one of these basic maneuvers.

An aircraft departs an airport in the central standard time zone at 0930 CST for a 2-hour flight to an airport located in the mountain standard time zone. The landing should be at what time? 0930 MST. 1030 MST. 1130 MST.

B

An aircraft departs an airport in the Pacific standard time zone at 1030 PST for a 4-hour flight to an airport located in the central standard time zone. The landing should be at what coordinated universal time? 2030Z. 2130Z. 2230Z.

C

An aircraft departs an airport in the central standard time zone at 0845 CST for a 2-hour flight to an airport located in the mountain standard time zone. The landing should be at what coordinated universal time? 1345Z. 1445Z. 1645Z.

C

An aircraft departs an airport in the eastern daylight time zone at 0945 EDT for a 2-hour flight to an airport located in the central daylight time zone. The landing should be at what coordinated universal time? 1345Z. 1445Z. 1545Z.

C