Equations of Hyperbolas (continued) Assignment

The graph of a hyperbola is represented by the equation (x+6)^2/9 - (y-4)^2/4 = 1. What are the vertices of the hyperbola?

(-9, 4) and (-3, 4)

One focus of a hyperbola is located at (-7, 1). One vertex of the hyperbola is located at (-6, 1). The center is (-2, 1). What is the equation of the hyperbola? = 1

(x+2)^2/16 - (y-1)^2/9 = 1

A hyperbola has its foci at (1, 7) and (1, -13). A directrix of the hyperbola is y = 64/10. What is the equation of the hyperbola?

(y+3)^2/8^2 - (x-1)^2/6^2 = 1

Which equation represents the graph?

(y-1)^2/49 - x^2/81 = 1

The vertices of a hyperbola are located at (0, -4) and (0, 12). The foci of the same hyperbola are located at (0,-6) and (0, 14). What is the equation of the hyperbola?

(y-4)^2/64 - x^2/36 = 1

A hyperbola is represented using the equation (x-1)^2/4 - (y+2)^2/16 = 1. What are the slopes of the asymptotes? m = ± Use the center (1, -2), the positive slope, and the equation y = mx + b to determine the b value for the equation of the asymptote with the positive slope. b =

2 -4

Which statements about the hyperbola are accurate? Check all that apply.

There is a focus at (-9, 1). There is a directrix at x = -5.8. There is a directrix at x = -2.2.

Which statements about the hyperbola are true? Check all that apply.

There is a vertex at (-3, 6). The center of the hyperbola is at (-3, 5). The transverse axis is vertical. The directrices are horizontal lines.