7B combining probabilities

Purchasing 5 winning lottery tickets in a row when each ticket has a 1 in 5 chance of being a winner

(1/5)^ 5 = 1/3125

Use the​ "at least​ once" rule to find the probabilities of the following event. Getting at least one head when tossing nine fair coins

1 - (1/2) ^ 9 = 511/512

Getting rain at least once in 4 days if the probability of rain on each single day is 0.5

1 - (1/2) ^4 = 0.938

Spinning two winners in a row with a wheel of fortune on which the winner is one of 29 equally likely outcomes.

1/29 x 1/29 = 1/841

Suppose you roll a die 6 times. What is the probability of getting at least one odd number​?

3/6 = 1/2 (1/2) ^6 = 1/64 1- 1/64 = 63/64

Drawing at least one ten when you draw a card from a standard deck 4 times​ (replacing the card each time you​ draw)

4 tens in 52 cards 48 cards aren't 10s P(not A) = probability of drawing a card that is not a 10 = 12/13 1 - (12/13)^4 = 0.2740

Drawing three jacks in a row from a standard deck of cards when the drawn card is not returned to the deck each time

4/52 x 3/51 x 2/50 = 1/5225

suppose you roll a single die, what is the probability of rolling either a 2 or a 3

P (2 or 3) = P (2) + P(3) = 1/6 + 1/6 = 2/6 =1/3

a 3 person jury must be selected at random from a pool that has 6 men and 6 women. what is the probability of selecting an all male jury

P (all male)= P (1st is male, 2nd is male, 3rd is male) = 6/12 x 5/11 x 4/10 = 120/1320 = 0.091

In which of the following situations are the events​ non-overlapping? Select all that apply.We roll a​ die, hoping for a 2 or a 5.

We roll a​ die, hoping for a 2 or a 5.

Randomly drawing and immediately eating two red pieces of candy in a row from a bag that contains 10 red pieces of candy out of 43 pieces of candy total.

dependent 10/43 x 9/42 = 0.050

Drawing three red cards in a row from a standard deck of cards when the drawn card is not returned to the deck each time

dependent, 2/17 ( 0.1176)

Randomly selecting a​ four-person committee consisting entirely of Americans from a pool of 12 Americans and 16 Canadians.

12/28 x 11/27 x 10/26 x 9/25 = 0.0242

What is the probability of getting a parking ticket on campus on at least one out of 6 days without a parking pass if the chance of not getting a ticket on a particular day when a parking pass​ isn't present is 0.15​?

(0.15)^6 = 0.000 1 - 0.000 = 100%

use the at least once rule to find the probability of at least one head when you toss three coins

P (at least one head) = 1 - P (no head) = 1 - (1/2)(1/2)(1/2) = 7/8

you purchase 10 lottery tickets with the probability of winning 1 in 10. what is the probability that you will have at least 1 winning ticket among the ten

P (at least one wins) = 1 - P (none win) = 1 - (9/10)^10 =0.651

Purchasing at least one winning lottery ticket out of 10 tickets when the probability of winning is 0.04 on a single ticket

P (no A in one trial) = 1 - 0.04 = 0.96 1 - 0.96^10 = 0.3352

what is the probability of rolling three 4's in a row with a single die?

P(4 on first roll , 4 on second roll, 4 on third roll) = P(4 on 1st roll) x P(4 on 2nd roll)x P(4 on 3rd roll) = 1/6 x 1/6 x 1/6 = 1/216

what is the probability that in a standard shuffled deck of cards you will draw a 5 or a spade

P(5 or spade) = P(5) + P(spade) - P(5 and spade) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13

Use the​ "at least​ once" rule to find the probability of getting at least one 6 in four rolls of a single fair die.

P(6) = 1/6 P(not 6) = 1 - P(6) = 1 - 1/6 = 5/6 1 - (5/6) ^ 4 = 0.518

If A and B are​ non-overlapping events, then

P(A or B) = P(A) + P(B)

If A and B are overlapping​ events, then

P(A or B) = P(A) + P(B) - P(A and B)

Getting a green light at a busy intersection at least once in six times through the​ intersection, given that the light in your direction is green 4/10 of the time

P(A) = 0.4 P(not A) = 1 - 0.4 = 0.6 n = 6 1 - (0.6)^6 = 0.953

what is the probability of drawing 2 aces from a deck of cards

P(A1) x P(A2/A1) = 1/13 x 3/51

Rolling two 6s followed by one 3 on three tosses of a fair die.

The individual events are independent. The probability of the combined event is (1/6) x (1/6) x (1/6) = 1/216

independent events

the occurence of one event does not affect the probability of the other event occurring. if A and B have individual probabilities P(A) and P(B), the probability that A and B occur together is P(A and B)= P(A) x P(B)

dependent events

the outcome of one event affects the outcome of another event the probability that dependent events A and B occur together is P (A and B) = P (A) x P (B given A) = P(A) x P (B/A) , where P (B given A) is the probability of event B given the occurrence of event A

non overlapping events

they cannot occur together, like the outcome of a coin toss (heads or tails) the probability for non-overlapping events A and B, P(A or B) = P(A) + P(B)

At least how many times do you have to roll a fair die to be sure that the probability of rolling at least one 2 is greater than 8 in 10 ​(0.80​)?

1 - (5/6) ^ 9 9 rolls ( test all exponents until the decimal is greater than 0.8)

Suppose you roll a die 4 times. What is the probability of getting at least one six​?

1 - 1/6 = 5/6 (5/6)^4 = 625/1296 1 - 625/1296 = 671/1296

what is the probability of drawing at least 1 ace when you draw a card from a standard deck 6 times, replacing the card each time

1-P (no A)^6 = 1 - (12/13)^6 = 1 - 0.619 = 0.381

The probability of drawing an ace or a spade from a deck of cards is the same as the probability of drawing the ace of spades.

The statement does not make sense because there is one card that is the ace of spades but more than one card that is either an ace or a spade.

The probability of getting heads and tails when you toss a coin is​ 0, but the probability of getting heads or tails is 1.

The statement makes sense because heads and tails are the only possible outcomes and it is impossible to get both heads and tails on a single coin toss.

My chance of getting a 5 on the roll of one die is 1/6​, so my chance of getting at least one 5 when I roll three dice is 3/6.

This does not make sense because the real probability would be 1 - (5/6) ^3 , which is not equal to 3 divided by 6.

In which of the following situations are the events​ overlapping? Select all that apply.

We want to know whether a person selected at random is a Democrat or a man.

In which of the following situations would we be interested in an​ either/or probability? Select all that apply.

We want to know whether a person selected at random is a Democrat or a man. We roll a​ die, hoping for a 2 or a 5.

Being dealt three jacks off the top of a standard deck of​ well-shuffled cards.

dependent and probability ( without replacement ) ​P(A and B and ​C) = ​P(A) x ​P(B given ​A) x ​P(C given A and​ B) 1/13 x 1/17 x 1/25 = 1/5525

overlapping events

if they can occur together, like the outcome of picking a queen or a club the probability that either A or B occurs: P (A or B) = P(A) + P(B) - P(A and B)

Drawing either a spade or a club from a regular deck of cards

non overlapping 13/52 + 13/52 = 1/2

Drawing either a black eight or a red three on one draw from a regular deck of cards

non overlapping, probability is 2/52 + 2/52 = 1/26 + 1/26 = 1/13

At least once rule (independent events)

suppose probability of an event A occurring in one trial is P(A). if all trials are independent, the probability that event A occurs at least once in n trials is: P (at least 1 event) = 1 - P (no event A)