Module 8.4

Find the equation for the line that passes through the point (0,−1) and that is parallel to the line with the equation y−3=−3/4(x+1)y

y=−3/4x−1

Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates. slope: 0, ordered pair: (−5,−6)

y=−6

Write an equation for the line parallel to the line 2y=−5/2y=−5 through the point (3,−7)

y=−7

Graph the following equation by plotting two points. y+2=5(x−7)

1. Determine the slope =5 2. Find The Point 7,-2 3. Plot the point 7,-2 and go up 5 and over 1

Graph the following equation by plotting two points. y−6=−2/3(x−2)

1. The equation is given in point-slope form, y−y1=m(x−x1), where m is the slope and (x1,y1 is a point on the line. In order to graph y−6=−2/3(x−2) determine the slope. 2. Slope =-2/3 3. Find the point (2,6) 4. Plot the point

Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates. slope: 1/5 ordered pair: (4,−1)

1. Use point-slope formula 2. The point-slope form of the equation is y−(−1)=(15)(x−(4)) 3.y=1/5x-9/5 The slope-intercept form of the equation of a line is y=mx+b

Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates. slope: −3 ordered pair: (1,−5)

1. Use point-slope formula y−y1=m(x−x1) 2. y−(−5)=(−3)(x−(1) 3. y=−3x−2 The slope-intercept form of the equation of a line is y=mx+b

find the equation in slope-intercept form of the line passing through the points with the given coordinates.(−5,2),(8,2)

1. determine the slope of the line slope=0 2.Substitute the slope, 0, and the coordinates of one of the ordered pairs into the point-slope form of the equation of a line, y−y1=m(x−x1)) then, put the equation in slope-intercept form. y=2 3.

You were asked to find the equation, in slope-intercept form, of the line passing through the points corresponding to the ordered pairs (1,−1) and (−1,0).

1. determine the slope of the line using the coordinates of the given ordered pairs. slope=-1/2 2.Substitute the slope, −1/2, and the coordinates of the ordered pairs into the point-slope form of the equation of a line, y−(−1)=(−1/2)(x−(1)) 3. y=−1/2x−1/2

7x−6y=−4Find the slope of a line that is a) parallel and b) perpendicular to the given line.

Parallel 7/6 Perpendicular -6/7

ind the equation for the line that passes through the point (−3,2)and that is perpendicular to the line with the equation −2/3x−y=−8/3.

er:y=32x+132

Find the equation for the line that passes through the point (−2,2), and that is perpendicular to the line with the equation y=−4

x=−2