Unit 4-8

Consider the velocity of slip mechanism in Figure 6-18. Assume the following values for vectors and angles in the figure: VA2 = 9 in/sec, θ2=49 deg, θ4=139 deg, and the Axis of slip is at an angle = 107 deg. If all angles are measured from the horizontal x-axis, determine the magnitude of Vslip42.

Cant get correct solution... but the process is <E = θ4+θ2-180 <F = 270-θ2-θslide <G = 90-θ4+θslide VA42 = VA2*sin(<E)/sin(<G) VA4 = VA2*sin(<F)/sin(<G)

A cam system is an example of path generation. (T/F)

False Cams are an example of function generation.

The magnitude of VB43 is the angular rate of the sliding link 3. (T/F)

False The magnitude of VB43 is the sliding rate of link 3 in link 4.

Jerk is defined as which of the following? - Derivative of acceleration - Derivative of velocity - Integration of position - Integration of acceleration

- Derivative of acceleration

Given the following linkage, if you were to start at joint B and proceed around the linkage clockwise which would represent the vector loop equation? - -R4-R1+R2+R3=0 - -R4+R1+R2-R3=0 - -R4-R1+R2-R3=0 - -R4-R1-R2-R3=0

-R4-R1+R2-R3=0

An instant center is a point common to two bodies in plane motion which has the same instantaneous velocity in each body. (T/F)

True

For a geared 5-bar linkage, theta_5 is equal to the phase angle (phi) when the crank angle (theta_2) is zero. (T/F)

True

The geared fivebar has 3 unknowns. (T/f)

True

The mechanical advantage is largest when the crank and the coupler are in toggle. (T/F)

True

The mechanical advantage is smallest when the transmission angle is zero. (T/F)

True

The mechanical advantage will be large when there is very small rocker motion for a given crank motion. (T/F)

True

In the 7th degree single polynomial case of example 8-9 the result produces a position undershoot of ... - 4011 in/sec^2 - (-1297) in/sec^2 - (-3.934) in - (-3458) in/sec^2

- (-3.934) in

For the 6th degree polynomial of example 8-9, the max acceleration was 1297 in/s^2. This value corresponds, to which of the following? (rounded to nearest 1000th) - 5.764 in/rad^2 - 0.002 in/deg^2 - 86.467 in/rad^2 - 1.5091 in/deg^2

- 5.764 in/rad^2 - 0.002 in/deg^2

Consider the following all revolute 4bar: L1=8 in, L2=5in, L3=8in, L4=6in, theta_2=75deg, theta_3=7.5deg, theta_4=78.2deg, omega_2=-50rad/sec, alpha_2=10rad/sec^3. - Aa_t - Aa_n - Ab_t - Ab_n - Aba_t - Aba_n

- Aa_t = 50.0 - Aa_n = 12500.00 - Ab_t = 1653.43 - Ab_n = 9980.11 - Aba_t = 2655.55 - Aba_n = 27.54

The velocity diagram (Figure 6-4b) is a vector addition triangle containing sides VA, VB and VBA. If VA is 10 (in/sec) at an angle 97 (deg) and VB is 8 (in/sec) at an angle 280 (deg), what is the y-component of VBA (in/sec)?

-17.8 VB = VA + VBA VB - VA = VBA VB*sin(angle VB)-VAsin(angle VA) = VBAy

The velocity diagram (Figure 6-4b) is a vector addition triangle containing sides VA, VB and VBA. If VA is 98 (in/sec) at an angle 122 (deg) and VB is 5 (in/sec) at an angle 36 (deg), what is the y-component of VBA (in/sec)?

-80.2 VB = VA + VBA VB - VA = VBA VB*sin(angle VB)-VAsin(angle VA) = VBAy

Consider the figure 6-5 below (not drawn to scale) from the textbook. Assume that the distance from I2,4 to A is 7 in. and the value of I2,4 to O2 is 2 in. If L1 = 8 in. and omega_2 = 8 rad/sec, what is omega_4 in rad/sec? Note: Round your answer to the nearest tenth.

