Stats : Exam #1

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bar chart

-a chart with bars whose lengths are proportional to quantities -A bar chart compares different categories by using individual bars to represent the tallies for each category. The length of a bar represents the​amount, frequency, or percentage of values falling into a category. -categorical data

1. The percentage of the adult population that was married in 1990 was 2. The percentage of the adult population that was married in 1997 was 3.The percentage of the adult population that was married in 2000 was 4.The percentage of the adult population that was married in 2007 was

1 - 59.8 2- 57.9 3- 56.4 4- 53.2 Year: Married Total 1990 113.3 189.5 1997 117.8 203.5 2000 120.5 213.7 2007 124.1 233.3

Match each description with the correct histogram of the data. 1. The age of death of a sample of 19 typical women in the U.S. 2. The yearly tuition for 142​ colleges, 85 of which are private and 57 of which are​ state-supported. 3. The outcomes of rolling a fair die​ (with six​ sides) 5000 times.

1- B 2-C 3-A

Name two measures of the variation of a​ distribution, and state the conditions under which each measure is preferred for measuring the variability of a single data set.

1. The interquartile range is preferred when the data is strongly skewed or has outliers. 2.The standard deviation is preferred when the data is relatively symmetric.

1. What percentage of women are right handed? 2.What percentage of right handed students are females? 3. What percentage of students are right handed? 4.If the percentage of​ right-handed females remained roughly the same and there were 75 females, how many of them would be​ right-handed? Total right handed : 7 Total left handed: 4 Total male :2 Total female : 9 Total male and female : 11

1.To find the​ proportion, divide the number of females who are​ right-handed by the total number of females in the class. = 66.7% 2. To find the​ proportion, divide the number of females who are​ right-handed by the total number of​ right-handed students in the class.( multiply by 100% to get percent) = 85.7 % 3. To find the​ proportion, divide the number of students who are​ right-handed by the total number of students in the class. = 63.6 % 4. Multiply 75 by the proportion 0.667. = 50

Indicate whether the study is an observational study or a controlled experiment: A group of boys is randomly divided into two groups. One group watches violent cartoons for one​ hour, and the other group watches cartoons without violence for one hour. The boys are then observed to see how many violent actions they take in the next two​ hours, and the two groups are compared.

A controlled experiment

Left skewed

A density curve where the left side of the distribution extends in a long tail. (Mean < median.)

Data are more than just​ numbers, because data have​ _____.

Context

unstacked data

Data stored such that each column represents a variable from a different group. Can only store two variables.

Stacked data

Data values stored in a spreadsheet format. Each row contains data for a single individual. Can store many variables.

Stem Plot

For the number​ 65.4, the 65 is the stem and the 4 is the leaf. For the number​ 60, the 6 is the stem and the 0 is the leaf.

According to the ancient Roman architect​ Vitruvius, a​ person's armspan​ (the distance from fingertip to fingertip with the arms stretched​ wide) is approximately equal to his or her height. For​ example, people 5 feet tall tend to have an armspan of 5 feet.​ Explain, then, why the distribution of armspans for a class containing roughly equal numbers of men and women might be bimodal.

Men and women tend to have different heights and therefore different armspans.

If you moved to one of these regions and met 50​ people, in which region would you be most likely to meet at least one person living with​ AIDS?

Most likely to meet one person with aids living in region : F

Indicate whether the study is an observational study or a controlled experiment. A researcher was interested in the effects of exercise on academic performance in elementary school children. She went to the recess area of an elementary school and identified some students who were exercising vigorously and some who were not. The researcher then compared the grades of the exercisers with the grades of those who did not exercise.

Observational study

In your own​ words, describe to someone who knows only a little statistics how to recognize when an observation is an outlier. What​ action(s) should be taken with an​ outlier?

Outliers are observed values far from the main group of data. In a histogram they are separated from the others by space. Outliers must be looked at in closer context to know how to treat them. If they are​ mistakes, they might be removed or corrected. If they are not​ mistakes, you might do the analysis​ twice, once with and once without the outliers.

Which measure of the center​ (mean or​ median) is more resistant to​ outliers, and what does​ "resistant to​ outliers" mean?

