lab physic
Successive frames in the video are subject to motion blur caused by the movement of the mug over the exposure time of the camera. The effect becomes more pronounced as the speed of the mug increases, making it difficult to determine its exact position. Which choice is the most reasonable uncertainty for the position of the mug as it slides out of view?0.1 cm0.001 cm1 cm0.01 cm10 cm S
1 cm Each pixel represents a distance of 0.0633 cm. The edge of the cup has a maximum blur in the horizontal direction of about 10 pixels, or 0.633 cm. An uncertainty of 1 cm captures the full range of possible measurements throughout the blur. Continue Each pixel represents a distance of 0.0633 cm. The edge of the cup has a maximum blur in the horizontal direction of about 10 pixels, or 0.633 cm. An uncertainty of 0.001 cm is much smaller than the size of the blur.
The positive x-axis points to the right and the positive y-axis points up. The x-component of the mug's acceleration is 1.20 m/s2 . The y-component of the mug's acceleration is −0.50 m/s2 . What is the magnitude of the mug's acceleration? Multiple Choice 0.70 m/s2 1.30 m/s2 1.70 m/s2
1.30 m/s^2 The magnitude of the acceleration is given by a = (ax2 + ay2)1/2 = (x2 + y2)1/2 . Substituting the values yields a = 1.30 m/s2� = 1.30 m/s2 .
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. How much time does it take for the object to move downward 9.80 m from its highest point? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity. 0.71 s 1.41 sCorrect 2.00 s 2.82 s
1.41 s Use y=y0+v0yt+(1/2)ayt2y=y0+v0yt+(1/2)ayt2 , where y = 0 m, y0=9.80 my0=9.80 m , v0y=0 m/sv0y=0 m/s , and ay=−g=−9.80 m/s2ay=-g=-9.80 m/s2 Substituting the values yields t = 1.41 s.A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. How far does the object move downward from its highest point in 2.00 s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity.
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Its initial vertical component of velocity is - 4.90 m/s. Down is the negative direction. How much time elapsed if its final vertical component of velocity is - 19.6 m/s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity.
1.50 s Use vy=v0y+aytvy=v0y+ayt , where v0y=−4.90 m/sv0y=-4.90 m/s , vy=−19.6 m/svy=-19.6 m/s , and ay=−g=−9.80 m/s2ay=-g=-9.80 m/s2 . Substituting the values yields t = 1.50 s.
An object undergoes free-fall. Its initial speed is 4.90 m/s. How much time elapsed if its final speed is 19.6 m/s? Use g = 9.80 m/s2g = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice1.00 s 1.50 s 2.00 s 2.50 s
1.50 s vf=vi+gt where: ��vf is the final speed, ��vi is the initial speed, �g is the acceleration due to gravity (given as 9.80 m/s29.80m/s2), �t is the time of fall. Given that the initial speed (��vi) is 4.90 m/s4.90m/s, the final speed (��vf) is 19.6 m/s19.6m/s, and �=9.80 m/s2g=9.80m/s2, you can rearrange the equation to solve for �t: �=��−���t=gvf−vi Now, substitute the given values: �=19.6 m/s−4.90 m/s9.80 m/s2t=9.80m/s219.6m/s−4.90m/s �=14.7 m/s9.80 m/s2t=9.80m/s214.7m/s �=1.5 st=1.5s Therefore, the time elapsed if the final speed is 19.6 m/s19.6m/s is 1.5 s1.5s. The correct answer is "1.50 s."
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. How far does the object move downward from its highest point in 2.00 s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice 4.90 m 9.80 m1 9.6 m 39.2 m
19.6 m d=1/2gt^2 or y=y intinal+1/gt^2 d=0+1/2(9.8)(2)^2
What shape do you expect for a graph of the vertical position vs. time (y vs. t)?Straight line with positive slope Straight line with zero slope Parabola opening up Parabola opening down Straight line with negative slope
For a position versus time graph, a parabola opening downward represents an object experiencing constant vertical acceleration in the negative (downward) direction. This can be understood by studying the vertical position kinematic equation,
Parabola opening up
For a velocity versus time graph, a parabola opening upward represents acceleration that is increasing at a constant rate in the positive (left-to-right) direction. In the absence of air resistance, a projectile experiences zero horizontal acceleration. Try Again
Straight line with negative slope
For a velocity versus time graph, a straight line with negative slope represents constant, nonzero horizontal acceleration in the negative (right-to-left) direction. In the absence of air resistance, a projectile experiences zero horizontal acceleration (equivalent to a constant horizontal velocity)
What shape do you expect for a graph of horizontal position versus time (x vs. t)? Straight line with negative slope Straight line with positive slope Parabola opening up Parabola opening down Straight line with zero slope
Parabola opening down position versus time graph, a parabola opening downward represents an object experiencing constant horizontal acceleration in the negative (right-to-left) direction, which is consistent with the motion of the cart.
Select all of the following that are not approximately constant for the mug in this lab. Check All That Apply position velocity acceleration
Position velocity Position and velocity both depend on time while acceleration is approximately constant.
What shape do you expect for a graph of horizontal position versus time (v vs. t) ?Straight line with zero slope Parabola opening downParabola opening up Straight line with negative slope Straight line with positive slope
Straight line with positive slope Correct. For a position versus time graph, a straight line with positive slope represents the constant, horizontally directed, nonzero velocity for a projectile moving left-to-right (positive direction). This can be understood by studying the horizontal position kinematic equation for projectile motion, �=�0+�0��. Note that the equation is linear in time with a slope equal to the initial horizontal velocity
Magnitude of horizontal acceleration ax (m/s2)
The magnitude of the horizontal acceleration (ax) can be found using the following kinematic equation: vxfinal= vx+ax⋅t where: vx is the final horizontal velocity, vx is the initial horizontal velocity, ax is the horizontal acceleration, t is the time. If you have the initial horizontal velocity (vx), the final horizontal velocity (vx), and the time (�t), you can rearrange the equation to solve for ax: ax=vx−ux/t
The individual acceleration components, ax and ayhave been determined from the slopes of the vx vs. tand vy vs.t graphs, respectively. Which formula represents the magnitude of the net acceleration down the incline?
