ETA LEJATC YEAR 1 QUIZ 4 REVIEW

? is a threadable conduit that has a rubberized outside coating and is commonly installed in highly corrosive environments. a.Electrical metallic tubing b.Intermediate metal conduit c.Liquidtight flexible metal conduit d.PVC-coated rigid metal conduit

D

? is added to cement to start the chemical reaction that hardens the cement into concrete. a.Chlorine b.Hydrogen peroxide c.Sand d.Water

D

Aggregates and sand make up ? of concrete. a.10% b.20% c.55% to 65% d.75% to 80%

D

All hand benders include a hook, ? , handle, and foot pedal. a.back b.curve c.saddle d.shoe

D

Benders are manufactured to create a specific ? . a.bend angle b.bend type c.offset d.radius

D

If the actual stub length is less than the desired stub length (due to bender wear), the difference between the two stub lengths is ? . a.added to the take-up b.disregarded c.multiplied by 2 d.subtracted from the take-up

D

In order to place the bending mark in the correct position on the conduit, the take-up must first be subtracted from the ? . a.back-to-back distance b.conduit length c.gain d.stub length

D

The handles of a ? are opened and closed several times to provide a mechanical advantage, which can easily cut through thick-walled pipes. a.band saw b.hacksaw c.PVC saw d.ratchet cutter

D

To calculate shrink when bending offsets, the shrink constant is multiplied by the ? . a.bend angle b.conduit length c.gain factor d.height of the obstacle

D

When bending a 6-inch offset using 22.5° bends in 1-inch RMC, what multiplier (rounded to the nearest tenth) would be used to determine the distance between bends? a.1.4 b.1.73 c.2.0 d.2.6

D

When conduit is bent around an obstacle, the total length of the run is ? . a.expanded b.identical c.increased d.reduced

D

Use the multiplier method for three-bend saddles to solve this question. Determine the distance (D) between the center bend pencil mark (CB) and the outside bend pencil marks (OB) for a three-bend saddle that is bent with a center bend angle of 45° and has a rise (R) of 6.9 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

Distance (D) = Rise (R) × Multiplier for 22.5° bend using the three-bend multiplier = 6.9 × 2.5 = 17.25 ≈ 17.3 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of ½-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 23 inches.

Distance (D) = Stub - Bender Take Up = 23 - 5 = 18 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of ¾-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 25 inches.

Distance (D) = Stub - Bender Take Up = 25 - 6 = 19 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of 1-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 27 inches.

Distance (D) = Stub - Bender Take Up = 27 - 8 = 19 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of ½-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 30 inches.

Distance (D) = Stub - Bender Take Up = 30 - 5 = 25 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of ¾-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 30 inches.

Distance (D) = Stub - Bender Take Up = 30 - 6 = 24 inches

Determine the proper distance (D) of a pencil mark from the end of a piece of 1-inch EMT when the desired stub-up (Stub 1) length of a 90° bend is 33 inches.

Distance (D) = Stub - Bender Take Up = 33 - 8 = 25 inches

Identify the type of conduit body shown below. a.LB b.LL c.LR d.T

A

Identify the type of connector shown below. a.90° elbow b.90° pulling elbow c.Hub d.Set screw ***IT SHOWS A 90 DEGREE ELBOW***

A

The ? must always be the primary source of force used to bend conduit. a.foot pedal b.handle c.hickey d.hook

A

The ? side of a triangle is the side next to the reference angle and connected to the right angle. a.adjacent b.hypotenuse c.opposite d.right

A

The measured rise method does not require the Electrical Worker to fabricate conduit bends to a specific ? . a.angle b.distance multiplier c.offset rise d.radius

A

Three-bend saddles are made using the multiplier method and the ? method. a.center of bend b.center of obstruction c.edge of obstruction d.measured rise

A

When bending an 11-inch offset using 22.5° bends in 1-inch EMT, what multiplier (rounded to the nearest tenth) would be used to determine the distance between bends? a.2.6 b.2.9 c.3.9 d.6.0

A

Determine the distance (D) in inches between bends of an offset which will be bent using an angle of 30° and has a rise (R) of 9.9 inches. (Round your FINAL answer to two decimal places.)

