Exam 4 chem 1451
isobutyl
(CH3)2CHCH2-
tert-butyl
(CH3)3C-
Meth-
1 carbon
Prop-
3 carbons
Ethylene
Ethene
iodo
I-
Ester structure
RCOOR
phenolate (or phenoxide) ion
The conjugate bases of a phenol
aniline
benzenamine
alkynes
have at least one triple bond between carbon atoms.
-one
ketone suffix
propionic acid
propanoic acid CH3CH2COOH
Dec-
10 carbons
Eth-
2 carbons
But-
4 carbons
Pent-
5 carbons
Hex-
6 carbons
Hept-
7 carbons
Oct-
8 carbons
Non-
9 carbons
Complete combustion reaction
A reaction in which O2 is added to a compound containing carbon and hydrogen, producing CO2 and H2O
-al
Aldehyde suffix
Haloalkanes
Alkanes with halogen substituents
substituent
An atom or group of atoms attached to the parent chain in a molecule. A molecule can have one or more substituents.
bromo
Br-
isopropyl
CH(CH3)2
methyl
CH3
ethyl structure
CH3CH2
propyl
CH3CH2CH2
butyl
CH3CH2CH2CH2-
sec-butyl
CHCH2CH3- | CH3
carboxylic acid
COOH
weak organic acids
Carboxylic Acid and Phenol donate a proton (H+), acting as a Brønsted-Lowry acid.
chloro
Cl-
Incomplete combustion reaction
Combustion in which not enough oxygen is supplied to completely burn the fuel. Carbon monoxide is a common product.
When the two higher-priority groups are positioned in opposite directions
E-configuration.
Acetylene
Ethyne (C2H2)
fluoro
F-
Alkenes
Hydrocarbons with one or more carbon-carbon double bonds
constitutional isomers.
Molecules which have the same molecular formula but are different due to different atomic connectivity
Conformations
One important feature of a single bond is its ability to rotate around the bond. Different shapes that a single molecule can take on because of bond rotations are called • They have the same molecular formula. • They have the same atomic connectivity. • They look different because of the rotation of one or more single bonds.
Rules for Naming Alkenes (or Alkynes)
Step 1 Identify the parent chain and the substituent(s) in a molecule and their name. Find the longest carbon chain containing the double bond (or the triple bond), and name the compound by using the suffix -ene (or −yne). Indicate the position of the double bond by giving the number of the first alkene carbon and placing that number immediately before the parent name. If more than one double bond is present, indicate the position of each and use one of the suffixes -diene, −triene, (or −diyne, −triyne) and so on. Step 2: Number the carbon atoms in the parent chain. Begin at the end nearer the double bond (or the triple bond) or if the double (or triple) bond is equidistant from the two ends, begin at the end nearer the first branch point. This rule ensures that the double-bond (or triple-bond) carbons receive the lowest possible number. Step 3: Number the substituents according to their positions in the chain. Step 4: Write the name as a single word. List the substituents alphabetically.
Rules for Naming Alkanes with Substituents
Step 1 Identify the parent chain and the substituent(s) in a molecule and their name. In order to name branched alkanes, you need to understand the concepts of the parent chain and a substituent. • The parent chain is the longest continuous chain of carbon atoms in a molecule. Only one parent chain exists in a molecule. • A substituent is an atom or group of atoms attached to the parent chain in a molecule. A molecule can have one or more substituents. Step 2 Number the atoms in the parent chain. If there is one substituent, the parent chain is numbered to give the substituent the lower number. If there are two or more substituents, number the parent chain from the end that gives the lower number to the substituent encountered first. Step 3 Number the substituents. Assign the number to each substituent according to its point of attachment to the parent chain. If there are two substituents on the same carbon, give them both the same number. Step 4 Write the name as a single word. Construct the name of the alkane by placing the alkyl groups in alphabetical order and specifying their position numbers, followed by the name of the parent chain. The labels di, tri tetra, etc., are added if two or more identical substituents are present. Don't use these prefixes for alphabetizing purposes. Separate numbers by using a comma, and numbers from letters by using a hyphen. Also, the prefix iso- is not hyphenated and is used for alphabetizing purposes, but the hyphenated prefixes sec- and tert- are not used for alphabetizing purposes.
carboxylate ion
The conjugate bases of a carboxlyic acid
weak organic bases
The lone pair on the nitrogen atom of an amino group can accept a proton (H+). Therefore, an amine can act as a Brønsted-Lowry base
Hydrogenation
When a hydrogen molecule (H2) reacts with an alkene or an alkyne compound, hydrogen atoms are added to each of the carbon atoms in the double bond of an alkene or the triple bond of an alkyne, converting the double bond or the triple bond into a single bond. hydrogen molecule acts as a reducing agent to reduce the alkene or alkyne to an alkane.
cis-configuration.
When the two alkyl groups are positioned in the same direction,
Z-configuration.
