Unit 6 Exam

A 10-acre parcel was sold for $3.50 per square foot. What was the total selling price for the parcel?

$1,524,600 An acre consists of 43,560 square feet. 43,560 × 10 = 435,600 total square feet. 435,600 × 3.50 = $1,524,600

If a farm described as "the NW¼ of the SE¼ of Section 10, Township 2 North, Range 3 West of the 6th. P.M." sold for $4,500 an acre, what was the total sales price?

$180,000 Disregard all elements of the description except those showing area. It is a quarter of a quarter of a section, or 1/16 of 640, or 40 acres. When sold, each acre brought $4,500, so the gross selling price is calculated as follows: 40 acres × $4,500 = $180,000.

A buyer purchased a half-acre parcel for $2.15 per square foot. What was the selling price of the parcel?

$46,827 An acre consists of 43,560 square feet; therefore, a half-acre has 21,780 square feet. If each square foot sells for $2.15, 21,780 sq ft × $2.15 per sq ft = $46,827.

A man buys 4.5 acres of land for $78,400. An adjoining owner wants to purchase a strip of this land measuring 150 feet by 100 feet. What should this strip cost the adjoining owner if the owner sells it for the same price per square foot he originally paid for it?

$6,000. Price divided by area (in square feet) gives cost per square foot. The area is 4.5 times the size of one acre, or 4.5 × 43,560 sq ft = 196,020 sq ft. Then, $78,400 divided by 196,020 sq ft = $0.3996 (essentially, $0.40) per square foot. Determining the purchase price of a 100-by-150-foot lot at the same cost per square foot requires finding the area of the lot: 100 × 150 = 15,000 sq ft. Multiply this area by $0.40: 15,000 sq ft × $0.40 = $6,000.

What is the number of the section designated as the school section in any township?

16

A parcel of land is 400 feet by 640 feet. The parcel is cut in half diagonally by a stream. How many acres are in each half of the parcel?

2.94. The parcel is 256,000 square feet: 400' ×640' = 256,000 sq ft. Half of it is 128,000 square feet. Each acre requires 43,560 square feet. Therefore: 128,000 sq ft ÷ 43,560 sq ft per acre = 2.938 acres (rounded to three decimal places). The nearest answer is 2.94.

How many square feet are in an acre

43,560 square feet in an acre

The N½ of the SW¼ of a section contains how many acres?

80 A section contains 640 acres. A ½ of ¼ of 640 equals 80 acres. Using decimals, the equation is 0.5 × 0.25 × 640 = 80

How many acres are contained in the tract described as "beginning at the NW corner of the SW¼, then south along the west line to the SW corner of the section, then east along the south line of the section 2,640 feet, more or less, to the SE corner of the said SW¼, then in a straight line to the POB"?

80 acres. The area described is a triangle formed when a quarter of a section is cut from one corner to the opposite corner. A section has 640 acres, a quarter-section has 160 acres, and half of that quarter has 80 acres.

A property contains 10 acres. How many lots of not less than 50 feet by 100 feet can be subdivided from the property if 26,000 square feet were dedicated for roads?

81. The area of ten acres in square feet is figured as follows: 10 acres × 43,560 sq ft = 435,600 sq ft. Reserving 26,000 square feet for roads leaves 409,600 square feet. The area of each lot is to be not less than 5,000 square feet: 50' ×100' = 5,000 sq ft. Divide the available square footage by the square footage needed for each lot: 409,600 sq ft ÷ 5,000 square feet = 81.92. Because each lot must be "not less than 50 feet × 100 feet," the property can be subdivided into 81 such lots.

Elements of the rectangular survey system

Base lines, principal meridians, and townships

Components of a metes-and-bounds description

Degrees, minutes, and seconds; Points of beginning; and Tangible and intangible monuments

What is the shortest distance between Section 1 and Section 36 in the same township?

Four miles. The shortest distance from Section 1 to Section 36 is from the bottom of Section 1 to the top of Section 36, or four miles.

A survey that provides only the location of the structures and improvements as related to property boundaries is an

Improvement Location Certificate (ILC).

In describing real estate, which method uses a property's physical features to determine boundaries and measurements?

Metes and bounds

As a legal description, "the northwest ¼ of the southwest ¼ of Section 6, Township 4 North, Range 7 West" is defective because it contains no reference to

a principal meridian.

A legal description must contain a reference to

a principle meridian

The meridian used in the rectangular survey system may not

necessarily be the nearest one.

No parcel of land is described by reference to more than one

principle meridian

The LEAST specific method for identifying real property is

street address

A legal description is a detailed way of describing a parcel of land and is based on information collected through a

survey

The location and dimensions of a parcel is identified on the

survey sketch

When surveying land, a surveyor refers to the principal meridian that is

within the rectangular survey system area in which the land being surveyed is located.