The magnitude of the net acceleration vector is obtained using the Pythagorean theorem with the known horizontal and vertical components. Continue
The motion of an object in free fall near the Earth's surface
The motion of an object in free fall near the Earth's surface can be described by the constant-acceleration kinematic equations.
Select the true statement about the velocity of the apple. Assume air resistance is negligible. The magnitude of the velocity always increases. The magnitude of the velocity always decreases. The magnitude of the velocity remains approximately constant. Submit
The velocity changes at a constant rate called the standard gravitational acceleration. In the absence of air resistance and any other forces acting on the apple (other than gravity), the apple is in free fall. As the apple falls, its velocity increases, and the magnitude of the velocity continuously increases due to the constant acceleration (gravity) pulling it downward. This is true until the apple reaches its terminal velocity, which is the maximum velocity it can achieve under the given conditions.
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. How far does the object move downward from its highest point in 2.00 s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity. 4.90 m 9.80 m 19.6 mCorrect 39.2 m
Use y = y0 + v0yt + (1/2)ayt2 y = y0 + v0yt + (1/2)ayt2 , where y = 0 m, t = 2.00 s , v0y = 0 m/sv0y = 0 m/s , and ay=−g=−9.80 m/s2 ay=-g=-9.80 m/s2 . Substituting the values yields y0 = 19.6 my0 = 19.6 m .
In this lab, which components of the object's motion can be described by constant-acceleration kinematic equations? Multiple Choice vertical components only thorizontal components only both vertical and horizontal components neither vertical nor horizontal components
both vertical and horizontal components
In this lab, which components of the object's motion can be described by constant-acceleration kinematic equations? Multiple Choice vertical components only horizontal components only both vertical and horizontal components neither vertical nor horizontal components
both vertical and horizontal components
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. How much time does it take for the object to move downward 9.80 m from its highest point? Use g = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice 0.71 s 1.41 s 2.00 s 2.82 s
d=1/2gt^2 or y=y intinal+1/gt^2 -9.80=0+1/2(-9.8)t^2 t=1.41S
How to calculate average velocity
displacement/time
What is the magnitude of the cart's acceleration parallel to the track inclined at an angle ?Calculate the magnitude of theoretical acceleration in cm/s2. Record in Lab Data to 1 decimal place
g.sin angle
A mug slides down an inclined plane. Air resistance can be ignored. Select all of the following that are approximately constant during the mug's motion. Check All That Apply horizontal component of velocity horizontal component of velocity vertical component of velocity vertical component of velocity horizontal component of acceleration horizontal component of acceleration vertical component of acceleration vertical component of acceleration
horizontal component of acceleration vertical component of acceleration Both components of the velocity are not constant because both components of the acceleration are not equal to zero. The acceleration is approximately constant, so both of its components are approximately constant.
A cart rolls up and then down an inclined plane. Friction and air resistance can be ignored. Select all of the following that are constant during the cart's motion. Check All That Apply horizontal component of velocity horizontal component of velocity vertical component of velocityvertical component of velocity horizontal component of accelerationhorizontal component of acceleration vertical component of acceleration
horizontal component of acceleration vertical component of acceleration Both components of the velocity are not constant because both components of the acceleration are not equal to zero. The acceleration is constant, so both of its components are constant.
In this lab, which of the following is always equal to zero? Multiple Choice magnitude of the acceleration vertical component of the acceleration horizontal component of the acceleration None of the above are always equal to zero.
horizontal component of the acceleration
You A mug starts from rest at the top of an inclined plane and slides down. Air resistance can be ignored. The plane is inclined at an angle of 30.0 degrees from the horizontal and its length is 2.35 m. The coefficient of kinetic friction between the mug and the inclined plane is 0.30. How much time does it take for the mug to move from the top of the inclined plane to the bottom? Use g = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice 0.71 s 1.41 s 2.00 s 2.82 s
0.71 s t= squer rote for 2Xd/g
Convert both x and y pixel-coordinates to meters. Record in Lab Data to 4 decimal places
o convert pixel coordinates to meters, you need to know the physical dimensions represented by the pixels. If you have information about the physical size of your camera sensor or the field of view, you can use that information for conversion. Assuming you know the physical size of the camera sensor in both the horizontal and vertical directions, you can use the following formulas to convert pixel coordinates to meters: X Position in Meters=X Pixel-coordinate×(Horizontal Size/MetersNumber of Pixels in Horizontal Y Position in Meters=Y Pixel-coordinate×(Vertical Size in Meters/Number of Pixels in Vertical Direction) ) If you don't have information about the physical size, you might need to use calibration techniques to determine the conversion factor between pixels and meters.
What shape do you expect for a graph of the vertical velocity vs. time Straight line with negative slope Parabola opening up Parabola opening down Straight line with positive slopeStraight line with zero slope
straight line with negative slope The vertical velocity component has a linear dependance on time. Because the acceleration is in the negative direction, the velocity should decrease as time increases. Continue
What shape do you expect for a graph of the horizontal velocity vs. time
straight line with negative slope nonzero horizontal acceleration in the negative (right-to-left) direction. For the horizontal component of motion, the cart accelerates at a constant, nonzero rate in the negative (right-to-left) direction
What shape do you expect for a graph of the horizontal velocity vs. time (vx vs. t)? straight line with negative slope parabola opening up parabola opening down straight line with zero slope straight line with positive slope Submit
straight line with positive slope For a velocity versus time graph, a straight line with positive slope represents constant, nonzero horizontal acceleration in the positive (left-to-right) direction.
Constant Velocity:
straight line with zero slope. T If the object is moving with a constant horizontal velocity, the graph would be a straight line with zero slope. This indicates that the velocity is not changing over time.
What shape do you expect for a graph of the vertical position vs. time (y vs. t)? Straight line with zero slope Parabola opening up Straight line with negative slope Straight line with positive slope Parabola opening down
Parabola opening down The position has a quadratic dependance on time. Because the acceleration is in the negative direction, the position should decrease as time increases
Data from an experiment
Data from an experiment can be analyzed by constructing a linear graph with a best-fit line.
