5.5 Write an equation of a line that passes thru the given point and is parallel to the given line
y = mx + b
Slope-intercept form of an equation of a line is
m = (y2-y1) / (x2-x1)
slope formula is
0
slope of a horizontal line is
undefined
slope of a vertical line is
y = 7
equation of horizontal line through (-2, 7)
x = 3
equation of line parallel to x = -1 through (3, 11)
y = 5
equation of line parallel to y=4 through (8, 5)
y = 11
equation of line perpendicular to x = -1 through (3, 11)
x = 8
equation of line perpendicular to y=4 through (8, 5)
y = -(1/2)x + (7/2)
equation of line through (7, -1) and (-1, 3)
y=x+5
equation of line thru (-1,4) and perpendicular to y=-x-4
y=3x-4
equation of line thru (1,-1) and parallel to y=3x+2
y=(2/5)x-(2/5)
equation of line thru (2,0) and perpendicular to y=-5x+3
y=-4x+7
equation of line thru (4,-9) and perpendicular to y=(1/4)x+2
y=5x-13
equation of line thru (4,7) and parallel to y=5x-3
y=(2/3)x-(10/3)
equation of line thru (5,0) and parallel to y=(2/3)x-4
y = (3/4)x - 3
equation of the line with x-intercept 4 and y-intercept -3
y = 2x + 7/2
equation of the perpendicular bisector of AB given A(1, 3) and B(-1, 4)
y = -(1/2)x + 17/2
equation of the perpendicular bisector of AB given A(2, 5) and B(4, 9)
x = -2
equation of vertical line through (-2, 7)