1.6 V124 = omega_2*dist(I24,O2)/(dist(I24,O2)+L1)

If you have an all revolute 4 bar with L2 = 1.0, L3 = 2.0, L4 = 6.0, L1 = 5.0, and theta 2 = 39 deg, what is the value of theta 3 for the open configuration?

135

If |VBA| is 20 (in/sec) and L3 is 1.2 (in) what is the angular velocity of the coupler (rad/sec)?

16.7 Omega = V/L Omega = 20/1.2 = 16.7 rad/sec

Given a fourbar inverted crank-slider, if θ4 = 110 (deg) and γ = 59 (deg), what is θ3?

169 θ3 = θ4 + γ

Assume another 4 segment critical path example where the total time is 1sec and again the deceleration segment width is not specified other than to say it should be equal to the acceleration segment. What would be the acceleration segment width in degrees if the constant velocity portion is maintained for 0.625 sec and the return takes 95 degrees?

20

The velocity diagram (Figure 6-4b) is a vector addition triangle containing sides VA, VB and VBA. If θ4=61 (deg), L4=6 (cm) and ω4 =71 (rad/sec) what is the x-component of VB (cm/sec)?

206.5 VB = w4*L4 VBx=VB*cos(90+theta4)

If the cam rotates 266 degrees in 1.5 sec then the angular velocity of the cam is _____ rad/sec. Note: Round to the nearest tenth.

3.1 x [deg]/y [sec]*2*pi/360 => (pi/180)*x/y [rad/sec]

How many instant centers are there for a crank-slider 4-bar linkage?

6 n = 4 C = n(n-1)/2

If we specify 9 boundary conditions then we would expect a polynomial of what degree?

8 n = BC - 1

Acceleration analysis is best performed graphically. (T/F)

False We often avoid graphical techniques for acceleration analysis and instead rely on analytical techniques.

In the online example of the inverted crank-slider, VBA will be perpendicular to link BA. (T/F)

False While this is the case for our pure revolute linkages, here VBA depends on both the rotation of link BA as well as the sliding of link 3 in link 4.

Given the following linkage, if you were to start at joint A and proceed around the linkage clockwise which would represent the vector loop equation? - -R3+R4-R1+R2=0 - R2+R3-R4+R1=0 - R3-R4-R1+R2=0 - R3-R4-R1-R2=0

R3-R4-R1+R2=0

Take 2 derivatives of the 3-4 polynomial position equation in example 8-10. Choose all of the following that are true for the resulting velocity and acceleration expressions. - The value of acceleration at the end of the segment is h/beta^2*(-12) - The value of velocity at midpoint of segment is h/beta*1.5 - The acceleration is a 1-2 polynomial. - The value of velocity (in/deg) at the start of the segment is 0. - The velocity is a 2-3 polynomial.

all of the above

Which of the following values should be known at the start of Graphical Velocity Analysis on the all revolute fourbar? - theta 2 - theta 4 - theta 3 - all of the above

all of the above

Which of the following is the correct equation for calculating the number of IC's? - c=(n-1)/2 - c=(n^2-1)/2 - c=(n+1)/2 - c=n(n-1)/2

c=n(n-1)/2

The fundamental law of cam design states that the cam function must be ____________ through the first and second ____________ of displacement across the entire interval (360deg).

continuous, derivative

For the following linkage, if ω2>0 which of the following is true? - omega_3 < 0 - coupler experiences rectilinear translation - coupler experiences curvilinear motion - omega_3 > 0

coupler experiences curvilinear motion

In cam design we are trying to select _______________ in rise/fall to match periods of _________________

functions, dwell

For a geared 5-bar linkage, what does λ represent? - coupler point orientation - crank angle - phase angle - gear/transmission ratio

gear/ transmission ratio

Given the inverted crank-slider in table P6-3 row c, with L1 = 3, L2 = 10, L4 = 6, γ = 45 (deg), and θ2 = 45 (deg). If ω2 = 7, use Eq. 6.30b or 6.30c to determine ω4.