Distance (D) = Rise (R) × Bend Multiplier = 9.9 × 2.0 = 19.8 ≈ 19.8 inches

? provides an excellent ground path and it can be bent with virtually no springback. a.Aluminum conduit b.Electrical metallic tubing c.PVC-coated rigid metal conduit d.Rigid nonmetallic conduit

A

A ? is a bend consisting of two offsets turned at a 90° angle from each other. a.corner offset b.kick c.three-bend saddle d.four-bend saddle

A

A ? is a conduit threader in which the die head is secured to the threader in a fixed position. a.non-ratcheting hand-driven threader b.power pony c.ratcheting hand-driven threader d.threading machine

A

A ? is a handheld power saw that has a flexible metal saw blade forming a continuous loop around two parallel pulleys. a.band saw b.hacksaw c.PVC saw d.ratchet cutter

A

A ? is a portable protective device capable of withstanding forces from a cave-in. a.shield b.shoring box c.soldier pile d.waler

A

A ? is used to establish and verify grades and elevations and to set up level points over long distances. a.builder's level b.leveling rod c.plumb bob d.transit level

A

A(n) ? box typically houses switches and receptacles. a.device b.outlet c.pull d.utility

A

A(n) ? is also called a crossover. a.three-bend saddle b.four-bend saddle c.five-bend saddle d.offset

A

? are manually-operated threading tools that require the arm strength of the Electrical Worker to turn the die around the conduit. a.Hand-driven threaders b.Mechanical threaders c.Power-driven threaders d.Threading machines

A

? are used when a conduit run needs to be placed on the adjoining wall of an inside or outside corner. a.Corner offsets b.Four-bend saddles c.Kicks d.90° stub-ups

A

? is produced when the bent conduit takes a shortcut by following the arc of the curve instead of following the straight distance into a corner. a.Gain b.Offset c.Shrink d.Take-up

A

? is the process of cutting back trench walls into a step pattern that reduces the chance of collapse into the work area. a.Benching b.Shielding c.Shoring d.Sloping

A

Cutting with ? is a messy process because large amounts of debris from the conduit and blade are left behind. a.abrasive saws b.band saws c.hacksaws d.ratchet cutters

A

? is a threadable conduit with an intermediate wall thickness compared to rigid metal conduit. a.Electrical metallic tubing b.Intermediate metal conduit c.PVC conduit d.Rigid nonmetallic conduit

B

? threads are used on conduit. a.British Standard Pipe (BSP) b.National Pipe Taper (NPT) c.National Pipe Taper Thread Fuel (NPTF) d.Special Unified National Thread Series (UNS)

B

A ? is also called a "diestock." a.die b.die head c.hand ratchet d.reamer

B

A common angle used to produce offsets in four-bend saddles is ? possibly because the distance multiplier is a simple whole number. a.22½° b.30° c.45° d.60°

B

A(n) ? box is also called a "J-box." a.joist b.junction c.pull d.utility

B

A(n) ? box is installed at an endpoint in an electrical system where current is supplied to utilization equipment. a.device b.outlet c.pull d.utility

B

A(n) ? is a cutting tool used to form external threads on the surface of conduit. a.band saw b.die c.oiler d.reamer

B

A(n) ? is an undesirable bend that is not in line with other bends in the same conduit. a.back-to-back b.dogleg c.offset d.shortcut

B

A(n) ? is any bend less than 90° that is used to change direction in a conduit run. a.hickey b.kick c.offset d.stub-up

B

Angles commonly used for bending offsets and saddles are 15°, 22½°, 30°, and ? . a.42½° b.45° c.60° d.90°

B

Surveyors often place corner stakes, known as ? , at each corner of a property. a.benchmarks b.hubs c.monuments d.property marks

B

The ? mark indicates the position of the conduit where the bend will begin to be formed. a.angle b.arrow c.shoe d.star

B

There should be no less than ? threads worth of contact between the conduit and fitting. a.3 b.5 c.7 d.10

