section 5 part 8 and 9 math

A lot measures 105' square. Zoning requires a front setback of 30', rear setback of 25', and side setbacks of 15'. What is the maximum square footage, of a single story structure, that could be built on this property? Draw a picture.

105 - 55 (total of front & rear setbacks) = 50 deep. 105 - 30 (total of side setbacks) = 75 wide. 50 x 75 (maximum structure) = 3,750 sq. feet. The correct answer is: 3,750

A lot measures 100 feet wide at the street and 150 feet deep from the street to the back property line. Local zoning standards call for a 30' front setback, 15' side setbacks and a 20' back setback. The footprint of any house built on this lot could occupy a maximum of how many square feet?

Width: 100 ft. - 30 ft. = 70 ft wide (You must subtract 15 feet on each side of the property). Depth: 150 - 30 ft. front setback - 20 ft. back yard setback = 100 ft. 100 ft wide X 100 ft deep = 7,000 square feet for the house. The correct answer is: 7000.

A rectangular lot with 1,250' of frontage contains 40 acres. The adjacent lot has a front footage of 2,000'. If both lots are the same depths, how many acres are in the second lot?

Lot 1: 40 X 43,560 = 1,742,400 square feet. 1,742,400 / 1250 (1st frontage) = 1,393.92 (depth of both lots). Lot 2: 2,000 (front) X 1,393.92 (depth) = 2,787,840 square feet. 2,787,840 / 43,560 = 64 acres. The correct answer is: 64

The plans for a house indicate a scale of 1/4" = 1 foot. If the living room is shown as 8 1/2" by 6 3/4", what is the cost to carpet the room if carpet is $2.70 per square yard?

On a ruler there would be 4' to each inch. 8.5" x 4 = 34 feet. 6.75" x 4 = 27 feet. 34' x 27' = 918 square feet. 918 / 9 sq. ft. per y= 102 square yards. 102 x $2.70 = 275.4 = $275.40. The correct answer is: $275.40

What is the number of square feet in a lot (trapezoid) that measures 95' along the front, 105' along the back, and 145' from front to back?

Set up problem. B1 + B2 / 2 X H = Area. 95 + 105 / 2 = 100. 100 X 145 = 14,500 square feet. The correct answer is: 14,500

A rectangular parcel of land is 990 feet long and contains 12.5 acres. What is the width of this parcel?

12.5 acres X 43,560 = 550,400 square feet. 550,400 square feet divided by 990 feet = 550 feet wide. The correct answer is: 550 feet.

What is the area of a lot that measures 120' by 164'?

Area = Length X Width. Area = 164' X 120' = 19,680 sq. ft. Read your calculator carefully. The correct answer is: 19,680 sq. ft.

If one rectangular lot with 1350' of frontage contains 25 acres, how many acres would the lot next to it contain if it has a 900' frontage and is the same width as the first lot?

Area = Length X Width. Lot 1: 43,560 (sq. ft. in acre) X 25 acres = 1,089,000 sq. ft. We know that 1,089,000 sq. ft. = Width X 1,350' (length). Therefore 1,089,000 / 1,350 = Width or 806.67. The problem told us that the lots were the same width. Lot 2: Area = 806.67' (width) x 900' (length) = 726,000 sq. ft. Therefore: 726,000 (area) / 43,560 = 16.67 acres. The correct answer is: 16.67 acres