Copy this combustion equation 2 C4H10 + 13 O2 → 8 CO2 + 10 H20

2450

27.3 moles of butane reacted with an excess of oxygen gas, what volume of carbon dioxide is produced?

359

How many grams of butane would it take to produce 693L of dihydrogen monoxide?

2780

How many liters of oxygen gas would it take to produce 1.72kg of dihydrogen monoxide?

5.88x10^34

How many molecules of dihydrogen monoxide would be produced if 7.65x10^34 molecules of oxygen gas reacted with an excess of butane?

0.67

How many moles of CO2 will be produced if 35g of O2 reacts with an excess of C4H10

98

When 140g of oxygen gas reacted with butane it produced 1g of oxygen dihydride. What is the percent error?

6.93x10^-6

If 2.37x10^16 molecules of butane reacted with an excess of oxygen gas, how many grams of CO2 would be produced?

4.23x10^23

If 36.5 grams of oxygen react with butane how many molecules of carbon dioxide would be produced as a result?

33.1

If 40.6 moles of oxygen gas reacted with an excess of butane what is the percent yield of dihydrogen monoxide if the actual yield is 186 grams?

600

If 5 moles of C4H10 reacts with oxygen gas, What volume of water will be produced?

371

If 603L of oxygen gas reacted with an excess of butane, how many liters of carbon dioxide would be produced?

363

If 72.5 moles of butane reacted with an excess of oxygen gas, how many moles of dihydrogen monoxide would be produced?