Area of Triangles

Finding area of a triangle with sAs

A=1/2ab(sinC) A=1/2bc(sinA) A=1/2ac(sinB)

Area of a right triangle

A=1/2bh

Finding area of a triangle with AsA

A=a²sinBsinC / 2SinA A=b²sinAsinC / 2SinB A=c²sinAsinB / 2SinC

Finding area of a triangle with AAA (Heron's Formula)

If Triangle ABC has sides abc opposite their respective angles. and you let the semiperimeter "s" be half of the triangle's perimeter than the area of the triangle is: A=√[s(s-a)(s-b)(s-c)] Semiperimeter is 1/2(a+b+c)

How is AsA formula built

Using sAs and law of sines A=1/2ab(sinC) a/sinA =b/sinB → b=[sinB(a) / sinA] A=1/2a[sinB(a) / sinA]sinC a²sinBsinC /2sinA