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Its initial vertical component of velocity is - 4.90 m/s. Down is the negative direction. What is its final vertical component of velocity after 2.00 s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice - 14.7 m/s - 19.6 m/s - 24.5 m/s - 39.2 m/s
- 24.5 m/s To find the final vertical component of velocity after 2.00 seconds, you can use the kinematic equation for vertical velocity under constant acceleration: vy=v0y−g⋅t where: vy is the final vertical component of velocity, v0y is the initial vertical component of velocity, g is the acceleration due to gravity, t is the time. Given that v0=−4.90 m/sv, g=9.80m/s2, and �=2.00 st=2.00s, plug in these values to calculate vy: vy=−4.90−9.80⋅2.00 −4.90−19.60 y=−24.50m/s −24.50m/s
A projectile is moving along a parabolic path through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Its initial vertical component of velocity is - 4.90 m/s. Down is the negative direction. What is its final vertical component of velocity after 2.00 s? Use g = 9.80 m/s2m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice- 14.7 m/s- 19.6 m/s - 24.5 m/s Correct- 39.2 m/s
- 24.5 m/s Use vy=v0y+aytv y=v0y+ayt , where v0y=−4.90 m/sv0y =-4.90 m/s , t = 2.00 s, and ay=−g=−9.80 m/s2ay=-g=-9.80 m/s2 . Substituting the values yields vy=−24.5 m/svy=-24.5 m/s .
f two objects have the same initial position at the same initial time, and the same final position at the same final time, then which speed would always be the same for both? Multiple Choiceinitial speedfinal speedaverage speedinstantaneous speed
average speed
A boat travelled a total distance of 40 km. During the first hour, it travelled at an average speed of 10 km/hr. During the last hour, it travelled at an average speed of 30 km/hr. What was its average speed over the total distance of 40 km? Multiple Choice 1 5 km/hr 18 km/hr 20 km/hr 24 km/hr
20 km/hr. Average speed is equal to distance divided by the time interval. Therefore, the average speed over the total distance was (40 km)/(2 hr) = 20 km/hr. The average speed of the boat over the total distance can be calculated by dividing the total distance by the total time taken. For the first hour, the boat traveled at an average speed of 10 km/hr, so the distance covered was 10 km/hr * 1 hr = 10 km. For the last hour, the boat traveled at an average speed of 30 km/hr, so the distance covered was 30 km/hr * 1 hr = 30 km. So, the total distance covered by the boat is 10 km + 30 km = 40 km. The total time taken for the trip is 1 hour + 1 hour = 2 hours. Therefore, the average speed over the total distance of 40 km is 40 km / 2 hr = 20 km/hr. So, the correct answer is 20 km
An object undergoes free-fall. Its initial speed is 4.90 m/s. What is its final speed after falling for 2.00 s? Use g = 9.80 m/s2g = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice14.7 m/s 19.6 m/s 24.5 m/s 39.2 m/s
24.5 m/s The final speed (��vf) of an object undergoing free fall can be calculated using the following kinematic equation: ��=��+��vf=vi+gt where: ��vf is the final speed, ��vi is the initial speed, �g is the acceleration due to gravity (given as 9.80 m/s29.80m/s2), �t is the time of fall. Given that the initial speed (��vi) is 4.90 m/s4.90m/s, the time (�t) is 2.00 s2.00s, and �=9.80 m/s2g=9.80m/s2, you can now substitute these values into the equation: ��=4.90 m/s+(9.80 m/s2×2.00 s)vf=4.90m/s+(9.80m/s2×2.00s) ��=4.90 m/s+19.60 m/svf=4.90m/s+19.60m/s ��=24.50 m/svf=24.50m/s Therefore, the final speed after falling for 2.00 s2.00s is 24.50 m/s24.50m/s. The correct answer is "24.5 m/s."
A mug starts from rest at the top of an inclined plane and slides down. Air resistance can be ignored. The plane is inclined at an angle of 30.0 degrees from the horizontal and its length is 4.70 m. The coefficient of kinetic friction between the mug and the inclined plane is 0.30. What is the mug's speed when it reaches the bottom? Use vy2 = v0y2 + 2ayΔy��2 = �0�2 + 2��Δ� as the magnitude of the acceleration due to gravity. Multiple Choice2.35 m/s3.32 m/s4.70 m/s6.65 m/s
4.70
Successive frames in the video are subject to motion blur caused by the movement of the basketball over the exposure time of the camera. The blur introduces uncertainty when locating the position of the ball. Which choice below is the most reasonable uncertainty for the position of the basketball?5 cm0.5 m0.5 cm5 m0.05 cm
5 cm Successive frames in the video are subject to motion blur caused by the movement of the basketball over the exposure time of the camera. The blur introduces uncertainty when locating the position of the ball, The distance per pixel is 0.0065 m or 0.65 cm. The edge of the basketball has a maximum blur in the horizontal direction of between 6 to 8 pixels, or between 3.9 cm and 5.2 cm. Continue
Which of the following is equal to 60 frames/min? Multiple Choice 60 frames/s 3600 frames/s 60 frames/h r3600 frames/hr
60 frames/s
Which of the following is equal to 60 frames/min? Multiple Choice 60 frames/s 3600 frames/s 60 frames/hr 3600 frames/hr
60 frames/s 60 frames per minute is equivalent to 1 frame per second. Therefore, none of the options provided are correct. Here's how you can calculate it: There are 60 seconds in a minute. So, if you have 60 frames per minute, you would divide 60 frames by 60 seconds to find the rate in frames per second: 60 seconds/60 frames=1 frame/second
An electric car travelled a total distance of 120 km. During the first 60 km, it travelled at an average speed of 60 km/hr. During the last 60 km, it travelled at an average speed of 120 km/hr. What was its average speed over the total distance of 120 km? Multiple Choice 72 km/hr 80 km/hr 90 km/hr 108 km/hr
80 km/hr The time interval for the first 60 km was (60 km)/(60 km/hr) = 1 hr, and the time interval for the second 60 km was (60 km)/(120 km/hr) = 0.5 hr, so the total time interval was 1.5 hr. Average speed is equal to distance divided by the time interval. Therefore, the average speed over the total distance was (120 km)/(1.5 hr) = 80 km/hr. The average speed of the car over the total distance can be calculated by dividing the total distance by the total time taken. For the first 60 km, the car traveled at an average speed of 60 km/hr, so the time taken was 60 km / 60 km/hr = 1 hour. For the last 60 km, the car traveled at an average speed of 120 km/hr, so the time taken was 60 km / 120 km/hr = 0.5 hours. So, the total time taken for the trip was 1 hour + 0.5 hours = 1.5 hours. Therefore, the average speed over the total distance of 120 km is 120 km / 1.5 hr = 80 km/hr. So, the correct answer is 80 km/hr.
