Linear Algebra Test 2 Review T/F

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A matrix A is diagonalizable if A has n eigenvectors

False

If Ax=lambdax for some scalar lambda, then x is an eigenvector of A

False

If Ax=λx for some vector x, then λ is an eigenvalue of A.

False

The eigenvalues of a matrix are on its main diagonal

False

The determinant of A is the product of the pivots in any echelon form U of​ A, multiplied by ​(minus−​1)r​, where r is the number of row interchanges made during row reduction from A to U

False. Reduction to an echelon form may also include scaling a row by a nonzero​ constant, which can change the value of the determinant. Your answer is correct

The determinant of A is the product of the diagonal entries in A

False. This is only true if A is trangular

If A is​ invertible, then the columns of A−1 are linearly independent. Explain why.

It is a known theorem that if A is invertible then A−1 must also be invertible. According to the Invertible Matrix​ Theorem, if a matrix is invertible its columns form a linearly independent set.​ Therefore, the columns of A−1 are linearly independent.

If C is 6×6 and the equation Cx=v is consistent for every v in set of real numbers ℝ6​, is it possible that for some v​, the equation Cx=v has more than one​ solution? Why or why​ not?

It is not possible. Since Cx=v is consistent for every v in set of real numbers ℝ6​, according to the Invertible Matrix Theorem that makes the 6×6 matrix invertible. Since it is​ invertible, Cx=v has a unique solution.

A row replacement operation does not affect the determinant of a matrix

True. If a multiple of one row of a matrix A is added to another to produce a matrix​ B, then det B equals det A

If the columns of A are linearly​ dependent, then det A=0

True. If the columns of A are linearly​ dependent, then A is not invertible

Explain how the columns or rows of A change when A is multiplied by D on the right or on the left. Choose the correct answer below.

​Right-multiplication (that​ is, multiplication on the​ right) by the diagonal matrix D multiplies each column of A by the corresponding diagonal entry of D.​ Left-multiplication by D multiplies each row of A by the corresponding diagonal entry of D.

If A can be row reduced to the identity​ matrix, then A must be invertible.

​True; since A can be row reduced to the identity​ matrix, A is row equivalent to the identity matrix. Since every matrix that is row equivalent to the identity is​ invertible, A is invertible

A product of invertible n×n matrices is​ invertible, and the inverse of the product is the product of their inverses in the same order.

False; if A and B are invertible matrices then (AB)^-1 = B^-1 A^-1

If A is​ invertible, then elementary row operations that reduce A to the identity In also reduce A−1 to In

False; if A is invertible, then the row operations required to reduce A to the identity correspond to some product of elementary matrices. Then the row operations required to reduce A^-1 to the identity would correspond to the product

A number c is an eigenvalue of A if and only if the equation ​(A−​cI)x=0 has a nontrivial solution

True

Find a 3×3 matrix​ B, not the identity matrix or zero​ matrix, such that ABequals=BA. Choose the correct answer below.

There are infinitely many solutions. Any multiple of I3 will satisfy the expression.

A subset H of set of real numbers ℝn is a subspace if the zero vector is in H.

This statement is false. For each u and v in H and each scalar​ c, the sum u+v and the vector cu must also be in H

Determine whether the statement​ "The multiplicity of a root r of the characteristic equation of A is called the algebraic multiplicity of r as an eigenvalue of​ A" is true or false

True

Finding an eigenvector of A may be​ difficult, but checking whether a given vector u is in fact an eigenvector is easy

True

If AP=​PD, with D​ diagonal, then the nonzero columns of P must be eigenvectors of A

True

If A=[a b/ c d] and ad=bc, then A is not invertible

True; if ad=bc then ad-bc=0 and 1/(ad-bc) [d -b/-c a] is undefined

If A is​ invertible, then the inverse of A^-1 is A itself.

True; since A^-1 is the inverse of A, A^-1A=I=AA^-1. Since A^-1A=I=AA^-1, A is the inverse of A^-1

If ℝn has a basis of eigenvectors of​ A, then A is diagonalizable

True

How many rows does B have if BC is a 9x8 ​matrix?

