algebra 1B exam 9th grade review semester 1
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product to a power
(x⁴y⁵)³ = x¹²y¹⁵
power to a power
(x⁵)³ = x⁵⁺³ = x¹⁵
for exponent properties 0=
1
8⁻²
1 1 -- -- 8² = 64
standard form
Ax+By=C
quotient of like bases
x⁵ − x³ = x⁵⁻³ = x²
point slope form
y-y1=m(x-x1)
exponential model equations
y=bⁿ y=a x bⁿ-c +d
slope intercept form
y=mx+b
linear model equations
y=mx=b Ax=By=C y-y1=m(x-x1)
what do you do when you have a negative exponent? IE: 8⁻²
you put a one over it and make the exponent positive "switch floors"
y=bⁿ
parent function
x¹ + x⁷ = x¹⁺⁷ = x⁸
product of like bases
y=a x bⁿ⁻c = d
transformation