The median is more​ resistant, which indicates that it usually changes less than the mean when comparing data with and without outliers.

Indicate whether the following study is an observational study or a controlled experiment. A researcher was interested in the effect of exercise on memory. She randomly assigned half of a group of students to run up a stairway three times and the other half to rest for an equivalent amount of time. Each student was then asked to memorize a series of random digits. She compared the numbers of digits remembered for the two groups.

This is a controlled experiment. The researcher separates the students into at least two random​ groups, one of which is the control group. This is essential to conducting a controlled experiment.

Histogram

a bar graph depicting a frequency distribution good for numerical values

pie chart

a chart that shows the relationship of a part to a whole -categorical data

Right Skewed

a distribution with a tail that extends to the right (Mean > median)

Why is this pie chart hard to​ interpret?

here are so many possible numerical values causing the pie chart to have too many​ "slices", which makes it difficult to tell which is which.

It was predicted that a country will have an elderly population​ (65 and older) of 8,840,000 in the year 2050 and that this will be 23.3% of the population. What is the total predicted population of this country in 2050?

1. To find the total number of people in the​ country, first convert the percentage of elderly into its decimal equivalent. (23.3%/100%) = 0.233 2.The problem states that 23.323.3​% of the unknown total population​ (call it​ x) is equal to 8,840,000. Set up an equation as described and solve for x. 0.233x= 8,840,000. (Divide both sides by 0.233) 8,840,000 X= 0.233 Predicted pop in 2050 = 37,940,000

Two sections of statistics are​ offered, the first at 8 a.m. and the second at 10 a.m. The 8 a.m. section has 25​ women, and the 10 a.m. section has 15 women. A student claims this is evidence that women prefer earlier statistics classes than men do. What information is missing that might contradict this​ claim?

The percentage of female students in the two classes is unknown. There may be more females in the 8 a.m. because there are more students in the 8 a.m. class than the 10 a.m. class. This claim could be true only if the classes were the same size.

In a recent​ competition, do you think the standard deviation of the running times for all men who ran the​ 100-meter race would be larger or smaller than the standard deviation of the running times for the​ men's marathon? Explain.

The standard deviation for the​ 100-meter event would be less. All the runners come to the finish line within a few seconds of each other. In the​ marathon, the runners can be quite widely spread after running that long distance.

A study concludes that the use of pesticides is associated with the development of​ Parkinson's disease, a neurological disease that causes people to shake. The study reported that exposure to bug killers and weed killers is​"associated with" an increase of​ 33% to​ 80% in the chances of getting​ Parkinson's. Does this study show that pesticides cause​ Parkinson's disease? Why or why​ not?

The study does not show that pesticides cause​ Parkinson's disease. This was an observational study because researchers could not have deliberately exposed people to pesticides. Observational studies cannot conclude causation.

A study compared the rate of pneumonia before and after a vaccine was introduced. In the​ study, annual hospitalization rates were estimated from any cause using a database. Average annual rates of​ pneumonia-related hospitalizations before and after introduction of the vaccine were used to estimate annual declines in​ pneumonia-related hospitalizations. The annual rate of​ pneumonia-related hospitalizations among children of various age groups significantly declined relative to expected rates before introduction of the vaccine. Does this show that pneumonia vaccine caused the decrease in pneumonia that​ occurred? Explain.

The study does not show that the vaccine caused the decrease in pneumonia. This is an observational study because the children were not randomly assigned by the researchers. It is possible that confounding variables​ (other advances in​ medicine, for​ instance) would affect the rates of pneumonia.

The histogram shows the ages of 25 CEOs listed on a certain website. Based on the​ distribution, what is the approximate mean age of the CEOs in this data​set? Write a sentence in context​ (using words in the​question) interpreting the estimated mean.

The typical CEO is between 56 and 60.

Is the variable Eye ColorEye Color numerical or​ categorical? Explain.

The variable is categoricalcategorical because the values are categoriescategories.