9 rows

If a matrix A is 8x9 and the product AB is 8x4​, what is the size of​ B?

9x4

Solve the equation AB=BC for​ A, assuming that​ A, B, and C are square matrices and B is invertible.

A=BCB^-1

A is diagonalizable if A=PDP−1 for some matrix D and some invertible matrix P

False

A is diagonalizable if and only if A has n​ eigenvalues, counting multiplicities

False

Determine whether the statement ​"det A^T = (-1)detA" is true or false

False

Determine whether the statement "If A is 3x3 with columns a1,a2,a3 then detA equals the volume of the parallelepiped determined by a1,a2,a3 is T/F

False

Determine whether the statement​ "A row replacement operation on A does not change the​ eigenvalues" is true or false

False

If A is​ diagonalizable, then A has n distinct eigenvalues

False

If A is​ diagonalizable, then A is invertible

False

If A is​ invertible, then A is diagonalizable

False

If v1 and v2 are linearly independent​ eigenvectors, then they correspond to distinct eigenvalues

False

To find the eigenvalues of​ A, reduce A to echelon form

False. An echelon form of a matrix A usually does not display the eigenvalues of A

If three row interchanges are made in​ succession, then the new determinant equals the old determinant

False. If three row interchanges are made in​ succession, then the new determinant equals the negative of the old determinant

If det A is​ zero, then two rows or two columns are the​ same, or a row or a column is zero

False; If A = [ 2 6/ 1 3], then det A =0 and the rows and columns are all distinct and not full of zeros

det(A+​B)=det A+det B

False; If A= [1 0/ 0 1] and B= [-1 0/ 0 -1], then det(A+B)=0 and det A + det B=2

Det A^-1 = (-1)detA

False; det A ^-1 = (detA) ^-1

Is Nul A =R3

No, because the null space of a 5x8 matrix is a subspace of ℝ8. Although dim Nul A=3​, it is not strictly equal to ℝ3 because each vector in Nul A has eighteight components. Each vector in ℝ3 has threethree components.​ Therefore, Nul A is isomorphic to ℝ3​, but not equal.

If the given equation Gx=y has more than one solution for some y in set of real numbersℝn​, can the columns of G span set of real numbers ℝn​? Why or why​ not? Assume G is ns×n.

The columns of G cannot span set of real numbers ℝn. According to the Invertible Matrix​ Theorem, if Gx=y has more than one solution for some y in set of real numbers ℝn​, that makes the matrix G non invertible.

A subspace of set of real numbers ℝn is any set H such that​ (i) the zero vector is in​ H, (ii) Bold uu​, Bold vv​, and Bold uu+Bold vv are in​ H, and​ (iii) c is a scalar and cBold uu is in H.

The statement is false. Conditions​ (ii) and​ (iii) must be satisfied for each Bold uu and Bold vv in​ H, which is not specified in the given statement.

This statement is true. For an m×n matrix​ A, the solutions of Ax=0 are vectors in ℝn and satisfy the properties of a vector space

This statement is false. The column space of A is the set of all b for which Ax=b has a solution

B is an echelon form of a matrix​ A, then the pivot columns of B form a basis for Col A

This statement is false. The columns of an echelon form of a matrix are often not in the column space of the original matrix

Given vectors v1....vp in ℝn​, the set of all linear combinations of these vectors is a subspace of ℝn.

This statement is true. This set satisfies all properties of a subspace.

A matrix A is not invertible if and only if 0 is an eigenvalue of A

True

An eigenspace of A is a null space of a certain matrix

True

A​ steady-state vector for a stochastic matrix is actually an eigenvector

True

If A,B and C are nxn invertible matrices, does the equation C^-1(A+X)B^-1= In have a solution X

X=CB-A

Is Col A = R5

Yes, because the column space of a 5x8 matrix is a subspace of ℝ5. There is a pivot in each​ row, so the column space is 5​-dimensional. Since any 5​-dimensional subspace of ℝ5 is ℝ5​, Col A=ℝ5


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