A mug starts from rest at the top of an inclined plane and slides down. Air resistance can be ignored. The plane is inclined at an angle of 30.0 degrees from the horizontal. The coefficient of kinetic friction between the mug and the inclined plane is 0.30. How far does the mug move in 2.00 s? Use g = 9.80 m/s2� = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice2.35 m4.70 m9.40 m
9 m
The linear regression equation takes the form vx=at xt. Which coefficient represents the horizontal acceleration (ax) of the mug? a ab
A = ax so vx=axt+vx to the linear regression equation.
An object is moving through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Select all of the following graphs that are straight lines. Check All That Apply horizontal component of position vs. time vertical component of position vs. time horizontal component of velocity vs. time vertical component of velocity vs. time
For an object moving through the air near the surface of the Earth, affected only by the Earth's gravity and with air resistance ignored, the following graphs would be straight lines: Horizontal component of position vs. time: This is because in the absence of air resistance, the horizontal motion is uniform, meaning the object moves at a constant speed in the horizontal direction. Horizontal component of velocity vs. time: Again, due to the absence of air resistance, the horizontal velocity remains constant, resulting in a straight line when plotted against time. The vertical component of position vs. time and the vertical component of velocity vs. time would not be straight lines. This is because the object is accelerating downwards due to gravity, so its vertical position and velocity are changing at a non-constant rate.
For motion near the Earth's surface
For motion near the Earth's surface, the free fall acceleration is approximately constant.
Record frame number, along with the x and y pixel-coordinates of last measurement in Lab Data
Frame Number: 1 X Pixel-coordinate: 271 pixels Y Pixel-coordinate: 439 pixels
A cart rolls up and then down an inclined plane. Friction and air resistance can be ignored. Select all of the following that are zero when the cart is located at the highest point farthest to the right on the inclined plane. Check All That horizontal component of velocity component of velocity vertical component of velocity vertical component of velocity horizontal component of acceleration horizontal component of acceleration vertical component of acceleration vertical component of acceleration
Horizontal Component of Velocity Vertical Component of Velocity When the cart is located at its highest point, it is instantaneously at rest. Therefore, both components of its velocity are zero. The acceleration vector points down and to the left. Therefore, both of its components are not zero.
in projetile motion, which of the following is always equal to zero? Multiple Choice speed vertical component of the velocity horizontal component of the velocity None of the above are always equal to zero.
In projectile motion, at the highest point of the trajectory, the vertical component of the velocity is always equal to zero. This is because the object momentarily stops moving upward before it starts descending. However, the horizontal component of the velocity does not necessarily become zero unless there are external horizontal forces (neglecting air resistance). So, among the given options: vertical component of the velocity The speed is not always zero. It changes depending on the object's initial velocity and the angle of projection. The vertical component of the velocity is not always zero. It changes due to the acceleration caused by gravity. The horizontal component of the velocity is constant in ideal projectile motion (ignoring air resistance), but it is not zero unless the object was launched straight up or down. So, the answer would be "None of the above are always equal to zero." This is based on the assumption of ideal projectile motion in a vacuum. In real-world scenarios where air resistance is a factor, the specifics could vary. Please refer to your specific course material for the most accurate answer. 3of10
Straight line with zero slope
In the absence of air resistance, a projectile experiences zero horizontal acceleration. If the acceleration is zero, the velocity must remain constant. This can be understood by studying the horizontal velocity kinematic equation for projectile motion, vx=v0x. Note the absence of any time dependance, the equation represents a constant valu
In this lab, which force (or forces) is (or are) assumed to act on the object when it moves through the air near the Earth's surface? Multiple Choice No forces are assumed to act. Only the gravitational force is assumed to act. The gravitational and air resistance forces are both assumed to act.
In this lab scenario, it is mentioned that the object is only affected by the Earth's gravity. Therefore, in the given context: Only the gravitational force is assumed to act. No other forces, such as air resistance, are mentioned, so they are not assumed to act on the object in this specific scenario.
In this lab, which of the following is always equal to zero? Multiple Choice speed vertical component of the velocity horizontal component of the velocity in correct None of the above are always equal to zero.
None of the above are always equal to zero.
In this lab, which force (or forces) is (or are) assumed to act on the object when it moves through the air near the Earth's surface? Multiple Choice No forces are assumed to act. Only the gravitational force is assumed to act. he gravitational and air resistance forces are both assumed to act.
Only the gravitational force is assumed to act.
Which force (or forces) is (or are) assumed to act on an object when it is in free fall? Multiple Choice No forces are assumed to act. Only the gravitational force is assumed to act. The gravitational and air resistance forces are both assumed to act.
Only the gravitational force is assumed to act.
What shape do you expect for a graph of the horizontal velocity vs. time (v vs. t)? Straight line with negative slope Parabola opening down Straight line with zero slope Parabola opening up Straight line with positive slope Submit
Straight line with zero slope If the horizontal velocity (��vx) of the basketball remains constant over time, the graph will be a horizontal line parallel to the time axis. The slope of the line will represent the constant velocity. Acceleration or Deceleration: If there is a constant horizontal acceleration or deceleration, the graph will be a straight line with a constant slope. The slope indicates the acceleration or deceleration. Changing Velocity: If the horizontal velocity changes continuously over time (perhaps due to external forces), the graph will be a curve. Projectile Motion: In projectile motion, the horizontal velocity (��vx) remains constant (ignoring air resistance). Therefore, the graph will be a straight line parallel to the time axis.
An apple is larger than and weights more than a grape. If both objects are in free fall, then which statement is true? Multiple Choice The apple's acceleration magnitude is greater than the grape's acceleration magnitude. The apple's acceleration magnitude is less than the grape's acceleration magnitude. The apple's acceleration magnitude is equal to the grape's acceleration magnitude.
