AP stats units 5-6
A∩B
"A" intersects "B"
The effect of adding/subtracting a constant (b) on a probability distribution
-adds to/subtracts from measures of center and location (mean, median, quartiles, percentiles) -Does not change measures of variability (range, IRQ, standard deviation) - does not change the shape of the probability distribution
the effect of multiplying/dividing by a constant (b) on a probability distribution
-multiplies/divides measures of center and location (mean, median, quartiles, percentiles) by b -multiplies/divides measures of variability (range,IRQ, standard deviation) by b -does not change the shape of distribution
calculating binomial probability with a graphing calculator
2nd, vars, binompdf, enter values,enter,
Basic Probability Rules
For any event A: 0≤P(A)≤1 If S is sample space in a probability model: P(S)=1 addition rule for mutually exclusive events: P(A or B) = P(A) + P(B) Complement Rule: P(A^c)=1-P(A) probabilities of equal outcomes: P(A)=number of outcomes in event A/ total number of outcomes in sample space
Geometric probability formula
If X has geometric distribution with probability p of success on each trial, the possible values of X are 1,2,3..... if x is any one of these values, P(X=x)=(1-p)^x-1 ·p
independant events
If knowing whether or not one event has occurred does not change the probability that the other event will happen. They are independent if P(A|B)= P(A|B^c)= P(A) or simply They are independent if P(AUB)=P(A)xP(B)
the effect of a linear transformation on a random variable
If y=a+bX is a linear transformation of random variable X, -the probability distribution of Y has the same shape as the probability distribution of X if b>0 -μY=a+bμX (mean=μ) -σY=|b|σX (because b could be negative)
discrete random variables with graphing calculator
List: enter values into L1 and probability into L2 Graph: stat plot, plot 1, histogram, Xlist:L1, Freq:L2 Window: adjust with X for values and Y for probability Graph Calc: stat, calc, 1-var
graphing binomial distribution on graphing calculator
List: list possible values of random variable X into L1 Highlight L2, binompdf(n,p), enter, make histogram Remember to include 0 with the values if you keep getting an extra number in L2
addition rule for mutually exclusive events
P(A or B) = P(A) + P(B)
Complement Rule
P(A^c)=1-P(A) P=probability A^c= complement of event A A=event A
Probability distribution for discrete random variable
Probability distribution for discrete random variable X lists the values xi and probabilities (pi) which must be between 0 and 1 and add to be 1 P(xi) or P(X=xi)
Intersection
The event "A and B" is called the intersection of events A and B. It consists of all outcomes that are common to both events, and is denoted A∩B
geometric distribution
The probability distribution of X with probability p of successes on any trial. Possible values of X are 1,2,3....
multiplication rule for independent events
The probability that both events A and B will occur P(A and B)=P(A∩B)= P(A)xP(B)
AUB
The union of A and B.
discrete random variable
X takes a fixed set of possible values with gaps between
event
any collection of outcomes from some random process
Geometric setting
arises when we perform independent trials of the same random process and record the number of trials it takes to get one success. On each trial, the probability p of success must be the same
binomial setting
arises when we perform n independent trials of the same random process and count the number of times that a particular outcome (called a "success") occurs: Four conditions for a binomial setting are (BINS) -Binary?Possible outcomes of each trial can be classified as success or failure -Independant? trials must independant (knowing outcome of one cannot predict outcome of another) -Number? number of trials n of the random process must be fixed in advance -Same probability? There is the same probability of success p on each trial
mean (expected value) of a discrete random variable
average value value over many, many trials of the same random process. Σxi⋅P(xi) AKA multiply each value of x by its probability and add the products
continuous random variable
can take any value in an interval on the number line
A|B
conditional probability, probability of A given that B has occurred Basically, the | means given that
probability model
description of some random process that consists of two parts: a list of possible outcomes and the probability for each outcome
median of probability distribution
find where the probability of .5 lies by reading and adding the probabilities left to right, choosing the number that lands on .5 or passes it
standard deviation of sum of independent random variables
for any 2 independent random variables X and Y, if S=X+Y, the variance of S is σ^2S= σ^2(of X)+σ^2(of Y) Standard deviation is the square root of variance σ^2S= √σ^2(of X)+σ^2(of Y)
mean (expected value) of difference of a random variables
for any 2 random variables X and Y, if D=X-Y, the mean of D is μD=μX-μY
mean(expected value) of sum of a random variables
for any 2 random variables X and Y, if S=X+Y, the mean of S is μ(of S)=μ(of X)+μ(of Y) Both the sum of means and the mean of the sum work.