look on chegg search book chapter 6 problem 8 or 9

Consider the figure 6-7 below (not drawn to scale) from the textbook. Assume that the distance from I1,3 to A is 20.5 in. and the value of I1,3 to the slider at B is 17.3 in. If L2 = 5.7 in. and omega_2 = 9.5 rad/sec, what is the angular velocity of the coupler in rad/sec?

omega_3 = omega_2*L2/dist(A, I1,3

There is only two reasons to bring the follower to zero acceleration: (1) to change its __________ , or (2) match an adjacent segment that has __________ acceleration.

sign, zero

For a likage with 6 bars or more we will have multiple vector loops, so we will get more ______ equations.

simultaneous

Generally in graphical velocity analysis for an all revolute 4bar we will solve for omega_2 and omega_4. (T/F)

False

Graphical position analysis uses a computer program like Working Model, ADAMS, or MATLAB. (T/F)

False

This vector addition equation is correct: VB = VA + VAB (T/F)

False

Which of the following are types of joint closure for Cam-follower mechanisms? - form - flat - force - firm

- form - force

For the 2-3-4 polynomial of example 8-10, what is the value of velocity (units in/deg) at the start of the segment?

0

For the Grashof double-rocker the min transmission angle is _______ and the maximum is ______.

0 and 90

Consider the figure 6-7 below (not drawn to scale) from the textbook. Assume that the distance from I1,3 to A is 22.8 in. and the value of I1,3 to the slider at B is 15.1 in. If L2 = 5.6 in. and omega_2 = 5.8 rad/sec, what is the angular velocity of the coupler in rad/sec?

1.4 omega_3 = omega_2*L2/dist(A, I1,3)

In the CPM example, if the 1st and 3rd segments (acceleration and deceleration) were 60 deg wide instead of the original 30 deg wide, what would be the value of C2 in the position equation for segment 1?

1.7

Given an all revolute fourbar with L2 = 5, L3 = 8, L4 = 6, L1 = 8 , θ2=97, omega_2 =-2rad/sec, AP = 6 and delta_3 = 14deg. What is the magnitude of Vp?

10 Perform Pos. Analysis: l = sqrt(a^2 + d^2 - 2ad*cos(θ2)) β = atan( (a*sin(θ2)) / (d - a*cos(θ2)) ) γ = acos( (b^2 + c^2 - l^2) / (2bc) ) Δ = atan( (c*sin(γ)) / (b - c*cos(γ)) ) α = atan( (b*sin(γ)) / (c - b*cos(γ)) ) θ3 = Δ - β θ4 = 180 - β - α w3 = ( a*w2*cos(θ2 - θ3)) / (b + c*cos(θ4 - θ3)) Vpy = a*w2*cos(θ2) + AP*w3*cos(θ3 + δ) Vpx = -a*w2*sin(θ2) - AP*w3*sin(θ3 + δ) Vp = sqrt( Vpy^2 + Vpx^2 ) ** if asks for angle < Vp = atan(Vpy/Vpx)

What is the peak velocity (in/sec) in the double harmonic RFD cam design?

19.5

In example 8-9 two attempts are made at the cam design. The first does not specify a velocity at the conclusion of the rise. How many boundary conditions are used for the polynomial? - 6 - 7 - 8 - 3

7 at theta = 0, S=0, V=0, A=0 (3 BC's) at theta = 45deg, S = 1 inch. (1 BC) at theta = beta, S=0, V=0, A=0 (3 BC's) Total BC's = 7

If |VBA| is 10 (in/sec) and L3 is 1.2 (in) what is the angular velocity of the coupler (rad/sec)?

8.3 Omega = V/L

Determine the mechanical advantage of the rock-crusher in figure 6-11 if L2 = 0.8 ft, μ = 62.3 deg, ν = 18.3 deg, L4 = 2.1 ft and rout = 0.7 ft. Note: rin = L2.