The apple's acceleration magnitude is equal to the grape's acceleration magnitude. In free fall near the surface of the Earth, all objects experience the same acceleration due to gravity, regardless of their mass. This acceleration is denoted by the symbol �g, and its magnitude is approximately 9.8 m/s29.8m/s2 on the surface of the Earth. Therefore, in the scenario described, the correct statement is: The apple's acceleration magnitude is equal to the grape's acceleration magnitude.
If two objects have the same initial position at the same initial time, and the same final position at the same final time, then which speed would always be the same for both? Multiple Choice initial speed final speed average speed instantaneous speed
The average speed would always be the same for both objects. Average speed is calculated as the total distance traveled divided by the total time taken. If two objects start and end at the same positions at the same times, they have traveled the same total distance in the same total time, so their average speeds are the same. Here's the formula for average speed: Average speed=Total time/Total distance So, even if the two objects traveled at different speeds or took different paths, their average speeds over the total time interval would be the same. The initial, final, and instantaneous speeds could all be different.
What shape do you expect for a graph of the vertical velocity vs. time (Vfvs. t)? Straight line with negative slope Parabola opening up Straight line wi th positive slope Straight line with zero slope Parabola opening down Submit PHASE
The vertical velocity component has a linear dependance on time. Because the acceleration is in the negative direction, the velocity should decrease as time increases. ContinueFor an object in free fall near the Earth's surface, assuming air resistance is negligible, the graph of vertical velocity vs. time (��vy vs. �t) is expected to be a straight line with a negative slope. The vertical velocity of an object in free fall starts at zero when the object is released, then increases in the negative direction (downward) at a constant rate due to the acceleration of gravity. As time progresses, the velocity becomes more negative. Therefore, the graph of vertical velocity vs. time will be a straight line with a negative slope, indicating a constant acceleration downward
For this question, down is defined as the positive direction and up is defined as the negative direction. Given these definitions, what would be the shape of the vy vs. t graph for the apple? Multiple Choice straight line with zero slope straight line with positive slope straight line with negative slope parabola opening upparabola opening down
The vy vs. t graph for an apple falling down (where down is defined as the positive direction) would be a straight line with positive slope. This is because the velocity of the apple increases linearly over time due to the constant acceleration of gravity1. The positive slope indicates that the velocity is increasing in the positive direction, which in this case is defined as downward. So, the correct answer is "straight line with positive slope".
An object is dropped from rest and undergoes free-fall. How far does the object fall in 4.00 s? Use g = 9.80 m/s2g = 9.80 m/s2 as the magnitude of the acceleration due to gravity. Multiple Choice 9.80 m19.6 m39.2 m78.4 m
Therefore, the correct answer is 78.4 m. The distance fallen by an object in free fall can be calculated using the kinematic equation: =1/2gt^2 where: d is the distance traveled, g is the acceleration due to gravity (given as 9.80 m/s29.80m/s2), �t is the time of fall. Plug in the values: d=12×9.80 m/s2×(4.00 s)2d=21×9.80m/s2×(4.00s)2 d=12×9.80 m/s2×16.00 s2d=21×9.80m/s2×16.00s2 d=78.4 md=78.4m
Rank the following speeds, with the largest at the top and the smallest at the bottom,0.36 km/hr,120 m/min,6 m/s
Therefore, the ranking from largest to smallest is: 120 m/min 2m/s 6 m/s 0.36 km/hr 6 m/s 120 m/min = 2 m/s 0.36 km/hr = 0.1 m/s To rank the speeds from largest to smallest, let's convert all the speeds to a common unit. Since 1 kilometer is equal to 1000 meters and 1 hour is equal to 60 minutes, we can use meters per second (m/s) as the common unit. 0.36 km/hr=0.36 km/hr×1000 m1 km×1 hr3600 s≈0.1 m/s0.36km/hr=0.36km/hr×1km1000m×3600s1hr≈0.1m/s 120 m/min=120 m/min×1 min60 s≈2 m/s120m/min=120m/min×60s1min≈2m/s 6 m/s=6 m/s6m/s=6m/s Now, ranking them from largest to smallest: 120 m/min (approximately 2 m/s) 6 m/s 0.36 km/hrr (approximately 0.1 m/s)
A train travelled a total distance of 120 km. During the first 60 km, it travelled at an average speed of 30 km/hr. During the last 60 km, it travelled at an average speed of 60 km/hr. What was its average speed over the total distance of 120 km? 36 km/hr 40 km/hr 45 km/hr 54 km/hr
Time taken to travel the first 60 km at 30 km/hr: 30 km/hr60 km=2 hours Time taken to travel the last 60 km at 60 km/hr: 60 km/hr60 km=1 hour Total time taken: 2 hours+1 hour=3 hours Average speed: 3 hours120 km=40 km/hr So, the average speed of the train over the total distance of 120 km is 40 km/hr. Therefore, the correct answer is 40 km/hr.
Free throw range is 4.57 meters. Calculate one pixel's length in meters. Record in Lab Data to 4 decimal places,the pixels is 690
To calculate the length of one pixel in meters, you can use the formula: Pixel length=Free throw range/Number of pixels Given: Free throw range) = 4.57 meters Number of pixels) = 690 Using the formula:Pixel length=4.57meters/690 pixels =0.0066metee
Video is recorded at 60.00 frames per second (60.00 fps). Calculate time between one video frame in seconds. Record in Lab Data to 4 decimal places
To calculate the time between one video frame (frame duration) in seconds, you can use the formula: Frame duration= Duration/Number of frames Given: Duration (Duration) = 1 second Number of frames per second (Frame per second) = 60.00 fps Using the formula: Frame duration=1 second/60.00 fpsFrame =0.0167
To capture data of the apple in free fall, when should you start taking measurements?After the hand releases the apple (Frame 17 of 36)Once the hand starts moving (Frame 5 of 36)At the start of the video (Frame 1 of 36)
To capture accurate and relevant data for an object in free fall, it is ideal to start taking measurements at the point when the object is released. In this scenario, you should start taking measurements after the hand releases the apple. This ensures that the entire free fall motion is captured, and you can analyze the complete trajectory of the apple from the moment it begins its descent. Therefore, the appropriate time to start taking measurements would be at Frame 17 of 36, after the hand releases the apple.