A study was conducted to see whether participants would ignore a sign that​ said, "Elevator may stick between floors. Use the​ stairs." Those who used the stairs were said to be​ compliant, and those who used the elevator were said to be noncompliant. There were three possible​ situations, two of which involved confederates. A confederate is a person who is secretly working with the experimenter. In the first​ situation, there was no confederate. In the second​ situation, there was a compliant confederate​ (one who used the​ stairs), and in the third​ situation, there was a noncompliant confederate​ (one who used the​ elevator). The subjects tended to imitate the confederates. What more do you need to know about the study to determine whether the presence or absence of a confederate causes a change in the compliance of​ subjects?

-Identify whether there was random assignment to groups. Without random assignment there is the possibility of​ bias, so we cannot infer causation. Your answer is correct. -Identify the sample size of the study. Without enough participants to observe the full range of variability in subjects we cannot control for other relevant​ factors, so we cannot infer causation.

Typical value found on a histogram

A typical value can be found by finding the center of the distribution the typical number of sleep hours for these men is 7.0-7.5

A :A statistics class is made up of 171 men and 222 women. What percentage of the class is​ male?. B: A different class has 278 ​students, and 62.2​% of them are men. How many men are in the​ class? C: A different class is made up of 54​% women and has 272 women in it. What is the total number of students in the​ class?

A 1. To find the percentage of the class that is​ male, first find the total number of students in the class. 2.Next find the proportion of men in the statistics class by dividing the number of men in the class by the total number of students in the class. 3.To convert the decimal proportion found in the previous step to a​ percentage, multiply the number by​ 100%. Ex: 0.436X100% = 43.6 B. 1. To find the number of men in the​ class, first convert the percentage 62.262.2​% to its decimal equivalent. Ex: 62.2% / 100% = 0.622 B. 2. Now multiply the proportion by the total number of people in the class to find the number of men in the class. there are 173 men in the 278 C. 1. To find the total number of people in the​ class, first convert the percentage of women into its decimal equivalent. ( 60%/100%)= 0.54 C. 2 : The question can be interpreted as 60​% of some unknown number​ (call it​ x) is equal to 27. Set up an equation as described and solve for x. 0.54x = 27 X= 27/0.54. (divide both sides by 0.54) = 50

Pareto graph

A bar graph where the bars are arranged in descending order. - good for categorical

Stemplot

A graphical representation of a quantitative data set. Leading values of each data point are presented as stems and second digits are given as leaves.

The mean birth weight for children born in a certain country at full term​ (after 40​ weeks) is 3470 grams​ (about 7.7 pounds). Suppose the standard deviation is 600 grams and the shape of the distribution is symmetric and unimodal. Complete parts a and b below. A.Find the range of birth weights​ (in grams) of children born from one standard deviation below the mean to one standard deviation above the mean.

A. To find the top​ value, add one standard deviation to the​ mean, (bar over X) + s =3470+600 = 4070 To find the bottom​ value, subtract one standard deviation from the​ mean, (bar over X) - s = 3470-600 = 2870

A study looked at the effects of light on female mice. Fifty mice were randomly assigned to a regimen of 12 hours of light and 12 hours of dark​ (LD), while another fifty mice were assigned to 24 hours of light​ (LL). Researchers observed the mice for two years. Three of the LD mice and 10 of the LL mice developed tumors. The accompanying table summarizes the data. Complete parts a through c. A. Determine the percentage of mice that developed tumors from each group​ (LL and​ LD). Compare them and comment. B.Was this a controlled experiment or an observational​ study? How do you​ know? C. Can we conclude that light for 24 hours a day causes an increase in tumors in​ mice? Why or why​ not?

A. In the LD​ mice, 6​% developed tumors. In the LL​ mice, 20​% developed tumors. The LD mice developed tumors at a lower rate than the LL mice. B. This was a controlled experiment because there were two groups that were randomly assigned by the researchers C. Because it was a controlled​ experiment, it can be concluded that light for 24 hours a day causes an increase in tumors in mice.

Refer to the accompanying​ graph, which shows the time spent on a typical day talking on the cell phone for some men and women. Each person was asked to choose the one of four intervals that best fitted the amount of time they spent on the phone​ (for example,​ "0 to 4​ hours" or​ "12 or more​ hours"). Complete parts​ (a) through​ (d) below. B. Is the graph a bar chart or a​ histogram? Which would be the better choice for these​ data? C.If you had the actual number of hours for each​ person, rather than just an​ interval, what type of graph should you use to display the distribution of the actual numbers of​ hours?