8.46 ma = (L4sin(μ)r_in)/(L2sin(ν)r_out)

For a traditional all revolute 4bar linkage the coupler orientation is measured by a vector whose base is at which joint? - B - A -O2 - O4

A

When we derive equations for positions as functions of time or input angle we are doing what type of position analysis? - None of the following - Graphical - Computational - Algebraic

Algebraic

Consider the vector loops for a 4-bar crank slider. Which of the following loops are correct? - R3 = R2 - R1 - R4 - R2 - R3 - R4 - R1 = 0 - R1 + R4 = R2 - R3 - R2 = R1 + R4 + R3

All of the above

Which of the following are correct expressions for calculating mechanical advantage? - (T_out/T_in)(r_in/r_out) - F_out/F_in - (w2/w4)(r_in/r_out) - (l4sin(mu)/L2sin(v))(r_in/r_out)

All of these expressions are ultimately equal.

The velocity VBA is always perpendicular to which link? - Ground - Coupler - Rocker - Crank

Coupler

When doing position analysis, the equations in the textbook assume that the coordinate system is aligned with the ground link. (T/F)

True

Match the 4 segment widths (Beta's) for the constant velocity CPM example with their corresponding follower motions. - Beta_1 = 30 deg - Beta_2 = 180 deg - Beta_3 = 30 deg - Beta_4 = 120 deg

- Beta 1 = Accelerate from some position at 0in/sec to 10in/sec - Beta_2 = Maintain constant velocity - Beta_3 = Slow follower to 0 velocity - Beta_4 = Return to position where segment to acceleration started

Which of the following all-revolute 4bar instant centers is not necessarily at a joint? (can be more than one answer) - I2,4 - I1,3 - I1,4 - I1,2 - I2,3 - I3,4

- I2,4 - I1,3

Which of the following is true about the direction in which VA2 acts when the crank angle is 90 deg? (Select all that are true) - If omega_2 is positive (counter-clockwise), VA2 is moving to the left. - If omega_2 is negative (clockwise), VA2 is moving to the left. - If omega_2 is negative (clockwise), VA2 is moving to the right. - If omega_2 is positive (counter-clockwise), VA2 is moving to the right.

- If omega_2 is negative (clockwise), VA2 is moving to the right. - If omega_2 is positive (counter-clockwise), VA2 is moving to the left.

What of the choices below are reasons the double harmonic was chosen instead of the SCCA for the RDF cam design? - To create an optimal RFD cam design - To reduce the maximum acceleration magnitude - To create a smoother acceleration curve - To reduce the maximum velocity magnitude - None of the above

- To create a smoother acceleration curve

Which of the following are ways to classify cams? - Type of cam surface - Type of joint closure - Type of motion program - Type of cam rotation - Type of follower

- Type of joint closure - Type of motion program - Type of follower

Matching the following component names with their characteristic or definition. - VA2 - VA4 - VA42 - Axis of slip - Axis of transmission

- VA2 = Always perpendicular to the crank - VA4 = The velocity of point A on link 4 - VA42 = Also called Vslip42 - Axis of slip = Always tangent to the sliding motion - Axis of transmission = The axis through which force or motion is transferred

Match the following velocity vectors from row A in table P6-1 with their components. - V_Ax - V_Ay - V_Bx - V_By - V_BAx - V_BAy

- V_Ax = -10 - V_Ay = 17 - V_Bx = 32 - V_By = 16 - V_BAx = 42 - V_BAy = -1

In the examples of graphical velocity analysis for the all revolute 4bar we were unsure about the direction of which vector before we formed the vector addition triangle? - Vb - Vba - Va - none of the above

- Vba We know that VBA is perpendicular to the coupler but we don't generally know in which direction before forming the vector addition

Which of the following are correct conventions when analyzing a vector loop for Algebraic Position Analysis? - tail to head is positive - tail to head is negative - head to tail is positive - head to tail is negative

- head to tail is negative - tail to head is positive

If the position of a cam's follower is given in inches, then which of the following makes the most sense as units of jerk? - in/sec^2 - in/deg^2 - in/rad^3 - in/rad

- in/rad^3

The power in a translating mechanical system is equal to - torque time angular velocity - scalar dot product of force and velocity - scalar dot product of force and angular velocity - product of force and velocity

- scalar dot product of force and velocity

Which of the following expressions are equivalent for angular velocity? - V - θ dot - dθ/dt - w

- θ dot - dθ/dt - w

If the acceleration and decleration polynomials (segments 1 and 3) were 60deg wide instead of the original 30 deg wide, what would be the acceleration (in/sec^2) boundary condition (at theta = 0) for the return polynomial (segment 4)?

