Solving radicals and quadratic equations with square roots

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√0=

0

√1=

1

BEFORE solving the equation √x=7 for x, how many solutions would you expect?

1 solution

√100=

10

√121=

11

√144=

12

√169=

13

√196=

14

√225=

15

√4=

2

BEFORE solving the equation 5x²=125 for x, how many solutions would you expect?

2 solutions, a positive and negative answer

BEFORE solving the equation x²=9 for x, how many solutions would you expect?

2 solutions, a positive and negative answer

√9=

3

√16=

4

√25=

5

√36=

6

√49=

7

√64=

8

√81=

9

Solve for x: √x = 9

SQUARE both sides (not square root!) x = 81

Solve for x: √x = 7

SQUARE both sides! x = 49

Solve for x: x² = 9

Square ROOT both sides! x = ±3

Solve for x: 6x² = 600

divide by 6, square toot both sides x = ±10

Solve for x: 5x² = 125

divide by five, then square root! x = ±5

Solve for x: √x +3 = 19

Subtract 3 then SQUARE both sides (not square root!) x = 256

Solve for x: x² + 8 = 89

Subtract 8, Square root both sides! x = ±9

x² = -25

no real solution

(x + 2)² = 16

x = 2 or -6

(x - 1)² = 9

x = 4 or -2

x² + 1 = 26

x = 5 or -5

(x - 3)² = 4

x = 5 or 1

x² - 2 = 34

x = 6 or -6

x² = 49

x = 7 or -7

x² = 64

x = 8 or -8

x² - 5 = 76

x = 9 or -9

(x - 4)² = 12

x = ±√12 + 4

x² = 40

x = ±√40

x² + 5 = 10

x = ±√5


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