Karatsuba Algorithm for Fast Multiplications 1 & 2

Pataasin ang iyong marka sa homework at exams ngayon gamit ang Quizwiz!

Which of the following methods is used to make two numbers the same digits?

int makeEqualLength(string &str1, string &str2) makeEqualLength

The Karatsuba algorithm decreases the number of multiplications from n to ___.

n-1

The Karatsuba algorithm between two digits can be done using __.

the bit complexity

The first number is 3,233, and the second number is 3,434. How many multiplications are needed to solve the problem using the traditional multiplication algorithm?

16

The Karatsuba algorithm has a limitation that each number should have even number of digits. If you want to multiply two odd numbers, then how will you resolve this issue?

Append an additional 0.

Why is mathematical multiplication very simple?

Because there is a smaller number of digits

Which of the following is the main limitation with the Karatsuba algorithm?

Both the numbers should have even number of digits.

Which of the following is the first method that is being called once a program execution starts?

Compiler calls the main method

Which of the following is the correct first step in the Karatsuba algorithm?

Divide the number into half digits.

The __ method calculates the number of digits in the number. (Refer to the Java program in the lecture note to answer this question.)

GetSize

Which of the following is the main benefit of using the Karatsuba algorithm?

It reduces the number of multiplication operations.

__ calls the multiply method and gets the results inside the main function.

Line 57

___ is the starting method in the C++ program.

Main()

The first number is 21, and the second number is 32. How many multiplications are needed to solve the problem using the Karatsuba algorithm?

Three

You need to multiply the following numbers: 33,323,434 × 23,434,343 Which of the following algorithms should be used to complete this task?

Use Karatsuba algorithm

The Karatsuba algorithm uses the ___ approach to find the multiplication.

divide-and-conquer


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