General Multiplication Rule
for any random process, the probability that both event A and B occur can be found using P(A and B)=P(A∩B)= P(A)xP(B|A)
random process
generates outcomes that are determined purely by chance
geometric probability on a graphing calculator
geometpdf computes P(X=x) geometcdf computes P(X≤x) 2nd, vars, enter values, enter
probability distribution
gives a random variable's possible values and its probabilities
mutually exclusive (disjoint)
if 2 events have no outcome in common and therefore can never occur together P(A and B)=0
general addition rule
if A and B are any 2 events resulting from some random process P(A or B)=P(A)+P(B)-P(A and B) Aka P(AUB)=P(A)+P(B)-P(A∩B)
probabilities of equal outcomes
if all outcomes in a sample space are equally likely, the probability that event A occurs can be found using formula P(A)=number of outcomes in event A/ total number of outcomes in sample space
mean (expected value) of binomial random variable
if count X of sucesses has a binomial distribution of with number of trials n and probability of success p, the mean of X is μ(of X)=E(x)=np
standard deviation of a binomial random variable
if count X of sucesses has a binomial distribution of with number of trials n and probability of success p, the standard deviation of X is σ(of x)=√np(1-p)
independent random variables
if knowing the value of X does not help predict the value of Y. If knowing one variable does not change the probability distribution of the other variable
law of large numbers
if we observe more and more trials of any random process, then the proportion of times that a specific outcome occurs approaches its probability
simulation
imitates a random process in such a way that simulated outcomes are consistent with real-world outcomes
sample space
list of all possible outcomes
standard deviation of discrete random variables
measure how much the values of variables typically vary from the mean in many, many trials of the random process √Σ(xi-μx)^2⋅P(xi)
venn diagram
one or more circles surrounded by a rectangle, with each circle representing an event. The region inside the rectangle represents the sample space of the process
tree diagram
shows the sample space of a random process involving multiple stages. The probability of each outcome is shown on the corresponding branch of each tree. All probabilities after the first stage are conditional probabilities
Binomial probability formula
suppose that X is a binomial random variable with n trials and probability p of success on each trial. The probability of getting exactly X successes in n trials (x=0,1,2...,n) is P(X=x)=(n x)p^x(1-p)^n-x where (n x)=n!/x!(n-x)!
Large counts condition
suppose that a count X of successes has a binomial distribution with n trials and successes probability p. The large counts condition says that the probability of distribution X is approximately Normal if np≥10 and n(1-p)≥10 That is, the expected numbers of both successes and failures are both atleast 10
Random variable
takes numerical values that describe the outcomes of some random process
binomial random variable
the count of successes X in a binomial setting. The possible values of X are 1,2,....,n
Union
the event "A or B" is called the union of events A and B. It consists of all outcomes that are in event A or event B, or both, and is denoted A∪B
complement
the event that A does not occur
geometric random variable
the number of trials X that it takes to get a success in a geometric setting
binomial coefficient
the numbers of ways to arrange X successes among n trials (binomial coefficient)=n!/ x!(n-x)! for x=1,2,...,n where n! is given by n!=n(n-1)(n-2)⋅⋅⋅(3)(2)(1) and 0!=1 (the binomial coefficient is not a fraction)
Binomial Distribution
the probability distribution of X. Completely specified by 2 numbers: number of traits (n) of the random process and the probability (p) of success
how to find probability for a continuous random variable
the probability for any event containing a continuous random variable is the area under the density curve and directly above the values on the horizontal axis that makeup the event. Remember the area/probability=1, and area=basexheight . So probability=heightxthe value you want the probability of
conditional probability
the probability that 1 event happens given that another is known to have happened. The conditional probability that event A happens given that event B happened is P(A|B) P(A|B)= P(A and B)/P(B)= P(A∩B)/P(B)= P(Both events occur)/P(given B event occurs)
Probability
the proportion of times an outcome of a random process would occur in a long series of trials, represented by a number between 0 and 1. It is unpredictable in the short run but has a regular and predictable pattern in the long run
standard deviation of difference of independent random variables
the variance is σ^2D= σ^2(of X)+σ^2(of Y) the standard deviation σ^2D= √σ^2(of X)+σ^2(of Y) It is the variance of the sum, NOT the sum of the variances (we can't assume they are independent)
Binomial coefficient on graphing calculator
type the n, math, PRB, nCr, type the x, enter
linear combination of independent normal variables
we must know that the graph is normal/independent to know distributions
10% condition
when taking random sample of size n from the population of size N, we can treat individual observations as independent when performing calculations as long as n<0.10N
variance
Σ(xi-μx)^2⋅pi
mean(expected value) and standard deviation of geometric random variable
μ(of x)=E(X)=1/p σ(of x)=√1-p/ p