answered math questions
2.2 In a large population, 66 % of the people have been vaccinated. If 3 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?
1-(1-0.63)^4
2.1 The table summarizes results from 978 pedestrian deaths that were caused by automobile accidents. If one of the pedestrian deaths is randomly selected, find the probability that both the pedestrian and the driver were intoxicated.Report the answer as a percent rounded to one decimal place accuracy. You need not enter the "%" symbol.
5.8
2.2 Suppose a jar contains 11 red marbles and 38 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.
so you do 11/49 x 10/48 = 0.04676
2.1 Suppose you roll a special 21-sided die. What is the probability that the number rolled is a "1" OR a "2"?
so you do P (1 or 2) = 3/21 - (1/21 - 2/21) = .1428571429 - (-0.0476190476) = 0.952380953
2.1 If one student is chosen at random,Find the probability that the student did NOT get an "B"
0.6486486486
2.1 If one student is chosen at random,Find the probability that the student was female OR got an "A".
27/62+24/62 - 8/62 = 0.693548387
2.2 if two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were intoxicated.
312 pedestrians intoxicated so 312/977 x 311/977 =101654 or 10.2 because there's two separate deaths, so when adding up the second group, subtract the first death.
2.1 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy. You need not enter the "%" symbol.
327/978 + 846/978 - 278/978 = 91.5%
2.1 A poll showed that 55.4% of Americans say they believe that Marilyn Monroe had an affair with JFK. What is the probability of randomly selecting someone who does not believe that Marilyn Monroe had an affair with JFK.Report the answer as a percent rounded to one decimal place accuracy. You need not enter the "%" symbol.
44.6
2.1 A geneticist conducts an experiment with peas, one sample of offspring consisted of 446 green peas and 144 yellow peas. Based on these results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected?
75.6 yes
2. 1 In a study of brand recognition, 1198 consumers knew of MicroSoft, and 23 did not. Use these results to estimate the probability that a randomly selected consumer will recognize MicroSoft
98.1%
2.2 A quick quiz consists of a multiple-choice question with 6 possible answers followed by a multiple-choice question with 5 possible answers. If both questions are answered with random guesses, find the probability that both responses are correct.
The six choices,each has the probability of 1/6 to be picked In the second question; ⇒The five choices, each has a probability of 1/5 to be picked Finding the probability that both responses are correct will be; 1/6* 1/5=1/30 As a percentage will be 1/30 * 100= 3.33
2.1 online Can the value 8 be a probability?
no. probability must be between 0 and 1
2.1 The table summarizes results from 983 pedestrian deaths that were caused by automobile accidents. 1 of the pedestrian deaths is randomly selected, find the probability that the driver was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy.
87.3
2.1 You draw one card from a standard deck (see picture). Use the Addition Rule to compute the probabilites. Write your answers with three significant figures.
P( ace or red card) 4/52 + 26/52 - 2/52 = .538
Find the probability that the student was male AND got a "A".
male and gotten an A = 13 divide 75 and get .17105
2.2 suppose 42% of people own dogs. if you pick two people at random what is the probability that they both own a dog?
probability both own a dog = (42/100)*(42/100) = 0.1764
Find the probability that the student was NOT a female that got a "A"
theres only 13 females who got A's. subtract that from the whole group and you have 53/67 = .79104
