BUS 205-Exam One HW Chapter 1-5

The first row of a stem-and-leaf chart appears as follows: 53 | 0 3 3 6 7 9. Assume whole number values.

a.What is the "possible range" of the values in this row? Possible range 530 to 539 b.How many data values are in this row? number of data values: 6 c.List the actual values in this row of data. 530 533 533 536 537 539 explanation: a. The smallest possible value is 530 and the largest possible value is 539. So the "possible range" is 530 to 539. b. Count the number of leaves to determine there are 6 values in this row. c. The stem is the leading digit or digits to the left of a vertical line. The leaves are the trailing digits. The values are 530 533 533 536 537 539.

The frequency distribution representing the number of frequent flier miles accumulated by employees at Brumley Statistical Consulting Inc. is given below. (Go to Homework to see graph)

e frequency of the first class (0 to 3,000 frequent flier miles) is five. d. 8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

1.Student IQ ratings. 2.Distance students travel to class. 3.The jersey numbers of a sorority soccer team. 4. A student's state of birth. 5.A student's academic class—that is, freshman, sophomore, junior, or senior. 6.Number of hours students study per week.

1.Interval 2.Ratio 3.Nominal 4.Nominal 5.Ordinal 6.Ratio

Molly's Candle Shop has several retail stores in the coastal areas of North and South Carolina. Many of Molly's customers ask her to ship their purchases. The following chart shows the number of packages shipped per day for the last 100 days. For example, the first class shows that there were 5 days when the number of packages shipped was 0 up to 5.

1.What is this chart called? -Histogram 2.What is the total number of frequencies? - 100 c.What is the class interval? -5 d.What is the class frequency of the 10 up to 15 class? class frequency-28 e.What is the relative frequency of the 10 up to 15 class? -.28 f.What is the midpoint of the 10 up to 15 class? midpoint-12.5 g. On how many days were there 25 or more packages shipped? -13 days explanation: A histogram is a graph in which the classes are marked on the horizontal axis and the class frequencies on the vertical axis. The class frequencies are represented by the heights of the bars and the bars are drawn adjacent to each other. b. 100, found by summing the individual class frequencies 5 + 13 + 28 + 23 + 18 + 10 + 3. c. 5, found by subtracting the lower limit of a class from the lower limit of the next class. d. There are 28 values between 10 and 15. e. 0.28, found by dividing the class frequency (28) by the total of all the frequencies (100). f. The class midpoint is computed by adding the lower limits of consecutive classes and dividing the result by 2. In this case (10 + 15)/2 is equal to 12.5. g. 13, found by adding the class frequency for the 25 up to 30 class [10] and the class frequency for the 30 up to 35 class [3].

Of the prime-time viewing audience, 5.9% watched shows on ABC, 7.6% watched CBS, 5.5% watched Fox, 6.0% watched NBC, 2.0% watched Warner Brothers, and 2.2% watched UPN for a combined total of 29.2% of the entire viewing audience. Calculate the relative percentage of the viewing audience that watched just those channels. (Do not consider the 70.8% of the viewing audience that watched other channels.)

ABC-20.21% CBS-26.03% FOX-18.84% NBC-20.55% Warner-6.85% UPN-7.53%

The information below shows the cost for a year of college in public and private colleges in 2000-01 and 2013-14. What is the geometric mean annual increase for the period for the two types of colleges? (Round your answers to 2 decimal places.)

Divide the ending period by the beginning period, take the nth root of the ratio and subtract one to compute the geometric mean rate of increase, where n is the number of periods. In this case, it is 9.26% for public colleges, found by 7,7132,440−−−−√13−1 Divide the ending period by the beginning period, take the nth root of the ratio and subtract one to compute the geometric mean rate of increase, where n is the number of periods. In this case, it is 7.31% for private colleges, found by 13,7685,504−−−−−√13−1 The rates of increase are slightly higher for public colleges.

AVX Home Entertainment, Inc., recently began a "no-hassles" return policy. A sample of 500 customers who recently returned items showed 400 thought the policy was fair, 32 thought it took too long to complete the transaction, and the rest had no opinion. On the basis of this information, make an inference about customer reaction to the new policy. (Round your answers to 1 decimal place.)

Fair=80% Too long=6.4% No Opinion=13.6% Explanation: The obvious majority of consumers (400/500, or 80%) believe the policy is fair with only 6.4% believing the policy is too cumbersome (32/500). On the strength of these findings, we anticipate all customers to feel the same and support the new policy.

The following frequency distribution reports the number of frequent flier miles, reported in thousands, for employees of Brumley Statistical Consulting Inc. during the most recent quarter.

FrequentFilerMiles- #employess 0 up to 3 5 3 up to 6 12 6 up to 9 23 9 up to 12 8 12 up to 15 2 Total 50 How many employees were studied? -50 What is the midpoint of the first class? -1.5 A frequency polygon is to be drawn. What are the coordinates of the plot for the first class? - x=1.5 y=5 b. 1.5 thousand miles, computed by adding the limits of 0 and 3 then dividing the result by 2. d. x = 1.5 (the class midpoint), y = 5 (the number of employees in that class)

Two thousand frequent business travelers are asked which midwestern city they prefer: Indianapolis, Saint Louis, Chicago, or Milwaukee. One hundred liked Indianapolis best, 450 liked Saint Louis, 1,300 liked Chicago, and the remainder preferred Milwaukee. Prepare a frequency table and a relative frequency table to summarize this information. (Round "Relative Frequency" answers to 3 decimal places.)

