precal

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cos(2x)/1+sin(2x)=(cotx-1)/cotx+1

((cosx-sinx)/sinx)/((cosx+sinx)/sinx)

tan(2x)

(2tanx)/1-tan^2x

(2cos^2x-1)^2/cos^4x-sin^4x=1-2sin^2x

(cos^2x-sin^2x)^2/cos^2x-sin^2x

exact value: sin(17pi/12)

(root6-root2)/4

exact value: arcsin(sin(-3pi/7))

-3pi/7

exact value: ((sin-20)/cos380)+tan200

0

Exact Value of csc450

1

exact value of cot(17pi/4)

1

exact value: sin(arcsin(-4/5)-arctan(3/4))

1

sin(pi-x)=sinx

1(sinx)

1+cot^2(-x)=csc^2x

1+cot^2x

1+tanx/1-tanx=cotx+1/cotx-1

1+tanx/1-tanx(cotx/cotx)

csc(2x)=(1/2)secxcscx

1/2sinxcosx

quadrant of: secx<0, sinx>0

2

solve on (0,2pi): cos(x/3-pi/4)=1/2

21pi/12

cosx=((1-tan^2(x/2))/(1+tan^2(x/2)))

2cosx/2

exact value: arcsec(-2)

2pi/3

exact value: sec(-pi/6)

2root3/3

sin(2x)

2sinxcosx

write trig exp: cos(arcsosU+arcsinV)

U(root(1-v^2))-U(root(1-u^2))

a)sin(a+b) b)cos(a+b), c)sin(a-b), d)tan(a-b) sina=5/13; -3pi/2<a<-pi, tanb=-root3; pi/2<b<pi

a)(5+12root3)/26 b)(12-5root3)/26 c)(5-12root3)/26 d)(-240-169root3)/69)

cos(2x)

cos^2x-sin^2x

secx-tanx=(cosx/1+sinx)

cos^2x/cosx+sinxcosx

write as trig exp: cos(arccsc(u))

cosx(root(u^2)-1/u)

cscx-1/cotx=cotx/cscx+1

cot^2x/cotx(cscx+1)

exact value: tan(arctan(pi))

pi

exact value: arcsin(root2/2)

pi/4

cos(x/2)

root(1+cosx/2)

tan(x/2)

root(1-cosx/1+cosx)

sin(x/2)

root(1-cosx/2)

exact value: cos(-30)

root3/2

exact value: (tan40-tan10)/1+tan40tan10

root3/3

exact value: sec(arcsin(2root5/5))

root5

Remaining 6: cosx=(-4/5), x in Q3

sinx=(-3/5) tanx=(3/4) cotx=(4/3) secx=(-5/4) csc=(-5/3)

sinxcosx/cos^2x-sin^2x=tanx/1-tan^2x

sinxcos^2x/cosx(cos^2x-sin^2x)

solve on (0,2pi): (root3x)+1=0

x=(2pi/3), (11pi/6)

solve on (0,2pi): cos^2x-sin^2x=1+cosx

x=(pi/2, 7pi/6, 11pi/6)

solve on (0,2pi): sin(3x)=-1

x=(pi/2, 7pi/6, 11pi/6)

solve on (0,2pi): cosx=-sin(-x)

x=(pi/4, 5pi/4)

exact value: arcos(sin(5p/4))

x=3pi/4

exact value: sec(arctan(1/2))

x=root5/2

find inverse: f(x)=2cos(3x+2); -2/3<x<-2/3+pi/3

y=((arcos(x/2)-2)/3)

find inverse: f(x)=2tanx-3; -pi/2<x<pi/2

y=arctan((x+3)/2)


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