Algebra: Lesson 7.2 - Solving Linear Systems using Substitution

(3, 22)

-5x + 3y = 51 y = 10x - 8

(0, 2)

11x - 7y = -14 x = 2y - 4

(1, -1)

20x - 30y = -50 x = 1 - 2y

(8, -7)

2x - y = 23 x = 8

(6, 1)

3x - 5y = 13 x = -4y + 10

(13, 6)

4x - 7y = 10 y = x - 7

(5, -8)

5x + 2y = 9 y = -3 - x

(4, 3)

5x + 4y = 32 y = 9x - 33

(6, -3)

solve by substitution: 2x - 3y = 21 and y = 3 - x

(2, -3)

solve by substitution: x = 2 and 2x + y = 1

(-6, 1)

solve by substitution: x = y - 7 and x = -8y + 2

(-2, -4)

solve by substitution: y = 2x and x + 3y = -14

(1, 2)

solve by substitution: y = 2x and x + y = 3

(-1, 5)

solve by substitution: y = 3x + 8 and 5x + 2y = 5

(3, 9)

solve by substitution: y = 3x and 2x + y = 15

(-2, -9)

solve by substitution: y = 4x - 1 and y = 2x - 5

(1, 4)

solve by substitution: y = 4x and x + y = 5

(2, 1)

solve by substitution: y = x - 1 and x + y = 3

(-4, 2)

x + y = -2 y = x + 6

(2, -2)

x = -y x - 2y = 6

(5,3)

x = 17 - 4y y = x - 2

(-2, -7)

x = 2y + 12 -3x + y = -1

(6, 7)

x = 6 x - 5y = -29

(-1, -1)

x = y 5x + 2y = -7

(2, -1)

x = y + 3 2x - y = 5

(-10, -19)

x = y + 9 5x - 3y = 7

(1, 1)

y = 2x - 1 y = 3 - 2x

(-1, 11)

y = 9 - 2x 4x - y = -15