Quadratic in Form Polynomials

Rewrite the equation in terms of u

B u^2 + u - 2 + 0

Factor

(U-16)(U-1) = 0

Factor the equation.

(u + 2)(u - 1) = 0

Solve x^4 - 17x^2 + 16 = 0. Let u =

x^2

What are the solutions of the original equation?

x = -5 or x = -2

Select all of the zeros of the function

±3/2, ±3/2i

Solve the equation 6(2x + 4)2 = (2x + 4) + 2.

A

Which equation is equivalent to f(x) = 16x^4 - 81 = 0?

B, (4x^2 + 9)(4x^2 - 9) = 0

Select the solutions

x = 4, -4, 1, -1

Is the equation x^9 - 5x^3 + 6 = 0 quadratic in form? Explain why or why not.

The equation is not quadratic in form. The variable part of the first term is not the square of the variable part of the second term. The result of squaring x cubed is x to the 6th power, not the 9th power. x^9 (x3)^2

Rewrite the equation in terms of u.

U^2 - 17U + 16 = 0

Use substitution to write an equivalent quadratic equation.(3x + 2)^2 + 7(3x + 2) - 8 = 0

B, U^2 + 7U - 8 = 0, where U=3x + 2

Solve (x + 3)^2 + (x + 3) - 2 = 0. Let u =

x + 3

Solve (x + 4)^2 - 3(x + 4) - 3 = 0 using substitution.

x + 4 Solutions are B and D

What are the solutions of 4x^4 - 4x^2 = 8?

A and C