5.5 Write an equation of a line that passes thru the given point and is parallel to the given line

y = mx + b

Slope-intercept form of an equation of a line is

m = (y2-y1) / (x2-x1)

slope formula is

0

slope of a horizontal line is

undefined

slope of a vertical line is

y = 7

equation of horizontal line through (-2, 7)

x = 3

equation of line parallel to x = -1 through (3, 11)

y = 5

equation of line parallel to y=4 through (8, 5)

y = 11

equation of line perpendicular to x = -1 through (3, 11)

x = 8

equation of line perpendicular to y=4 through (8, 5)

y = -(1/2)x + (7/2)

equation of line through (7, -1) and (-1, 3)

y=x+5

equation of line thru (-1,4) and perpendicular to y=-x-4

y=3x-4

equation of line thru (1,-1) and parallel to y=3x+2

y=(2/5)x-(2/5)

equation of line thru (2,0) and perpendicular to y=-5x+3

y=-4x+7

equation of line thru (4,-9) and perpendicular to y=(1/4)x+2

y=5x-13

equation of line thru (4,7) and parallel to y=5x-3

y=(2/3)x-(10/3)

equation of line thru (5,0) and parallel to y=(2/3)x-4

y = (3/4)x - 3

equation of the line with x-intercept 4 and y-intercept -3

y = 2x + 7/2

equation of the perpendicular bisector of AB given A(1, 3) and B(-1, 4)

y = -(1/2)x + 17/2

equation of the perpendicular bisector of AB given A(2, 5) and B(4, 9)

x = -2

equation of vertical line through (-2, 7)