MATH CH 9
A mathematical system is a commutative group if all five of the following conditions hold.
1. The set of elements is closed under the given operation. 2. An identity element exists for the set under the given operation. 3. Every element in the set has an inverse under the given operation. 4. The set of elements is associative under the given operation. 5. The set of elements is commutative under the given operation.
(a+b)+c=a+(b+c)
Associative Property of Addition
identity element
a transformation that leaves an object unchanged
the commutative property of addition.
a+ b = b + a, for any elements a and b Ex: 3+4=4+3
Since clock 12 arithmetic under the operation of addition contains only the elements {1,2,3,4,5,6,7,8,9,10,11,12}, the mathematical system is
closed
If a binary operation is performed on any two elements of a set and the result is an element of the set, then that set is
closed under the given binary operation.
In clock 12 arithmetic under the operation of addition, since the system is closed, there is an identity element, each element has an inverse, and the associative and commutative properties hold, the mathematical system is a ___________________ group.
commutative
Every modulo system under the operation of addition meets all five requirements needed for it to be called a
commutative group
If a and b have the same remainder when divided by m, then a is_________ to b modulo m.
congruent
Since the sum of 0 and any integer is the given integer, we say that 0 is the additive_________ element for the set of the integers under the operation of addition.
identity
When a binary operation is performed on two elements in a set and the result is the identity element for the binary operation, each element is said to be the_________ of the other
inverse
an _______ element for A is an element which gives the identity when composed with A
inverse element
In clock 12 arithmetic, since 1+11= 11+1 =12, we say that 1 and 11 are additive
inverses
the commutative property of addition tells us
numbers can be added in any order and you will still get the same answer. The formula for this property is a + b = b + a.
when decrypting code,
subtract
Give the associative property of addition and illustrate the property with an example
For any elements a, b, and c, (a+b)+c=a+(b+c). An example of this is (3+2)+6=3+(2+6).
Is the set of negative integers a commutative group under the operation of addition?
No, it is not a commutative group. There is no identity element in the set of negative integers under the operation of addition. No, it is not a commutative group. There is at least one negative integer that does not have an inverse in the set of negative integers under the operation of addition.
Is the set of positive integers a group under the operation of addition?
No, it is not a group. There is at least one positive integer that does not have an inverse in the set of positive integers under the operation of addition. No, it is not a group. There is no identity element in the set of positive integers under the operation of addition.
Is the set of rational numbers a group under the operation of addition?
Yes, it is a group.
commutative group
a group in which the result of applying the group operation to two group elements does not depend on the order in which they are written.
The associative property states that
you can add or multiply regardless of how the numbers are grouped. By 'grouped' we mean 'how you use parenthesis'. In other words, if you are adding or multiplying it does not matter where you put the parenthesis. Add some parenthesis any where you like!.
is the set of integers a commutative group under the operation of addition?
Yes; it satisfies the five properties needed.
Is the set of rational numbers a commutative group under the operation of division?
No, it is not a commutative group. There exist rational numbers a, b, and c such that (a/b) /c not equal to a/(b/ c). No, it is not a commutative group. The set of rational numbers is not closed under the operation of division No, it is not a commutative group. There exist rational numbers a and b such that a/b not equal to b/a. No, it is not a commutative group. There is at least one rational number that does not have an inverse in the set of rational numbers under the operation of division.