Indianapolis-Frequency:100 relative frequency:.050 St.Louis-Frequency:450 relative frequency:.225 Chicago-Frequency:1300 Relative frequency:.650 Milwaukee- Frequency:150 relative frequency:.075

In June, an investor purchased 350 shares of Oracle (an information technology company) stock at $18 per share. In August, she purchased an additional 310 shares at $28 per share. In November, she purchased an additional 570 shares, but the stock increased to $34 per share. What is the weighted mean price per share?

Multiply each value by its "weight" or number of times it happens to find the total. Then divide by the sum of the weights. In this case the weights are the number of shares purchased at each price. The weighted mean price per share is $27.93, found by 350($18)+310($28)+570($34)/350+310+570 =34360/1230=27.93

As part of a research project, you need to report the average profit as a percentage of revenue for the #1-ranked corporation in the Fortune 500 for each of the last 10 years.

Population

Statistics 201 is a course taught at a university. Professor Rauch has taught nearly 1,500 students in the course over the past 5 years. You would like to know the average grade for the course.

Population

You are looking forward to graduation and your first job as a salesperson for one of five large pharmaceutical corporations. Planning for your interviews, you will need to know about each company's mission, profitability, products, and markets.

Population

You are shopping for a new MP3 music player such as the Apple iPod. The manufacturers advertise the number of music tracks that can be stored in the memory. Usually, the advertisers assume relatively short, popular songs to estimate the number of tracks that can be stored. You, however, like Broadway musical tunes and they are much longer. You would like to estimate how many Broadway tunes will fit on your MP3 player.

Sample

The following cumulative frequency polygon shows the hourly wages of a sample of certified welders in the Atlanta, Georgia, area. (Go to Homework to see graph)

a. 40, because the vertical axis on the left ends at 40. b. 5, found by subtracting the lower limit of a class from the lower limit of the next class. c. 11 or 12, found by starting at $10 on the horizontal axis, up to the polygon and then across to the vertical axis on the left. d. About $18 per hour, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis. e. About $9 per hour, found by starting at 10 on the vertical axis on the left, over to the polygon and then down to the horizontal axis. f. About 78%, found by starting at $20 on the horizontal axis, up to the polygon and then across to the vertical axis on the right.

The distribution of the weights of a sample of 1,350 cargo containers is symmetric and bellshaped.

a.According to the Empirical Rule, what percent of the weights will lie between X¯¯¯−1s and X¯¯¯+1s =68% b.According to the Empirical Rule, what percent of the weights will lie between X¯¯¯ and X¯¯¯+ 3s ? =49.85% c.Below X¯¯¯−3s ? =.15% Look at examples

The ages of a sample of Canadian tourists flying from Toronto to Hong Kong were 34, 22, 69, 44, 51, 13, 56, 52, 40, and 40. (Round the range to nearest whole number and the standard deviation to 2 decimal places.)

a.Compute the range. - 56 b.Compute the standard deviation. -16.40 explanation: a. The range is the difference between the largest and smallest value or 56, found by 56 - 13. b. The sample mean is 42.1, found by 421/10. The differences between each value and the mean are: −8.1, −20.1, 26.9, 1.9, 8.9, −29.1, 13.9, 9.9, −2.1 and −2.1, respectively. Their squares are 65.61, 404.01, 723.61, 3.61, 79.21, 846.81, 193.21, 98.01, 4.41, and 4.41. The sum of the squares is 2,422.9. So the sample variance is 269.211, found by 2,422.9/9 and the sample standard deviation is the square root of that number or 16.41.

Consider these five values a population: 7, 4, 7, 4, and 8.

a.Determine the mean of the population. b.Determine the variance of the population explanation: a. The mean is the total divided by the number of values. So we have 6.0. b. A population variance is the mean of the squared deviation from the mean. In this case, it is 2.80, found by (7−6.0)2+(4−6.0)2+(7−6.0)2+(4−6.0)2+(8−6.0)25 look at homework 3 as reference

The following stem-and-leaf chart shows the number of units produced per day in a factory. stem left 3 2468 4 5 1349 6 1335579 7 269 8 24449 9 3479 10 88

a.How many days were studied? 29 b.How many observations are in the first row? 4 c.What are the minimum value and the maximum value? min 32,max 108 d.Select the actual values in the fourth row. -61,63,63,65,65,67,69 How many values are in the second row? -0 How many values are less than 70? 15 explanation: a. Count the number of leaves on the chart to determine there are 29 observations in the study. b. Each leaf corresponds to a separate observation. Since there are (4) leaves on the first row. c. The smallest value is found by combining the very first leaf with its corresponding stem: 32. The largest value is found by combining the very last leaf with its corresponding stem: 108. d. The values on each row are found by combining the stem of the row with each individual leaf on the same row. Since there are 7 leaves on the fourth row, there are 7 values. Each of the 7 leaves is combined with the stem of 6 to make a value. So the values are 61,63,63,65,65,67,69. e. Since there are no leaves on the second row, there are no values on that row. f. Find the number of values less than 70 by counting the number of leaves for the rows with a stem of 3, 4, 5, and 6. There are 4 leave(s) for stem row of 3; there are 0 leave(s) for stem row of 4; there are 4 leave(s) for stem row of 5; there are 7 leave(s) for stem row of 6. This makes the total number of values less than 70 equal to 4 + 0 + 4 + 7 = 15.