Rank the following time intervals, with the largest at the top and the smallest at the bottom. Rank the options below. 100 s 6 min 0.01 hr
To rank the time intervals from largest to smallest, let's convert all the time intervals to a common unit. Since 1 minute is equal to 60 seconds and 1 hour is equal to 60 minutes, we can use seconds as the common unit. 0.01 hr=0.01 hr×60 min/hr×60 s/min=36 s0.01hr=0.01hr×60min/hr×60s/min=36s 6 min=6 min×60 s/min=360 s6min=6min×60s/min=360s 100 s=100 s100s=100s Now, ranking them from largest to smallest: 6 min6min (360 s) 100 s100s 0.01 hr0.01hr (36 s) Therefore, the ranking from largest to smallest is: 6 min 100 s 0.01 hr
Select the true statement about the acceleration of the apple. Assume air resistance is negligible. The magnitude of the acceleration always increases. The magnitude of the acceleration remains approximately constant. The magnitude of the acceleration always decreases.
When the apple is in free fall, the gravitational force causes it to accelerate at a constant rate. The acceleration of the apple is constant."The magnitude of the acceleration remains approximately constant. When air resistance is negligible, the only force acting on the apple is gravity. In the absence of other forces, the acceleration of an object in free fall near the surface of the Earth is constant and equal to the acceleration due to gravity, denoted by �g, which is approximately 9.8 �/�29.8 m/s2. This acceleration is directed downward, towards the center of the Earth. So, under the given conditions, the apple experiences a constant acceleration of 9.8 �/�29.8 m/s2 downward.
What shape do you expect for a graph of the vertical position vs. time (y vs. t) for the mug accelerating down the inclined surface to resemble most closely?parabola opening up parabola opening downs straight line with negative slope straight line with positive slope straight line with zero slope Submit
a parabola opening downward For a position versus time graph, a parabola opening downward represents an object experiencing constant vertical acceleration in the negative (downward) direction. This description is consistent with the motion of the mug. Continue Continue
What shape do you expect for a graph of the vertical position vs. time (y vs. t)?
a parabola opening downward position versus time graph, a parabola opening downward represents an object experiencing constant vertical acceleration in the negative (downward) direction. Here, the cart's initially upwardly directed velocity decreases at a constant rate. The cart reverses direction, then rolls back down the inclined track with constantly increasing, negatively directed velocity.
position versus time graph
a straight line with negative slope represents the constant, vertically directed, nonzero velocity for an object moving downward (negatively defined direction). The mug moves negatively (downwardly) with approximately constant acceleration. Try Again
When friction is present, which formula describes the magnitude of the mug's acceleration down a surface inclined at an angle θ? �||=�(sin(�)−��⋅cos(�))�||=�(sin(�)−��⋅sin(�))�||=�(cos(�)−��⋅sin(�))�||=�(cos(�)−��⋅cos(�))�||=�−��⋅cos(�) Submit
a= g (sin(θ)−μk cos(θ0)) In this formula: a is the acceleration of the mug down the incline, g is the acceleration due to gravity (approximately 9.8 m/s²), θ is the angle of the incline, μ is the coefficient of friction. The term �sin(�)gsin(θ) represents the component of gravity parallel to the incline, and ��cos(�)μgcos(θ) represents the frictional force opposing the motion. Subtracting the frictional force from the gravitational component gives the net acceleration down the incline when friction is present. Ensure that you use consistent units (e.g., meters for distance, seconds for time) and be aware that �μ is the coefficient of friction, which is a dimensionless quantity representing the frictional properties of the surfaces in contact.
In the absence of friction, which formula describes the magnitude of the mug's acceleration down a surface inclined at an angle angle?
a=g sin)a=g sin(θ) n the absence of friction, the acceleration of the mug down an inclined surface can be described by the following formula, which takes into account the component of gravitational acceleration parallel to the incline: a=g sin)a=g sin(θ) In this formula: a is the acceleration of the mug down the incline, g is the acceleration due to gravity (approximately 9.8 m/s²), θ is the angle of the incline.
n this lab, which of the following is constant? Multiple Choicepo position velocity acceleration
acceleration
n this lab, which of the following is constant? Multiple Choice position velocity acceleration
acceleration In the absence of external forces (neglecting air resistance and other factors), if an object is moving along a parabolic path through the air near the surface of the Earth and is only affected by the Earth's gravity, then the acceleration due to gravity (�g) would be constant.
An object is moving through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Select all of the following graphs that are straight lines.
all choses horizontal component of position vs. time vertical component of position vs. timev horizontal component of velocity vs. timehorizontal component of velocity vs. time vertical component of velocity vs. time The graph of the horizontal component of position vs. time is a straight line because the horizontal component of velocity is constant. The graph of the vertical component of position vs. time is not a straight line because the vertical component of velocity is not constant. Both graphs of the components of velocity vs. time are straight lines because both components of the acceleration are constant.
