Quiz-SN1 IST 22
An Ip address is composed of a host part and network part. If a host IP is 127.16.29.67, what is the host part? An Ip address is composed of a host part and network part. If a host IP is 127.16.29.67, what is the host part? 127.0.0.0 none of the given answers is correct 127.16.29.67 0.0.29.67 0.16..29.67 0.0.0.67
0.16..29.67
convert 1 to binary 0001 none of the given answers is correct 1000 00000001 10000000
00000001
convert 255 to binary 11111111 255 11111110 none of the given answers is correct 11111
11111111
A host IP is 127.16.29.67, what is its network IP A host IP is 127.16.29.67, what is its network IP 127.0.0.0 127.16.0.0 127.0.29.67 none of the given answers is correct 127.16.29.0 127.16.29.67
127.0.0.0
what is the subnet mask of an IPv4 address class C 255.255.0.0 255.255.255.0 0.0.0.255 none of the given answers is correct 255.0.0.0
255.255.255.0
convert 192 to binary 11111111 00000011 None of the given answers is correct 11000000 10000000
Dividend Remainder 192/2 = 96 0 96/2 = 48 0 48/2 = 24 0 24/2 = 12 0 12/2 = 6 0 6/2 = 3 0 3/2 = 1 1 1/2 = 0 1 11000000
11111111.11011111.11111111.0 is an example of a subnet mask 11111111.11011111.11111111.0 is an example of a subnet mask True False
False
255.255.28.0 is an example of a subnet mask 255.255.28.0 is an example of a subnet mask True False
False
convert 10011111 to decimal none of the given answers is correct 159 5 31 158
Step by step solution Step 1: Write down the binary number: 10011111 Step 2: Multiply each digit of the binary number by the corresponding power of two: 1x27 + 0x26 + 0x25 + 1x24 + 1x23 + 1x22 + 1x21 + 1x20 Step 3: Solve the powers: 1x128 + 0x64 + 0x32 + 1x16 + 1x8 + 1x4 + 1x2 + 1x1 = 128 + 0 + 0 + 16 + 8 + 4 + 2 + 1 Step 4: Add up the numbers written above: 128 + 0 + 0 + 16 + 8 + 4 + 2 + 1 = 159. So, 159 is the decimal equivalent of the binary number 10011111. 159
Network are generally segmented according to Network are generally segmented according to all of the given answers are correct geographic location device types departmental boundaries
all of the given answers are correct