A. One variable is GENDER which is CATEGORICAL variable since it describes QUALITIES. The other variable is TIME RANGE which is a CATEGORICAL variable since it describes QUALITIES B.The graph is a bar chart. It is the better choice since both variables are categorical. C. Two histograms should be used since the time would be a numerical value

A group of overweight people are asked to participate in a weight loss program. Participants are allowed to choose whether they want to go on a vegetarian diet or follow a traditional​ low-calorie diet that includes some meat. Half of the people choose the vegetarian​ diet, and half choose to be in the control group and continue to eat meat. Suppose that there is greater weight loss in the vegetarian group. Complete parts​ (a) and​ (b) below. A. Suggest a plausible confounding variable that would prevent us from concluding that the weight loss was due to the lack of meat in the diet. Explain why it is a confounding variable. B. Explain a better way to do the experiment that is likely to remove the influence of confounding variables.

A. People who are not prepared to change their diet very much​ (such as by excluding​ meat) might also not change other factors that affect​ weight, such as how much exercise they get. B. The experiment would be improved if some subjects were randomly assigned to eat meat and the remaining subjects to consume a vegetarian diet.

The data were collected from a statistics class. The column head gives the​ variable, and each of the rows represents a student in the class. Find the​ frequency, proportion, and percentage of women.

A. The frequency of women in the class is 6 B. The proportion of women in the class is 6/11 C. The percentage of women in the class is 54.5%

A. Interpret the mean. Choose the correct answer below. B. Interpret the standard deviation. Choose the correct answer below.

A. The mean is the typical or average number of vacation days B. The standard deviation measures how many vacation days more or less than the mean a country usually has

The idea of sending delinquents to​ "Scared Straight" programs has appeared recently in several media programs. In a 1983​ study, each male delinquent in the study​ (all aged​ 14-18) was randomly assigned to either Scared Straight or no treatment. The males who were assigned to Scared Straight went to a​ prison, where they heard prisoners talk about their bad experiences there. Then the males in both the experimental and the control group were observed for 12 months to see whether they were rearrested. Complete parts​ (a) and​ (b) below. A.a. Report the rearrest rate for the Scared Straight group and for the No Treatment​ group, and state which is higher. B. This experiment was done in the hope of showing that Scared Straight would cause a lower arrest rate. Did the study show​ that? Explain.

A. The rearrest rate for the Scared Straight group is 81.1%. the rearrest rate for the No Treatment group is 67.3%. The rearrest rate for the Scared Straight group is higher than the rearrest rate of the No Treatment group. B.No. The study does not show that Scared Straight causes a lower arrest​ rate, because the rearrest rate in the Scared Straight group was higher than in the No Treatment group.

A doctor reported on a study that treated children who had sleep​ apnea, which interferes with breathing while a child is asleep. In the​ study, 464​ children, 5 to 9 years of​ age, were randomly assigned to either surgery or to be under constant watch for a certain period of time. The study found that there were significantly greater improvements in​ behavioral, quality-of-life, and sleep study findings in the group that had surgery than the group assigned to constant watch. Complete parts​ (a) and​ (b) below. A. Was the study a controlled experiment or an observational​ study? Explain how you know. B. Assuming that the study was properly​ conducted, can we conclude that the early surgery caused the​ improvements? Explain.

A. The study was a controlled experiment because the children were randomly assigned to either surgery or constant watch. This is essential to conducting a controlled experiment. B. We can conclude that the early surgery caused the improvements because it was a randomized controlled experiment.

The accompanying histograms show the circumferences of heads for a group of men and a group of women. Complete parts​ (a) through​ (e) below A.If you were describing the​ men's heads in terms of​ shape, center, and​ spread, without comparing them to the​ women's heads, would you use the mean and standard deviation or the median and interquartile​ range? Why? B.If you were describing the​ women's heads in terms of​ shape, center, and​ spread, without comparing them to the​ men's heads, would you use the mean and standard deviation or the median and interquartile​ range? Why? C.If you were comparing the two​ groups, what measures would you​ use, and​ why? D. In which of the two graphs would the mean and median be close​ together, and​ why? E.In which of the two graphs would the mean and median be farther​ apart, and which would be​ larger?