If two objects have the same initial position at the same initial time, and the same final position at the same final time, then which speed would always be the same for both? initial speed final speed average speed instantaneous speed
average speed
An object is moving through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Select all of the following that are zero when the object is located at its highest point. Check All That Apply horizontal component of velocity vertical component of velocity horizontal component of acceleration vertical component of acceleration
horizontal component of velocity vertical component of velocity orizontal component of acceleration vertical component of acceleration The acceleration vector points straight down. Therefore, the horizontal component of the acceleration is zero, and the vertical component of the acceleration is not zero. When the object is located at its highest point, it is moving sideways but not up or down. Therefore, the vertical component of the velocity is zero, and the horizontal component of the velocity is not zero. Vertical component of velocity: At the highest point of its trajectory, the object momentarily stops moving upwards before it starts falling back down. Therefore, the vertical component of velocity is zero at this point. The horizontal component of velocity, horizontal component of acceleration, and vertical component of acceleration are not zero at the highest point. The horizontal component of velocity remains constant throughout the motion (assuming no air resistance), the horizontal component of acceleration is always zero (no horizontal forces), and the vertical component of acceleration is always equal to the acceleration due to gravity (approximately 9.81m/s2
An object is moving through the air near the surface of the Earth. It is only affected by the Earth's gravity. Air resistance can be ignored. Select all of the following that are constant during the object's motion through the air. Check All That Apply horizontal component of velocity vertical component of velocity vertical component of velocity horizontal component of acceleration horizontal component of acceleration vertical component of acceleration
horizontal component of velocity vertical component of velocity vertical component of acceleration The acceleration is constant, so both of its components are constant. The horizontal component of the acceleration is zero. Therefore, the horizontal component of velocity is constant. The vertical component of velocity is not constant because the vertical component of acceleration is not zero. Horizontal Component of Velocity: The horizontal component of velocity remains constant if there are no horizontal forces acting on the object (e.g., no horizontal acceleration). Vertical Component of Acceleration: The vertical component of acceleration is constant and equal to the acceleration due to gravity (�g). Therefore, you should check the following options:
A cart rolls up and then down an inclined plane. Friction and air resistance can be ignored. Select all of the following graphs that are straight lines. Check All That Applyhorizontal component of position vs. timehorizontal component of position vs. timevertical component of position vs. timevertical component of position vs. timehorizontal component of velocity vs. timehorizontal component of velocity vs. timevertical component of velocity vs. timevertical component of velocity vs. time
horizontal component of velocity vs. time vertical component of velocity vs. time The graphs of both components of position vs. time are not straight lines because both components of velocity are not constant. Both graphs of the components of velocity vs. time are straight lines because both components of the acceleration are constant.
A mug slides down an inclined plane. Air resistance can be ignored. Select all of the following graphs that are approximately straight lines. Check All That Apply horizontal component of position vs. timehorizontal component of position vs. time vertical component of position vs. timevertical component of position vs. time horizontal component of velocity vs. timehorizontal component of velocity vs. time vertical component of velocity vs. timevertical component of velocity vs. time
horizontal component of velocity vs. time vertical component of velocity vs. time The graphs of both components of position vs. time are not approximately straight lines because both components of velocity are not approximately constant. Both graphs of the components of velocity vs. time are approximately straight lines because both components of the acceleration are approximately constant.
For this question, down is defined as the positive direction and up is defined as the negative direction. Given these definitions, what would be the shape of the y vs. t graph for the apple? Multiple Choicestraight line with zero slope straight line with positive slope straight line with negative slope parabola opening up parabola opening down
is a parabola opening downward. If down is defined as the positive direction and up is defined as the negative direction, and an object is dropped from rest, the shape of the y (position) vs. t (time) graph for the apple would be a parabola opening down. This is because the displacement of the object due to gravity follows a quadratic relationship with time. The position decreases as time squared when an object is dropped and accelerates downward under the influence of gravity. The equation representing this relationship is �=12��2y=21gt2, where �y is the position, �g is the acceleration due to gravity, and �t is the time. The graph of this equation is a parabola opening downward.
In free-fall, the only force acting on an object is
is assumed to be the gravitational force.
The vertical position y
is measured relative to a vertically oriented axis with "up" defined as the positive direction.
A cart rolls down and inclined plane. Friction and air resistance can be ignored. The mass of the cart is m, the magnitude of the acceleration due to gravity is g, and the plane is inclined at an angle θ from the horizontal. What is the magnitude of the gravitational force on the cart? Multiple Choice m mg mg cosθ mg sinθ
mg
A mug slides down an inclined plane. Air resistance can be ignored. The mass of the mug is m, the magnitude of the acceleration due to gravity is g, the coefficient of kinetic friction between the mug and the inclined plane is µk, and the plane is inclined at an angle θ from the horizontal. What is the magnitude of the normal force on the mug? Multiple Choice µkmg cosθ µkmg sinθ mg cosθ mg sinθ
mg cosθ
The initial height of the apple is a positive number, and the origin of the coordinate system is at the level of the table. What sign do you expect for the vertical component of the velocity once the apple is in motion? Negative Positive
negative The vertical-measurement coordinate system is oriented such that the positive direction points upward from the table. When the apple is released, the vertical coordinate decreases with time The sign of the vertical component of the velocity depends on the direction in which the apple is moving. If the apple is moving upward, the vertical component of the velocity is positive. If the apple is moving downward, the vertical component of the velocity is negative.
A locust jumps at an angle of 55.0° and lands 0.770 m from where it jumped. What is the maximum height of the locust during its jump (in centimeters)?
o find the maximum height of the locust during its jump, we can use the kinematic equations of projectile motion. The key information is the initial launch angle, the horizontal distance traveled, and the acceleration due to gravity. The vertical motion of the locust can be described using the following equation: ℎ=v0 sin2(sin) Angle(θ)/2g h is the maximum height, v0 is the initial velocity, θ is the launch angle, g is the acceleration due to gravity. The initial vertical velocity (v0y) can be expressed as �0v0sin(θ). Given that the locust lands 0.770 m from where it jumped, we can use this horizontal distance (�d) to find the initial velocity �d=v0cos(θ)⋅t t is the total time of flight. Let's calculate the initial velocity �0v0 and then use it to find the maximum height ℎh. Note that we'll need to convert the result to centimeters. The maximum height of the locust during its jump is approximately 25.4 cm25.4cm.
What shape do you expect for a graph of horizontal position versus time (x vs. t) for the mug accelerating down the inclined surface to resemble most closely? Straight line with negative slope Parabola opening upS straight line with zero slope Parabola opening down Straight line with positive slope
parabola opening upward Correct. For a position versus time graph, a parabola opening upward represents an object experiencing constant horizontal acceleration in the positive (left-to-right) direction, which is consistent with the motion of the mug. based on the kinematic equations that describe the motion of an object experiencing constant acceleration. The general equation for position as a function of time (�(�)x(t)) under constant acceleration (�a) is given by: �(�)=�0+�0�+12��2x(t)=x0+v0t+21at2 In this equation: �0x0 is the initial position, �0v0 is the initial velocity, �a is the acceleration, and �t is time. If the mug is accelerating down the inclined surface, it experiences a constant acceleration due to the incline. The acceleration term in the equation results in the quadratic term (12��221at2), leading to a parabolic curve when graphed. Therefore, you can expect the x vs. t graph to have a parabolic shape, with the slope of the curve indicating the acceleration of the mug down the incline. Keep in mind that this assumes constant acceleration, and factors like friction or changes in the incline may affect the shape of the graph. Continue
Recall that the kinematic equation for the vertical velocity component is ��=��0+��. Linear regression uses your measurements to estimate the parameters ��0 and � that generates a line which best fits your data. Which parameter in the equation corresponds to the acceleration of the apple?Slopey-intercept Submit
slope The acceleration is the rate of change of the velocity, which corresponds to the slope of the line. The kinematic equation for the vertical velocity component (��vy) can be expressed as: ��=�0�+���vy=v0y+ayt In this equation: ��vy is the vertical velocity at a given time. �0�v0y is the initial vertical velocity. ��ay is the vertical acceleration. �t is the time. In the context of linear regression, which is used to fit a line to experimental data, the parameter that corresponds to the acceleration (��ay) is the slope of the line. In the equation ��=�0�+���vy=v0y+ayt, the coefficient of the �t term represents the slope, and that is the acceleration of the apple in the vertical direction. Therefore, in linear regression, the parameter corresponding to the acceleration (��ay) is the slope of the line generated by the regression analysis.
