Unit Three: Proofs Involving Triangles

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Given the following diagram, find the required measure. Given: m∠3 = m∠7 m∠2 = 60° m∠6 = 115° m∠4 = 10 20 25 30

10

Given the following diagram, find the required measure. Given: m∠3 = m∠7 m∠2 = 60° m∠6 = 115° m∠1 = 110 120 125 130

120

Given the following diagram, find the required measure. Given: l || m measure of angle 1 = 140° measure of angle 3 = 50° measure of angle 4 = 40 90 130 140

130

Given the following diagram, find the required measure. Given: l || m measure of angle 1 = 140° measure of angle 3 = 50° measure of angle 2 = 40 50 90 140

40

Given the following diagram, find the required measure. Given: l || m measure of angle 1 = 140° measure of angle 3 = 50° measure of angle 5 = 40 50 90 140

40

If m∠1 = 3x, m∠3 = 2x + 20 and m∠5 = 30, what is the value of x? 10 20 26 50

50

Given the following diagram, find the required measure. Given: m∠3 = m∠7 m∠2 = 60° m∠6 = 115° m∠3 = 5 45 55 65

55

Given the following diagram, find the missing measures. m∠O = m∠P m∠1 = 36° m∠O= 36 72 77.5 144

72

Given the following diagram, find the required measure. Given: l || m measure of angle 1 = 140° measure of angle 3 = 50° measure of angle 6 = 30 40 50 90

90

If one of the exterior angles of a triangle is acute, then the triangle must be: acute right obtuse equiangular

Obtuse

True/False - The two interior angles that are not adjacent to an exterior angle are remote interior angles.

True

What type of angles do the pairs of exterior angles of a triangle form? complementary supplementary vertical obtuse

Vertical

If the measure of angle 2 is twice the measure of angle O, then which of the following must be true? m∠P is greater than m∠O m∠P is less than m∠O m∠P = m∠O m∠2 = m∠O

measure of angle P = measure of angle O

Given the following diagram, find the required measure. Given: m∠3 = m∠7 All of the following are true except: m∠1 = m∠3 + m∠5 m∠5 = m∠4 + m∠7 m∠3 = m∠6 + m∠7 m∠1 = m∠5 + m∠7

m∠3 = m∠6 + m∠7

All of the following are equivalent except: 180 - m∠3 m∠2 + m∠6 180 - m∠7 m∠7 + m∠6

m∠7 + m∠6


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