A. Without comparing the​ men's data set to the​ women's data​ set, the MEAN AND STANDARD DEVIATION are preferred measures of​ shape, center, and spread for the​ men's data set because the distribution is ROUGHLY SYMMETRIC B.Without comparing the​ women's data set to the​ men's data​ set, the MEDIAN AND INTERQUARTILE RANGE are preferred measures of​ shape, center, and spread for the​ women's data set because the distribution is ASYMMETRIC DUE TO OUTLIERS C. The MEDIAN AND INTERQUARTILE RANGE are preferred measures of​ shape, center, and spread for comparing the two groups. The distribution of THE WOMENS set of data is ASYMMETRIC DUE TO OUTLIERS meaning that the MEDIAN AND INTERQUARTILE RANGE are appropriate measures for comparison D.The mean and median would be closer together in the MENS data set than the WOMENS data​ set, because the distribution of the data is ROUGHLY SYMMETRIC E.The mean and median would be farther apart in the WOMENS data set than the MENS because the distribution of the data is ASYMMETRICAL DUE TO OUTLIERS the mean would be LARGER than the median because the larger outliers INCREASES the value of the MEAN

The accompanying relative frequency histogram shows the number of hours of sleep​ (Sleep Hours) reported as experienced​ "last night" for 2626 college men. Complete parts​ (a) and​ (b) below. A. About how many men had 6 or fewer hours of​ sleep? B. The graph is bimodal. What are the two​ modes?

A. about 5 men had 6 or fewer hours of sleep B. 7.0, 8.0 calculate the total proportion of men who got 6 or less hours of sleep by adding the proportion of men who got 5.5 hours of sleep to the proportion of men who got 6.0 hours of sleep. (0.04+0.15=0.19) Multiply the total proportion by the total number of men to determine the number of men who got 6 hours of sleep or less. (0.19X26)

Because this was an observational​ study, it only shows an​ association; it does not show that the tutoring worked. It could be that more motivated students attended the tutoring and that was what caused the higher grades. A. The doctor is concerned that if his most severely depressed patients do not receive the​ antidepressants, they will get much worse. He therefore decides that the most severe patients will be assigned to receive the antidepressants. Explain why this will affect his ability to determine which approach works best. B.What advice would you give the doctor to improve his​ study? C. The doctor asks you whether it is acceptable for him to know which treatment each patient receives and to evaluate them himself at the end of the study to rate their improvement. Explain why this practice will affect his ability to determine which approach works best. D.What improvements to the plan in part​ (c) would you​ recommend?

A. if the doctor decides on the​ treatment, this could introduce bias. B. The doctor should randomly assign the patients to the different treatments. C.If the doctor is aware of the treatment each patient​ receives, that might influence his opinion about the effectiveness of the treatment. D. To prevent​ bias, the experiment should be​ double-blind. Neither the patients nor the doctor evaluating the patients should know whether each patient received medication

Name two measures of the center of a​ distribution, and state the conditions under which each is preferred for describing the typical value of a single data set. A. What are two measures of the center of a​ distribution? B.Under what conditions is the median​ preferred? C.Under what conditions is the mean​ preferred

A.median and mean B.The median is preferred when the data is strongly skewed or has outliers. C.The mean is preferred when the data is relatively symmetric.

Mounds of distribution

A​ one-mound distribution is called​ unimodal, a​ two-mound distribution is called a bimodal​ distribution, and a distribution that has more than two modes is referred to as multimodal. Notice that the modes do not have to be the same height.

Two drugs were tested to see whether they helped women with breast cancer. Of 1060​ women, about half were randomly assigned to drug A and the other half were assigned to drug B. After 77​ months, 473 out of​ 539, and 426 out of 521 women assigned to drugs A and​ B, respectively, were alive. Complete parts​ (a) and​ (b) below. A. The survival rate for drug A is 87.8%, the survival rate for drug B would be 81.8%. The survival rate for drug A is HIGHER than drug B B. Was this a controlled experiment or an observational​ study? Explain why. From studies like​ these, can we conclude a​ cause-and-effect relationship between the drug type and the survival​ percentage? Why or why​ not?