If two objects have the same initial position at the same initial time, and the same final position at the same final time, then which speed would always be the same for both? Multiple Choice initial speedfinal speed average speedinstantaneous speed
speed average Average speed is equal to distance divided by the time interval. The distances and time intervals are the same for both objects. Therefore, their average speeds are the same.
What shape do you expect for a graph of the vertical velocity vs. time (vy vs. t) for the mug accelerating down the inclined surface to resemble most closely? straight line with negative slope parabola opening down straight line with positive slope parabola opening up straight line with zero slope Submit
straight line with negative For a velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction (consistent with the motion of the mug). Continue The shape you would expect for a graph of vertical velocity versus time (��vy vs. �t) for the mug accelerating down the inclined surface is a straight line with a constant negative slope. When an object is moving along an inclined surface under the influence of gravity (assuming no other forces are acting in the vertical direction), the vertical velocity increases linearly with time due to the constant acceleration caused by gravity. The equation for vertical velocity as a function of time (��(�)vy(t)) is given by: ��(�)=�0�−��vy(t)=v0y−gt In this equation: �0�v0y is the initial vertical velocity, �g is the acceleration due to gravity (negative since it acts downward), and �t is time. The term −��−gt results in a straight line with a constant negative slope when graphed. This indicates that the vertical velocity is decreasing over time due to the acceleration of gravity. Therefore, the expected shape of the ��vy vs. �t graph is a straight line with a constant negative slope.
The individual acceleration components, �� and �� have been determined from the slopes of the vy vs. t. � graphs, respectively. Which formula represents the magnitude of the net acceleration down the incline? straight line with positive slop straight line with negative slope parabola opening down parabola opening up straight line with zero slope Correct. For a velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction (consistent with the motion of the mug). Correct. For a velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction (consistent with the motion of the mug). Submit
straight line with negative slope For a velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction (consistent with the motion of the mug). Continue
What shape do you expect for a graph of the vertical velocity vs. time (vy vs. t)? straight line with positive slope parabola opening down straight line with zero slope parabola opening up straight line with negative slope Submit
straight line with negative slope For a velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction, which is consistent with the motion of the ca
A mug slides down an inclined plane at constant velocity. Air resistance can be ignored. The mass of the mug is m, the magnitude of the acceleration due to gravity is g, and the plane is inclined at an angle θ from the horizontal. What is the coefficient of kinetic friction between the mug and the inclined plane? Multiple Choice sinθ cosθ tanθ None of the above.
tan(θ) When a mug is sliding down an inclined plane at constant velocity, it means that the net force acting on the mug is zero. The forces acting on the mug include the component of gravity parallel to the incline (��sin(�)mgsin(θ)), the kinetic friction force (���μkN), and any other horizontal forces. Since the mug is moving at a constant velocity, the force of kinetic friction is balancing the component of gravity parallel to the incline. Therefore, we can set up the equation: ��sin(�)=mgsin(θ)=μkN Now, we need to express the normal force (�N) in terms of the forces perpendicular to the incline. The normal force is equal to the component of gravity perpendicular to the incline (��cos(�)mgcos(θ)): ����cos(�)=��sin(�)μkmgcos(θ)=mgsin(θ) Now, solve for the coefficient of kinetic friction (��μk): ��=��sin(�)��cos(�)=tan(�)μk=mgcos(θ)mgsin(θ)=tan(θ) So, the correct answer is tan(�)tan(θ).
In this labin projetile motion, which of the following is always equal to zero? Multiple Choice magnitude of the acceleration vertical component of the acceleration horizontal component of the acceleration None of the above are always equal to zero.
the horizontal component of the acceleration In this lab scenario where an object is moving along a parabolic path through the air near the surface of the Earth and is only affected by the Earth's gravity, the horizontal component of acceleration is always equal to zero. Gravity acts vertically, and there are no horizontal forces assumed (neglecting external horizontal forces). Therefore, the horizontal component of acceleration is always equal to zero. So, among the given options: horizontal component of the acceleration
What shape do you expect for a graph of the vertical velocity vs. time (vy vs. t)?
velocity versus time graph, a straight line with negative slope represents constant, nonzero vertical acceleration in the negative (downward) direction. A projectile experiences a constant vertical acceleration in the negative (downward) direction. This can be understood by studying the kinematic equation for the vertical velocity component, and making the substitution ay=−g. The result is a line with a negative slop
A mug slides down an inclined plane. Air resistance can be ignored. The mass of the mug is m, the magnitude of the acceleration due to gravity is g, the coefficient of kinetic friction between the mug and the inclined plane is µk , and the plane is inclined at an angle θ from the horizontal. What is the magnitude of the kinetic friction force on the mug? Multiple Choice µkmg cosθ µkmg sinθ mg cosθ mg sinθ
µkmg cosθ The magnitude of the kinetic friction force (�kineticfkinetic) on the mug sliding down the inclined plane can be expressed as: kinetic=fkinetic=μkN where: μk is the coefficient of kinetic friction, �N is the normal force. Since the mug is sliding down the incline, the normal force is affected by the component of gravity perpendicular to the incline, which is m g cos(θ). Therefore: f kinetic=μk=m g cos(θ)
