Abeka grade 9 Algebra 1 Quiz 47 (2023/2024)

A bag of balloons contains 5 red, 15 green, and 5 blue balloons. 5. P (red and then green) if the first balloon is not replaced

A. 5/25 * 15/24

Matching: Use the following scenario to match the probability notation on the left with the work on the right that could be used to find each probability. Answers may be used once, more than once, or not at all. A bag of balloons contains 5 red, 15 green, and 5 blue balloons. 4. P (red and then green) if the first balloon is replaced

B. 5/25 * 15/25

A bag of balloons contains 5 red, 15 green, and 5 blue balloons. 7. P (green and then green) if the first balloon is not replaced

C. 15/25 * 14/24

A bag of balloons contains 5 red, 15 green, and 5 blue balloons. 6. P (green and then green) if the first balloon is replaced

F. 15/25 * 15/25

11. A basket contains 3 bananas, 2 oranges, and 5 apples. David pulled two pieces of fruit from the basket at random. Which of the following methods could be used to find the probability that the two pieces of fruit he pulled were a banana and an apple?

a. (3) (5) / ₁₀C₂ b. (3) (5) / 10! c. (3) (5) / (10) (10) d. (3) (5) / (10) (9)

Multiple Choice II: Determine which method could be used to find the answer for each scenario and write the letter of the correct choice in the blank. 8. Jeffery is purchasing a car. The customizations he can make are choosing one of 4 exterior colors and choosing one of 3 interior fabric options. Which of the following methods could be used to find the total number of possibilities available to him?

a. (4) (3) b. 4! c. ₄P₃ d. ₄C₃

Multiple Choice I: Simplify and write the letter of the correct choice in the blank. Show all work. 1. 4!

a. 1 b. 4 c. 10 d. 24 4! = 4 * 3 * 2 * 1 = 24

2. ₇P₂

a. 14 b. 21 c. 42 d. 49 ₇P₂ = 7 * 6 = 42

10. An electronics store has positions available in its window display for 3 devices. If the 3 positions will be filled from a selection of 7 individual devices, which of the following methods could be used to find how many possible window displays there are?

a. 3*7 b. 7*7*7 c. (7) (6) (5) d. (7) (6) (5) / (3) (2) (1)

3. ₈C₅

a. 40 b. 56 c. 336 d. 6,720 ₈C₅ = ₈P₅ / 5! = 8*7*6*5*4 / 5*4*3*2*1 = 56

9. There are 5 students that will be placed in a single-file line. Which of the following methods could be used to find how many possible ways there are to place these 5 students in line?

a. 5*5 b. 5! c. ₅P₁ d. ₅C₁