B

Threading machines are available to thread conduit from ? . a.½" to 2" b.½" to 4" c.¾" to 2" d.¾" to 6"

B

When bending an 11 ¾-inch offset using 30° bends in ¾-inch RMC, what multiplier (rounded to the nearest tenth) would be used to determine the distance between bends? a.1.2 b.2.0 c.2.6 d.5.0

B

The first step in bending an offset is measuring the ? . a.bend angle b.offset distance c.offset rise d.shrink

C

The multiplier for a 30° bend angle is ? . a.1.41 b.1.50 c.2.00 d.2.61

C

The notch on a hand bender typically represents the center of a ? bend. a.22 1/2° b.30° c.45° d.90°

C

The offset rise measurement is multiplied by the multiplier value to get the length of the ? , or distance between bends in an offset. a.adjacent side b.cosine c.hypotenuse d.opposite side

C

The teeth on a ? are designed to efficiently cut plastic conduit with minimal heat build-up. a.band saw b.hacksaw c.PVC saw d.ratchet cutter

C

When bending a 4-inch offset using 10° bends in ¾-inch EMT, what multiplier (rounded to the nearest hundredth) would be used to determine the distance between bends? a.1.73 b.2.61 c.5.76 d.6.76

C

When choosing a bend angle, consider that a(n) ? bend angle takes up more room when rising over an obstacle. a.larger b.obtuse c.smaller d.tight

C

Where should the center bend pencil mark location be for a three-bend saddle if the distance from the fixed end to the center of the obstruction is 55 inches and the shrink is ¼ inch? a.54¾" b.55" c.55¼" d.56"

C

? cover the scope of work and allow for a planned strategy. a.Benchmarks b.Hubs c.Job specifications d.Work journals

C

? is a non-threadable conduit that is rustproof and commonly available in Schedule 40 and Schedule 80 wall thicknesses. a.Electrical metallic tubing b.Intermediate metal conduit c.PVC conduit d.Rigid metal conduit

C

A ? consists of a cone-shaped metal weight fastened to a string. a.builder's level b.leveling rod c.plumb bob d.transit level

C

A ? is a manual saw that is designed to hold various types of blades for cutting different materials. a.band saw b.dry cutting saw c.hacksaw d.ratchet cutter

C

A(n) ? angle is an angle that measures exactly 90°. a.acute b.offset c.right d.square

C

A(n) ? consists of a handle, grip, and head that remove the sharp edges on conduit. a.oil bucket b.oiler c.reamer d.threader

C

A(n) ? offset bend is an offset where the second bend is made with an angle that is too large and the end of the conduit rises relative to the top of the obstacle. a.closed b.dogleg c.open d.rising

C

After the bottom of a trench is filled with stone, the remainder of the trench is usually filled with ? . a.asphalt b.cement c.sand d.soil

C

An offset bend is a double conduit bend with two equal angles bent in ? direction(s). a.a 90° b.any c.opposite d.the same

C

Identify the type of conduit body shown below. a.LB b.LL c.LR d.T

C

The ? is the distance from the bottom of a conduit to the top of an obstruction. a.bend angle b.length c.rise d.width

C

The ? method for bending kicks treats the kick as an offset. a.center of bend b.measured rise c.multiplier d.shrink

C

The ? side of a triangle is the side opposite the reference angle. a.adjacent b.hypotenuse c.opposite d.reference

C

Use the multiplier method for three-bend saddles to solve this question. Consider a three-bend saddle with a center bend (CB) angle of 30° and a rise (R) of 6.7 inches. The distance from the center of the obstruction (CO) to the box the conduit will connect to is 27.9 inches. Determine the distance from the end of the conduit to the pencil mark that represents the center of the 30° bend (CM). (Round your FINAL answer to one decimal place.)