B: This is a controlled experiment because the researchers randomly determined the groups. We can conclude a​ cause-and-effect relationship because the women were randomly assigned to the treatment and control​groups, which controls for other variables

A group of educators want to determine how effective tutoring is in raising​ students' grades in a math​ class, so they arrange free tutoring for those who want it. Then they compare final exam grades for the group that took advantage of the tutoring and the group that did not. Suppose the group participating in the tutoring tended to receive higher grades on the exam. Does that show that the tutoring​ worked? If​ not, explain why not and suggest a confounding variable.

Because this was an observational​ study, it only shows an​ association; it does not show that the tutoring worked. It could be that more motivated students attended the tutoring and that was what caused the higher grades.

When you are comparing two sets of​ data, and one set is strongly skewed and the other is​ symmetric, which measures of the center and variation should you choose for the​ comparison?

The medians and interquartile ranges

The histogram shows frequencies for the ages of 25 randomly selected CEOs. Convert this histogram to one showing relative frequencies by relabeling the vertical axis with the appropriate relative frequencies. Note that the new labels for the vertical axis are the only thing that will change.

D

The histograms contain data with a range of 1 to 6. Which group would have the larger standard​ deviation, group A or group​ B? Why?

Group A has a larger standard deviation. There are more observations far from the​ mean, which contribute to a larger standard deviation.

The​ five-number summary for a distribution of final exam scores is 35,75​,79​,90​,96. Explain why it is not possible to draw a boxplot based on this information.​ (Hint: What more do you need to​ know?)

It isn't possible to draw a box plot based on the five-number summary because the box plot must mark all potential outliers. Since the minimum is lower than the left limit, there may be other unknown outliers between the minimum and the left limit and so the box plot cannot mark all potential outliers

In​ 1994, major league baseball players went on strike. At the​ time, the average salary was​ $1,049,589, and the median salary was​ $337,500. If you were representing the​ owners, which summary would you use to convince the public that a strike was not​ needed? If you were a​ player, which would you​ use? Why was there such a large discrepancy between the mean and median​ salaries? Explain.

If you were representing the​ owners, you would use the AVERAGE salary to convince the public that a strike was not needed. If you were a​ player, you would use the MEDIAN to convince the public that a strike was needed. The average and median salaries differ so greatly because THE DISTRIBUTION OF SALARIES IS SKEWED RIGHT

Is this easier to determine with the pie chart or with the bar​ chart? Explain. Choose the correct answer below.

It is easier to use a bar chart because you can compare values using the heights of the​ bars, whereas it can be hard to determine which of two slices in a pie chart is larger when they are close in size and not adjacent to each other.

If you moved to one of these regions and met 50​ people, in which region would you be least likely to meet at least one person living with​ AIDS?

Least likely in region D

In​ 2011, the mean rate of violent crime​ (per 100,000​ people) for 24 particular states was 431 The standard deviation was 172. Assume that the distribution of violent crime rates is unimodal and symmetric. Complete parts​ (a) through​ (d) below. A. The percentage of data that should occur within 2 standard deviations of the mean would be = 95% (see figure B) Between which two values would you expect to find about​ 95% of the violent crime​ rates? (X-2s and X+2s) = 87,775 B.If one of these states had a violent crime rate of 438crimes per​ 100,000 people, would this be considered​unusual? Explain.

Recall that the Empirical Rule states that if a distribution of data is​ bell-shaped, then the following is true. Fig A. Approximately​ 68% of the observations fall within one standard deviation of the​ mean, that is, between, x(bar)-s and x(bar)+s ( denoted Xbar +/- S) Fig B. Approximately​ 95% of the observations fall within two standard deviations of the mean (X bar +/- 2s) Fig C. All or nearly all observations fall within three standard deviations of the mean (Xbar +/- 3s) B. Take the term​ "unusual" to be defined such that the data value in question lies more than two standard deviations from the mean. Use the Empirical Rule to find out within which range of standard deviations the given values lie.

standard deviation

Recall that the standard deviation is a measurement of how spread out the values within a data set are. how much scores vary around the mean score

A sociologist​ says, "Typically, men in a certain country still earn more than​ women." What does this statement​ mean?