-120

The velocity diagram (Figure 6-4b) is a vector addition triangle containing sides VA, VB and VBA. If θ2=124 (deg), L2=4 (cm) and ω2=52 (rev/min) what is the x-component of VA (cm/sec)?

-18.1 change w2 to rad/sec -> w2*2pi/60 VA = w2*L2 VAx=VA*cos(90+theta2)

The velocity diagram (Figure 6-4b) is a vector addition triangle containing sides VA, VB and VBA. If θ4=58 (deg), L4=4 (cm) and ω4=82 (rad/sec) what is the x-component of VB (cm/sec)?

-278.2 VB = w4*L4 VBx=VB*cos(90+theta4)

In the CPM example, the position curve for segment 1 was as follows: s=5/6(θβ)2−5/18(θβ)3 For this example, what would be the value of the jerk (in/sec^3) when θ=0 for this segment? Hint: In figure 8-37 the value of the velocity (v) and the acceleration (a) at theta = 0 is provided. Make sure you can generate these values before differentiating once more to evalute the jerk equation.

-2880

Consider the all revolute fourbar in row b of table P6-1 (i.e.: L1 = 7, L2 = 9, L3 = 3, L4 = 8, theta2 = 85 deg, theta3 = -43.2 deg and theta4 = 120.2 deg). If omega2 = 4.8, what is the angular velocity of the coupler (omega3) in rad/sec?

-29 w3 = a*w2*sin(θ4-θ2)/b*sin(θ3-θ4) w4 = a*w2*sin(θ2-θ3)/c*sin(θ4-θ3) * note: a=L2 b=L3 c=L4 also when calculating w4 if there's a negative theta value replace subtraction with addition Ex: theta3 = -43.2 theta4 = 120.2 put in calculator... sin( 120.2 + 43.2) NOT sin(120.2 - (-43.2))

Consider the all revolute fourbar in row b of table P6-1 (i.e.: L1 = 7, L2 = 9, L3 = 3, L4 = 8, theta2 = 85 deg, theta3 = -43.2 deg and theta4 = 120.2 deg). If omega2 = 9.8, what is the angular velocity of the coupler (omega3) in rad/sec?

-59 w3 = a*w2*sin(θ4-θ2)/b*sin(θ3-θ4) w4 = a*w2*sin(θ2-θ3)/c*sin(θ4-θ3) * note: a=L2 b=L3 c=L4 also when calculating w if there's a negative theta value replace subtraction with addition Ex: theta3 = -43.2 theta4 = 120.2 put in calculator... sin( 120.2 + 43.2) NOT sin(120.2 - (-43.2))

Consider the resulting position equation for the 6th degree polynomial of example 8-8. The maximum was stated to be s = 2.37. What is the maximum velocity in units = in/deg?

0.05

Consider the figure 6-5 below (not drawn to scale) from the textbook. Assume that the distance from I1,3 to A is 13 in. and the value of I1,3 to B is 8.9 in. If L2 = 2 in., L4 = 4.3 in., and omega_2 = 2 rad/sec, what is omega_4 in rad/sec?

0.48 omega3 = omega2*L2/dist(I13,A) omega4 = omega3*dist(B,I13)/L4

The final cam design for example 8-10 results in a different value of maximum acceleration than the designs of example 8-9. What is the value of the maximum acceleration for the final cam design in example 8-10 divided by the largest acceleration found in example 8-9?

0.5

Consider the figure 6-5 below (not drawn to scale) from the textbook. Assume that the distance from I1,3 to A is 12.1 in. and the value of I1,3 to B is 9.1 in. If L2 = 2.5 in., L4 = 4.1 in., and omega_2 = 2.4 rad/sec, what is omega_3 in rad/sec? Note: Round your answer to the nearest tenth.

