algebra 1B exam 9th grade review semester 1

product to a power

(x⁴y⁵)³ = x¹²y¹⁵

power to a power

(x⁵)³ = x⁵⁺³ = x¹⁵

for exponent properties 0=

1

8⁻²

1 1 -- -- 8² = 64

standard form

Ax+By=C

quotient of like bases

x⁵ − x³ = x⁵⁻³ = x²

point slope form

y-y1=m(x-x1)

exponential model equations

y=bⁿ y=a x bⁿ-c +d

slope intercept form

y=mx+b

linear model equations

y=mx=b Ax=By=C y-y1=m(x-x1)

what do you do when you have a negative exponent? IE: 8⁻²

you put a one over it and make the exponent positive "switch floors"

y=bⁿ

parent function

x¹ + x⁷ = x¹⁺⁷ = x⁸

product of like bases

y=a x bⁿ⁻c = d

transformation