The center of the distribution of salaries for men in the country is greater than the center for women.

Why is it best to compare medians and interquartile ranges for these​ data, rather than comparing means and standard​ deviations?

Some of these data have outliers​ and/or are​ skewed, and the median and interquartile range are resistant to outliers.

Suppose you have a data set with the weights of all members of a high school soccer team and all members of a high school academic decathlon team​ (a team of students selected because they often answer quiz questions​correctly). Which team do you think would have a larger standard deviation of​ weights? Explain.

The academic decathlon team would have a larger standard deviation of weights. Academics​ don't require a specific weight to​ succeed, so the distribution of weights should mirror that of the general population.

A dieter recorded the number of calories he consumed at lunch for one week. As you can​ see, a mistake was made on one entry. The calories are listed in increasing order below. 349, 371, 386 ,398, 412, 4190 When the error is corrected by removing the extra​ 0, will the mean​ change? Will the​ median? Explain without doing any calculation.

The corrected value will give a different mean but not a different median. Medians are resistant to outliers and not as affected by extreme​ values, but the more extreme a value​ is, the more the mean is affected by it

The distribution of​ in-state annual tuition for all colleges and universities in the United States is bimodal. What is one possible reason for this​ bimodality?

The distribution might be bimodal because private colleges and public colleges tend to differ in amount of tuition.

Predict the shape of the distribution of the numbers of times a group of 500 people eat breakfast in one week.

The distribution will be​ left-skewed. Most people will report eating breakfast every​ day, with a few reporting various values less than 7.

A teacher asks 90 students who drive how many speeding tickets they received in the last year. Predict the shape of the distribution and explain.

The distribution will be​ right-skewed. Most people will have no​ tickets, but there will be a few people with​ 1, 2,​ 3, or more tickets.

How could the graph be​ improved

The graph could be improved by making it a bar graph or a pie chart. This change would make the variable garage be seen as​ categories, not as numbers.

is the graph a histogram or a bar​ graph? How do you​ know?

The graph is a bar graph because the bars are separated

is the given graph a bar graph or a​ histogram?

The graph is a histogram because the bars touch.

The histogram shows the number of televisions in the homes of 90 community college students. Judging from the​ histogram, what is the approximate mean number of televisions in the homes in this​collection? Explain.

The mean number of televisions per home is between 3 and 4. The mean is near the​ center, which is due to the fact that the histogram is roughly symmetric.

A study was done to see whether a smaller dose of flu vaccine could be used successfully. In this​ study, the usual amount of vaccine was injected into half the​ patients, and the other half of the patients had only a small amount of vaccine injected. The response was measured by looking at the production of antibodies. In the​ end, the lower dose of vaccine was just as effective as a higher dose for those under 65 years old. What more do we need to know to be able to conclude that the lower dose of vaccine was equally effective at preventing the flu for those under​ 65?

The patients need to be randomly assigned the full or lower dose. Without randomization there could be​ bias, however, with randomization we can infer causation.

Are the ranks for the rates the same as the ranks for the number of​ cases? If​ not, describe at least one difference

The ranks for the rates are different from the ranks for the number of cases. Region F had the least number of cases but had the highest rate of cases.

The histogram shows frequencies for the ages of 25 randomly selected CEOs. Approximately what is a typical age of a CEO in this​ sample?

The typical age of a CEO in this sample is between 56 and 60 years old.

A real estate agent claims that all things being​ equal, houses with swimming pools tend to sell for less than those without swimming pools. What does this statement​ mean?

The typical price for homes with pools is smaller than the typical price for homes without pools.

Is the variable WeightWeight numerical or​ categorical? Explain.

The variable is numericalnumerical because the values are numbersnumbers.

Do these​ men, or do these​ women, have greater variation in brain​ size? Why?

The variation in brain sizes between men and women is less than​ 0.3, indicating no significant difference.

Indicate whether the following study is an observational study or a controlled experiment: A researcher is interested in the effect of music on memory. She randomly divides a group of students into three​ groups: those who will listen to quiet​ music, those who will listen to loud​ music, and those who will not listen to music. After the appropriate music is played​ (or not​ played), she gives all the students a memory test.