0.5 omega_3 = omega_2*L2/dist(AI1,3)

Consider the figure 6-5 below (not drawn to scale) from the textbook. Assume that the distance from I1,3 to A is 13.3 in. and the value of I1,3 to B is 8.6 in. If L2 = 2.1 in., L4 = 4.4 in., and omega_2 = 2.8 rad/sec, what is omega_4 in rad/sec?

0.9 omega3 = omega2*L2/dist(I13,A) omega4 = omega3*dist(B,I13)/L4

If a particular segment has a width of .5 seconds and the total cycle time is 1.5 seconds then what is x˙ (rad/sec) for this segment?

2

If we wanted the valves of an engine to remain open for a period of time, what type of function would we need? - Follow - Dwell - Fall - Rise

Dwell Here we would want a dwell function because we want the valves to remain open for a period of time.

A double harmonic is another good choice for a RDFD cam design. (T/F)

False

If the axis of slip is parallel to and lies within link 4 then VA4 and Vtransshould be perpendicular to one another. (T/F)

False

If we don't set a boundary conditions for a particular variable (i.e.: s, v, or a) it is equal to zero. (T/F)

False

In graphical position analysis for the traditional 4-bar all revolute linkage, the angle theta 4 is measured internal to the linkage. (T/F)

False

In the all revolute 4-bar graphical position analysis example, angle theta 3 was 230 degrees for the crossed configuration. (T/F)

False

Since the polynomial for the 6th degree polynomial case for example 8-9 seeks symmetry the maximum position of the follower was at theta = 45 deg. (T/F)

False

The following equation was used to solve for the velocity of the coupler point P: VP = VA + VAP (T/F)

False

The four unknowns for the Watt's sixbar are theta_3, theta_4, theta_5, and theta_7. (T/F)

False

The velocity of slip analysis is performed when there is a sliding joint between two links and one is a ground link. (T/F)

False

A 9th boundary condition was added to the single polynomial for the asymmetrical RFD example to attempt to eliminate the overshoot. (T/F)

False A 8th boundary condition was added (v=0 at theta = 45) or, start of rise S=V=A=0 at start of fall S=1, V=0 at end of fall S=V=A=0 Total BC's = 8.

A Cam linkage is equivalent to a 4-bar linkage with fixed link lengths. (T/F)

False A Cam linkage is equivalent to a 4-bar linkage with variable link lengths.

Checking whether or not a linkage is Class I Grashof isn't useful when doing algebraic position analysis. (T/F)

False Checking the Grashof condition for your linkage may help indicate whether or not it is actually indeterminate. (i.e. if the crank can only rotate 120 deg prior to toggle, but the design requests 150 deg)

The third link of a translating follower has an effective infinite length. (T/F)

False Effective Link 4 has an infinite length.

It is possible to have an actual mechanical advantage that is infinite. (T/F)

False Mechanical advantage can be theoretically infinite but in reality it is bounded by the strength of the mechanism.

A spring is more likely to be used on the follower in a "form closed" cam system than with a "force closed". (T/F)

False Springs are more likely used in a force closed system to provide the force to keep the follower in contact with the cam.

The types of followers given were radial, axial, and 3-D. (T/F)

False These were the types of cams

When there is an asymmetrical RFD cam design where a separate polynomial will be used for the rise and fall, the polynomial for the fall should be calculated first. (T/F)

False The polynomial with the smaller acceleration should (in this case the fall) should be calculated first.

