2.5 Study Guide
(7) x³y³ - y = x
(1 - 3x²y³) / (3x³y² - 1)
(49) y² = x³
(3x) / (4y)
(9) x³ - 3x²y + 2xy² = 12
(6xy - 3x² - 2y²) / (4xy - 3x²)
(13) sin(x) = x[1 + tan(y)]
(cos x - tan y -1) / (x sec² y)
(5) x³ - xy + y² = 7
(y - 3x²) / (2y - x)
(3) x^(½) + y^(½) = 16
- √(y/x)
(29) (x² + 4)y = 8 --- (2,1)
-(1/2)
(1) X=x² + y² = 9
-(x/y)
(47) x² - y² = 36
-36 / y³
(45) x² + y² = 4
-4 / y³
(31) (4 - x)y² = x³ ---- (2,2)
0
(57) 25x² + 16y² + 200x - 160y + 400 = 0
HT: (-4,0) and (-4, 10) VT: (0,5) and (-8,5)
(25) (x +y)³ = x³ + y³ ----- (-1,1)
[(-y(y + 2x) / x(x + 2y)) , -1]
(21) xy = 6 ---- (-6,-1)
[(-y/x) , (-1/6)]
(23) y² = (x² - 49) / (x² + 49) ---- (7,0)
[(98x/(y(x² + 49)²)) , undefined)
(27) tan(x+y) = x ---- (0,0)
[-sin²(x+y) or -(x²/(x²+1)) , 0]
(15) y = sin(xy)
[y cos (xy)] / [1 - x cos (xy)]
(41) a) equation: (x² / 2) + (y² / 8) = 1 at (1,2) b) show equation to (x² / a²) + (y² / b²) = 1 at (xof0, yof0) is (xof0 x / a²) - (yof0 y / b²) = 1
a) y = -2x +4 b) answers will vary :\
(11) sin(x) + 2 cos(2y) = 1
cos(x) / [4 sin (2y)]
(39) 3(x² + y²)² = 100(x² - y²)
y = -(2/11)x + (30/11)
(35) xy = 1
y = -x +2
(33) (y-3)² = 4(x-5)
y = -x +7
(37) x²y² - 9x² - 4y² = 0
y = √(3)x / 6 + 8√(3) / 3