Center Mark Distance (CM) = Center Obstruction (CO) + (Rise (R) × Shrink Constant for 15° Bend) = 27.9 + (6.7 × 0.13) = 27.9 + 0.871 = 28.771 ≈ 28.8 inches

Determine the distance (D) between the bends of a compound 90° bend using 45° bends that are installed to avoid a round obstruction where the diameter (d) is 5 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

Distance (D) = Obstruction Diameter (d) × Distance Multiplier = 5 × 2.4 = 12 ≈ 12 inches

Determine the distance (D) in inches between bends of an offset which will be bent using an angle of 60° and has a rise (R) of 5.2 inches. (Round your FINAL answer to two decimal places.)

Distance (D) = Rise (R) × Bend Multiplier = 5.2 × 1.15 = 5.98 ≈ 5.98 inches

Determine the distance (D) in inches between bends of an offset which will be bent using an angle of 15° and has a rise (R) of 6.1 inches. (Round your FINAL answer to two decimal places.)

Distance (D) = Rise (R) × Bend Multiplier = 6.1 × 3.86 = 23.546 ≈ 23.55 inches

Determine the distance (D) in inches between bends of an offset which will be bent using an angle of 22.5° and has a rise (R) of 6.5 inches. (Round your FINAL answer to two decimal places.)

Distance (D) = Rise (R) × Bend Multiplier = 6.5 × 2.6 = 16.9 ≈ 16.9 inches

It can be assumed that the take-up value is the same for all benders of the same size. Select one: True False

False

Use the center of bend or push through method for three-bend saddles to solve this question.Determine the distance (D) between the center bend pencil mark (CB) and the outside bend pencil marks (OB) for a three-bend saddle that is bent on ¾" EMT (OD = 0.92") with a center bend angle of 45° and has a rise (R) of 4.2 inches. (Round your FINAL answer to one decimal place.)

Note: Be sure to add in the outside diameter of the selected conduit.Distance (D) = (Rise (R) × Multiplier for 22.5° bend) + Outside Diameter (OD) = (4.2 × 2.6) + 0.92 = 10.92 + 0.92 = 11.84 ≈ 11.8 inches

Consider a conduit that runs between two boxes. The distance between the boxes (BD) is 20.8 inches. A single 22.5° offset will be bent in the conduit with a rise (R) of 6.4 inches. Utilize a shrink constant of 0.2 to determine the overall conduit (OAC) length required to complete this run. (Round your FINAL answer to two decimal places.)

OAC = Box Distance (BD) + Total Shrink = 20.8 + (Rise × Shrink Constant) = 20.8 + (6.4 × 0.2) = 20.8 + 1.28 = 22.08 ≈ 22.08 inches

Consider a conduit that runs between two boxes. The distance between the boxes (BD) is 24.1 inches. A single 30° offset will be bent in the conduit with a rise (R) of 13.6 inches. Utilize a shrink constant of 0.27 to determine the overall conduit (OAC) length required to complete this run. (Round your FINAL answer to two decimal places.)

OAC = Box Distance (BD) + Total Shrink = 24.1 + (Rise × Shrink Constant) = 24.1 + (13.6 × 0.27) = 24.1 + 3.672 = 27.772 ≈ 27.77 inches

Consider a conduit that runs between two boxes. The distance between the boxes (BD) is 28.3 inches. A single 45° offset will be bent in the conduit with a rise (R) of 6.5 inches. Utilize a shrink constant of 0.41 to determine the overall conduit (OAC) length required to complete this run. (Round your FINAL answer to two decimal places.)

OAC = Box Distance (BD) + Total Shrink = 28.3 + (Rise × Shrink Constant) = 28.3 + (6.5 × 0.41) = 28.3 + 2.665 = 30.965 ≈ 30.97 inches

Consider a conduit that runs between two boxes. The distance between the boxes (BD) is 28.6 inches. A single 10° offset will be bent in the conduit with a rise (R) of 11.5 inches. Utilize a shrink constant of 0.087 to determine the overall conduit (OAC) length required to complete this run. (Round your FINAL answer to two decimal places.)

