Algebra II: Solving Equations
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Use an algebraic equation to solve the problem. A rectangle is 3 times as long as it is wide. The perimeter is 60 cm. Find the dimensions of the rectangle. Round to the nearest tenth if necessary.
A. 7.5 cm by 22.5 cm
-5y-9 = -(y-1)
B. -2 1/2
Solve the equation. 3y+20 = 3+2y
D. -17
Is the following always, sometimes, or never true? 14 + 3x - 7 = 7x + 7 - 4x
A. always
Solve the equation or formula for the indicated variable. s = 5r^2t, for t
D. t= s/5r^2
