2.5 Study Guide

(7) x³y³ - y = x

(1 - 3x²y³) / (3x³y² - 1)

(49) y² = x³

(3x) / (4y)

(9) x³ - 3x²y + 2xy² = 12

(6xy - 3x² - 2y²) / (4xy - 3x²)

(13) sin(x) = x[1 + tan(y)]

(cos x - tan y -1) / (x sec² y)

(5) x³ - xy + y² = 7

(y - 3x²) / (2y - x)

(3) x^(½) + y^(½) = 16

- √(y/x)

(29) (x² + 4)y = 8 --- (2,1)

-(1/2)

(1) X=x² + y² = 9

-(x/y)

(47) x² - y² = 36

-36 / y³

(45) x² + y² = 4

-4 / y³

(31) (4 - x)y² = x³ ---- (2,2)

0

(57) 25x² + 16y² + 200x - 160y + 400 = 0

HT: (-4,0) and (-4, 10) VT: (0,5) and (-8,5)

(25) (x +y)³ = x³ + y³ ----- (-1,1)

[(-y(y + 2x) / x(x + 2y)) , -1]

(21) xy = 6 ---- (-6,-1)

[(-y/x) , (-1/6)]

(23) y² = (x² - 49) / (x² + 49) ---- (7,0)

[(98x/(y(x² + 49)²)) , undefined)

(27) tan(x+y) = x ---- (0,0)

[-sin²(x+y) or -(x²/(x²+1)) , 0]

(15) y = sin(xy)

[y cos (xy)] / [1 - x cos (xy)]

(41) a) equation: (x² / 2) + (y² / 8) = 1 at (1,2) b) show equation to (x² / a²) + (y² / b²) = 1 at (xof0, yof0) is (xof0 x / a²) - (yof0 y / b²) = 1

a) y = -2x +4 b) answers will vary :\

(11) sin(x) + 2 cos(2y) = 1

cos(x) / [4 sin (2y)]

(39) 3(x² + y²)² = 100(x² - y²)

y = -(2/11)x + (30/11)

(35) xy = 1

y = -x +2

(33) (y-3)² = 4(x-5)

y = -x +7

(37) x²y² - 9x² - 4y² = 0

y = √(3)x / 6 + 8√(3) / 3