This is a controlled experiment. She assigns students to the control and treatment groups at random in order to control for all relevant factors aside from the effect of music on​ memory, which is essential to conducting a controlled experiment.

Indicate whether the following study is an observational study or a controlled experiment: Patients with​ Alzheimer's disease are randomly divided into two groups. One group is given a new​ drug, and the other is given a placebo. After six months they are given a memory test to see whether the new drug fights​Alzheimer's better than a placebo.

This is a controlled experiment. The researchers randomly assigned patients to either a treatment or control​ group, and they gave the patients a test afterwards to identify the effect of the new drug. This satisfies a key criterion of controlled experiments.

Indicate whether the following study is an observational study or a controlled experiment: Records of patients who have had broken ankles are examined to see whether those who had physical therapy achieved more ankle mobility than those who did not.

This is an observational study. Since the researchers did not randomly assign subjects to the control or treatment group​ beforehand, they did not satisfy a key feature of controlled experiments.

Indicate whether the following study is an observational study or a controlled experiment. A local public school​ encourages, but does not​ require, students to wear uniforms. The principal of the school compares the grade point averages of students at this school who wear uniforms with the GPAs of those who do not wear uniforms to determine whether those wearing uniforms tend to have higher GPAs.

This is an observational study. The principal does not randomly assign students to either wear or not wear uniforms. Random assignment is essential to conducting a controlled experiment.

A college magazine suggested that overeating reduces brain function. Is this likely to be a conclusion from observational studies or randomized​ experiments? Can we conclude that overeating causes a reduction in brain​function? Why or why​ not?

This is likely to be from observational studies. It would not be ethical to assign people to overeat. We cannot conclude causation from observational studies because of the possibility of confounding factors.

What percentage of men had an older sibling? ( chart that adds up)

To find the​ proportion, divide the number of men with an older sibling by the total number of men. Then convert the proportion to a percentage.

Some people believe that wearing copper bracelets is a good treatment for arthritis of the hand. To test this​ belief, suppose you recruit 100 people and supply them all with copper bracelets. After the patients wear the bracelets for a​ month, you ask them whether or not their pain is less than it was before they began wearing the bracelets. Explain how to improve this study.

To improve the​ study, the patients should be randomly divided into two​ groups; one group will be given the copper​ bracelets, and the other group will be given​ non-copper bracelets. After a​ month, the patients will be surveyed on the levels of their pain.

What​ type(s) of​ graph(s) would be more​ appropriate?

Two histograms or a pair of dot plots with a common horizontal axis would be more appropriate since the given data are numerical.

The circles shown to the right are​ similar, but not exactly the same. This is an example of​ _______.

Variation

The study of statistics rests on what two major​ concepts?

Variation And Data

A study reported on the effects of vitamin C in breast milk for​ breast-feeding mothers. The children whose mothers had chosen to take high doses of vitamin C had a​ 30% lower risk of developing allergies. Can you conclude that the use of vitamin C caused the reduction in​ allergies? Why or why​ not?

You cannot conclude that the use of vitamin C caused the reduction in allergies because the researchers did not randomly assign mothers to treatment and control groups. This step is necessary for identifying causation.

Dot Plot

a graphical display of data using dots - good for numerical data

Indicate whether the study is an observational study or a controlled experiment: A student watched picnickers with a large cooler of soft drinks to see whether teenagers were less likely than adults to choose diet soft drinks over regular soft drinks.

an observational study

The​ five-number summary for a distribution of final exam scores is 45​,72​,79​,90​,100. Is it possible to draw a boxplot based on this​ information? Why or why​ not?

it is possible to draw a boxplot based on this information. Both the minimum and maximum are within the bounds of the left limit and right​ limit, which means that all potential outliers can be displayed. This is necessary to construct the boxplot.

In​ 2008, a highway safety administration reported that the number of pedestrian fatalities in City A was 65 and that the number in City B was 45. Can we conclude that pedestrians are safer in City​ B? Why or why​ not?

​No, in order to compare the fatalities the statistics must include the number of fatalities per pedestrian. There may be fewer pedestrians in City B causing the difference.


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