Chapter 22 Conceptual Questions

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A disk with a radius of R is oriented with its normal unit vector at an angle θ with respect to a uniform electric field. Which of the following would result in an increase in the electric flux through the disk? - increasing the given orientation angle of the disk, but not exceeding an angle of 90° - increasing the area of the disk - decreasing the given orientation angle of the disk - decreasing the area of the disk - increasing the strength of the electric field - decreasing the strength of the electric field

- increasing the area of the disk - decreasing the given orientation angle of the disk - increasing the strength of the electric field

Five point charges q and four Gaussian surfaces S are shown in the figure. What is the total electric flux through surface S2? - 3q/εo - 5q/εo - zero - q/εo - 4q/εo - 2q/εo

2q/εo

Five point charges q and four Gaussian surfaces S are shown. What is the total electric flux through surface S4? 2q/εo 3q/εo 4q/εo q/εo zero 5q/εo

2q/εo

What is the magnitude of the net electric field at the center of the square due to the four charges in terms of q and a?

E = 4√2kq/a^2

Three dimensional point charge Gauss's Law

E(r) = q/4πr^2ϵ0

Two Dimensional Line charge Gauss's Law

E(r) = λ/2πrϵ0

One Dimensional Sheet charge Gauss's Law

E(z) = σ/2ϵ0

A disk with a radius of RR is oriented with its normal unit vector at an angle Θ with respect to a uniform electric field. Which of the following represent the electric flux through the disk? - E(πR2)sinΘ - E(2πR)sinΘ - E(πR2)cosΘ - E(πR2)sinϕ - E(2πR)cosΘ - E(πR2)cosϕ

E(πR2)cosΘ E(πR2)sinϕ

As in the video, we apply a charge +QQ to the half-shell that carries the electroscope. This time, we also apply a charge -QQ to the other half-shell. When we bring the two halves together, we observe that the electroscope discharges, just as in the video. What does the electroscope needle do when you separate the two half-shells again? - It does not deflect at all. - It deflects more than it did at the end of the video. - It deflects the same amount as at end of the video. - It deflects less than it did at the end of the video.

It does not deflect at all.

Five point charges q and four Gaussian surfaces S are represented in the figure shown. Through which of the Gaussian surfaces are the total electric flux zero? - S2 - The total electric flux is not zero through any of the Gaussian surfaces. - S1 - S3 - S4

S1 S3

In the figure, a uniform electric field is shown passing through a flat area A. In (a), the surface of area A is perpendicular to the electric field. In (b), the surface is tilted by an angle θ with respect to the electric field. In (c), the surface is parallel to the electric field. In which orientation is the electric flux through the surface the largest? - The electric flux is the largest through the surface shown in (c). - The electric flux is the largest through the surface shown in (b). - The electric flux is nonzero and equal through all of the surfaces shown. - The electric flux is zero through all of the surfaces shown. - The electric flux is the largest through the surface shown in (a).

The electric flux is the largest through the surface shown in (a).

In the figure, a uniform electric field is shown passing through a flat area A. In (a), the surface of area A is perpendicular to the electric field. In (b), the surface is tilted by an angle θ with respect to the electric field. In (c), the surface is parallel to the electric field. In which orientation is the electric flux through the surface the equal to zero? - The electric flux is the zero through the surface shown in (b). - The electric flux is zero through all of the surfaces shown. - The electric flux is the zero through the surface shown in (c). - The electric flux is the zero through the surface shown in (a). - The electric flux is nonzero and equal through all of the surfaces shown.

The electric flux is the zero through the surface shown in (c).

A net charge is placed on a hollow conducting sphere. How does the net charge distribute itself? - The net charge uniformly distributes itself on the sphere's outer surface. - The net charge uniformly distributes itself on the sphere's inner surface. - The net charge uniformly distributes itself throughout the thickness of the conducting sphere. - The net charge uniformly distributes itself on the sphere's inner and outer surfaces. - The net charge clumps together at some location within the sphere.

The net charge uniformly distributes itself on the sphere's outer surface.

Gaussian surfaces A and B enclose the same positive point charge. The area of surface A is two times larger than that of surface B. How does the total electric flux through the two surfaces compare? - The total electric flux through the two surfaces is equal. - The total electric flux through surface A is eight times larger than that through surface B. - The total electric flux through surface B is eight times larger than that through surface A. - The total electric flux through surface B is four times larger than that through surface A. - The total electric flux through surface A is four times larger than that through surface B.

The total electric flux through the two surfaces is equal.

A solid conducting sphere is placed in an external uniform electric field. With regard to the electric field on the sphere's interior, which statement is correct? - There is no electric field on the interior of the conducting sphere. - The interior field points in a direction opposite to the exterior field. - The interior field points in a direction perpendicular to the exterior field. - The interior field points in a direction parallel to the exterior field.

There is no electric field on the interior of the conducting sphere.


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