In position analysis equations for the all revolute 4-bar, the +/- in the By calculation is because of which one of the following reasons? - Crank-slider (+) or Slider-crank (-) - Internal vs external theta 4 angles - The + is for theta 4, and the - is for theta 3 -Open or Crossed Configuration

Open or Crossed Configuration

A discontinuity will produce an infinite derivative. (T/F)

True

A nonGrashof triple rocker will have one toggle position when the crank angle (theta_2) is at its maximum value (1st or second quadrant). The second toggle position is the negative of the first. (T/F)

True

After mechanical advantage was redefined using torques, the angular velocities were brought in using the idea of power. (T/F)

True

For the purposes of this class, we stated that input power is equal to the output power for a linkage, i.e.: Pin = Pout. (T/F)

True

Graphical Position Analysis may require drawing the linkage multiple times. (T/F)

True

Graphical velocity analysis can still be useful as a quick check of calculated velocities in a linkage. (T/F)

True

Graphical velocity analysis generally assumes that position analysis has been previously performed. (T/F)

True

If angular velocity ratio is defined as mv = omega_4/omega_2 We can say that the mechanical advantage is inversely proportional to it. (T/F)

True

If asked for the length of a linkage with a strange shaped link (i.e. L-shape) you should use the dimension between two joints as the effective length. (T/F)

True

In algebraic position analysis a vector's orientation is always measured from its base or root. (T/F)

True

In the online example VB and VB4 are the same vector just written differently. (T/F)

True

In the traditional 4bar all-revolute linkage we use the following equation: VB = VA + VBA (T/F)

True

It is not possible to have a crank-slider with L2 = 2, L3 = 6, offset = 8, and theta_2 = 30. (T/F)

True

Solving algebraically for the coupler and rocker angles of the all revolute 4 bar requires multiple steps such that we generally solve it using a computer. (T/F)

True

The analytical velocity analysis solution can be described as determining a position vector equation and then differentiating it and solving for the unknowns. (T/F)

True

The angular velocity direction (CW or CCW) does not affect the magnitude of Vtrans or Vslip42. (T/F)

True

The cycloidal RFD cam design example that had an unnecessary return to zero acceleration nevertheless satisfied the fundamental law of cam design. (T/F)

True

The first step when designing a cam-follower linkage is to define the motion of the follower. (T/F)

True

The minimum transmission angle for a non-Grashof triple-rocker is always 0 deg. (T/F)

True

The position analysis solutions for the four-bar slider-crank and the four-bar crank-slider are very similar but the independent variables are different. For the slider-crank the actual independent variable is the slider position d. (T/F)

True

VBA is often referred to as a relative velocity. (T/F)

True

Velocity Analysis is the act of determining the translational and angular velocities of the parts in a linkage. (T/F)

True

We do position analysis so we can eventually analyze the accelerations of the linkage. (T/F)

True

When doing graphical position analysis of a 1 DOF all revolute 4-bar, you can determine the location and orientation of all links for a given input angle. (T/F)

True

When solving for the velocity of some random point on a 4-bar all revolute linkage, we generally assume that we have already done position analysis and solved for the coupler and rocker angular velocities. (T/F)

True

When we perform algebraic position analysis on the all revolute fourbar, we should expect two possible Bx values. (T/F)

True

When measuring the angles of our vectors in a vector loop, it is usually a good idea to measure the vector from its base/root. (T/F)

True By measuring each vector from its base/root, we can better ensure that the vector will move in the correct direction.

As stated in the livescribe, finding omega_3 and omega_4 is the first step in doing our velocity analysis. (T/F)

True In order to solve for the velocities of any given point on a linkage, you must first solve for the angular velocities of the actual links.

You can only have a positive transmission angle. (T/F)

True μ = |θ3-θ4|

For the alternate method of analytical velocity analysis, you use the following equation. Va = omega2 x Ra (T/F)

True In order to do the alternate method, you need to take the cross product.

Position analysis is necessary if we eventually want to be able to analyze the velocity or acceleration of the linkage. (T/F)

True. Once we can determine position, we can take the derivative to get velocity, then once again to get acceleration. We want to know accelerations so we can do a proper analysis of forces and therefore stresses on the linkage in the future.

If VA is 41 (in/sec) at an angle 206 (deg) and VB is 4 (in/sec) at an angle 71 (deg), what is the y-component of VBA (in/sec)?

V_bay = 4*sin(71) - 41*sin(206) = 20.97 in/sec