When the two higher-priority groups are positioned in the same direction,
Alkanes
a hydrocarbon containing only single covalent bonds
-ol
alcohol suffix
-amide
amide suffix
amine suffix
amine
Amine Salts
amines are bases, their reaction with an acid produces a salt
Cycloalkane
an alkane that is a ring or cyclic structure
Condensed Structural Formula
another way to write a large organic molecule.
wedge and dash notation
applied to organic compounds to represent a three-dimensional structure. Recall that a solid wedge is a bond coming out of the paper toward you and the dashed wedge is a bond behind the paper away from you. The solid line represents a bond that lies on the paper.
butyric acid
butanoic acid CH3CH2CH2COOH
methanetriyl group
carbon atom with exactly one attached hydrogen atom and three single bonds
methyl group
carbon atom with exactly three attached hydrogen atoms and one single bond
methylene bridge (methanediyl group)
carbon atom with exactly two attached hydrogen atoms and two single bonds
-oic acid
carboxylic acid suffix
alcohol
compound must be bonded to the hydroxyl (−OH) group
thiol
compound must be bonded to the the sulfhydryl (-SH) group
unsaturated hydrocarbons
contain double and/or triple bonds between carbon atoms. alkenes, alkynes, and arenes
Saturated hydrocarbons
contain only single bonds between carbon atoms Alkanes
Amide
derivative of a carboxylic acid in which the "-OH" of the carboxylic acid group is replaced with an "-NH2" group.
Ester
derivative of a carboxylic acid in which the "-OH" of the carboxylic acid group is replaced with an alkyl group.
Geometric Isomers of Alkenes
double bonds cannot rotate. The lack of rotation around the carbon-carbon double bond has the potential to. When identical groups are attached to a carbon atom on either side of a double bond, then are not possible. The Cis and Trans Notation. The E and Z Notation.
-oate
ester suffix
acetic acid
ethanoic acid CH3COOH
ether suffix
ether
primary alcohol
first oxidized to aldehyde, and then is further oxidized to a carboxylic acid.
Arenes (or aromatic compounds or aromatics)
hydrocarbons that are based on a benzene molecule. (Rings)
Phenol
hydroxybenzene
formic acid
methanoic acid HCOOH
Toluene
methylbenzene
Primary (1°) amine
nitrogen of an amino group bears only one alkyl group
Tertiary (3°) amine
nitrogen of an amino group bears three alkyl group
Secondary (2°) amine
nitrogen of an amino group bears two alkyl group
Hydrocarbons
organic molecules consisting of only carbon and hydrogen
secondary alcohol
oxidized to a ketone.
Oxidation of Alcohol
primary and secondary alcohols can be oxidized. occurs by removing one H atom from the hydroxyl (-OH) group and another H atom from the C atom bearing the -OH group. A tertiary alcohol cannot because no hydrogen atoms are connected to the carbon atom bearing the hydroxyl group.
condensation reaction
process in which two molecules are joined together by removing a small molecule (typically H2O).
Amide Formation Reactions (Amidation)
produced when a carboxylic acid reacts with ammonia or with an amine and eliminates a water molecule Because an amine (or ammonia) is a base, a reaction between a carboxylic acid and an amine (or ammonia) is an acid-base reaction and results in ammonium salt.
Structural Formula
shows all the bonds and atoms of the molecules.
numbering a carbon chain
smaller number is assigned alphabetically to the first substituent.
functional groups
specific arrangement of atoms in a molecule. It confers a molecule with particular physical and chemical properties.
Organic compounds
substances composed of carbon and hydrogen and a few other elements including nitrogen, oxygen, and sulfur. The simplest organic compound is methane (CH4).
The parent chain
the longest continuous chain of carbon atoms in a molecule. Only one exists in a molecule.
primary (1°) alcohol
the one alkyl group bonded to the carbon atom bearing the -OH group.
E and Z Notation
the positions of higher priority groups are compared instead of the positions of alkyl groups. higher priority is assigned to a longer alkyl group.
Molecular Formula
the simplest method to describe a molecule. It describes the types and the number of constituent atoms. For example, C3H8O. The formula describes that the molecule is made of three carbon atoms, eight hydrogen atoms and one oxygen atom.
tertiary (3°) alcohol
the three alkyl groups bonded to the carbon atom bearing the -OH group.
secondary (2°) alcohol
the two alkyl groups bonded to the carbon atom bearing the -OH group.
thiol suffix
thiol
trans-configuration.
two alkyl groups are positioned in opposite directions
Ester Formation Reaction (Fischer Esterification)
when a carboxylic acid and an alcohol react in the presence of an acid catalyst and eliminate a water molecule.
cis and trans notation
will not work when more than two alkyl groups are attached to a double bond
Line-Angle Formula (or Skeletal Formula)
• Covalent bonds are represented by lines. • Carbon atoms are not shown. You need to assume that a carbon atom appears where lines (bonds) meet and at the end of each line. • Hydrogen atoms are drawn only when attached to atoms other than carbon. • You need to assume that a hydrogen atom appears to give each carbon its required four bonds. • Draw explicitly all heteroatoms (atoms that are not carbon and hydrogen) and the hydrogen atoms directly attached to heteroatoms. • A double bond and a triple bond must be drawn as a double bond and a triple bond.