OAC = Box Distance (BD) + Total Shrink = 28.6 + (Rise × Shrink Constant) = 28.6 + (11.5 × 0.087) = 28.6 + 1.0005 = 29.6005 ≈ 29.6 inches

Determine the overall length (OAL) of a 1-inch EMT conduit with a total of two 90° bends. The finished dimensions of the conduit are 61.4 inches back-to-back (B2B) with the first stub length (Stub 1) of 13.0 inches and the second stub length (Stub 2) of 21.5 inches. The gain for your bender is 4.02 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

OAL = (Stub 1 - Bender Gain) + B2B + (Stub 2 - Bender Gain) = (13.0 - 4.02) + 61.4 + (21.5 - 4.02) = 87.86 ≈ 87.9 inches

Determine the overall length (OAL) of a ¾-inch EMT conduit with a total of two 90° bends. The finished dimensions of the conduit are 59.9 inches back-to-back (B2B) with the first stub length (Stub 1) of 14.8 inches and the second stub length (Stub 2) of 16.2 inches. The gain for your bender is 3.20 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

OAL = (Stub 1 - Bender Gain) + B2B + (Stub 2 - Bender Gain) = (14.8 - 3.20) + 59.9 + (16.2 - 3.20) = 84.5 ≈ 84.5 inches

Determine the overall length (OAL) of a 1-inch EMT conduit with a total of two 90° bends. The finished dimensions of the conduit are 51.9 inches back-to-back (B2B) with the first stub length (Stub 1) of 14.8 inches and the second stub length (Stub 2) of 12.4 inches. The gain for your bender is 3.89 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

OAL = (Stub 1 - Bender Gain) + B2B + (Stub 2 - Bender Gain) = (14.8 - 3.89) + 51.9 + (12.4 - 3.89) = 71.32 ≈ 71.3 inches

Determine the overall length (OAL) of a ¾-inch EMT conduit with a total of two 90° bends. The finished dimensions of the conduit are 66.6 inches back-to-back (B2B) with the first stub length (Stub 1) of 21.9 inches and the second stub length (Stub 2) of 14.2 inches. The gain for your bender is 3.32 inches. (Round your FINAL answer to the nearest tenth or one decimal place.)

OAL = (Stub 1 - Bender Gain) + B2B + (Stub 2 - Bender Gain) = (21.9 - 3.32) + 66.6 + (14.2 - 3.32) = 96.06 ≈ 96.1 inches

Determine the parallel offset adjustment (OA) with a bend of 10° and a distance between centerlines (CL) of 4 inches. (Round your FINAL answer to two decimal places.)

Offset Adjustment (OA) = Centerline (CL) × Shrink Constant = 4 × 0.0625 = 0.25 ≈ 0.25 inches

Determine the parallel offset adjustment (OA) with a bend of 45° and a distance between centerlines (CL) of 4 inches. (Round your FINAL answer to two decimal places.)

Offset Adjustment (OA) = Centerline (CL) × Shrink Constant = 4 × 0.375 = 1.5 ≈ 1.5 inches

Determine the total shrink (TS) of an offset with a bend angle of 10° and a rise (R) of 10.8 inches. (Round your FINAL answer to two decimal places.)

Total Shrink (TS) = Rise (R) × Shrink Constant = 10.8 × 0.0625 = 0.675 ≈ 0.68 inches

Determine the total shrink (TS) of an offset with a bend angle of 45° and a rise (R) of 10.9 inches. (Round your FINAL answer to two decimal places.)

Total Shrink (TS) = Rise (R) × Shrink Constant = 10.9 × 0.375 = 4.0875 ≈ 4.09 inches

Determine the total shrink (TS) of an offset with a bend angle of 30° and a rise (R) of 13.1 inches. (Round your FINAL answer to two decimal places.)

Total Shrink (TS) = Rise (R) × Shrink Constant = 13.1 × 0.25 = 3.275 ≈ 3.28 inches

Determine the total shrink (TS) of an offset with a bend angle of 22.5° and a rise (R) of 9.0 inches. (Round your FINAL answer to two decimal places.)

Total Shrink (TS) = Rise (R) × Shrink Constant = 9.0 × 0.1875 = 1.6875 ≈ 1.69 inches

Threads for conduit fittings are straight without a taper. Select one: True False

True