Chemistry: Units 7.3-7.4

Mc Mass to Mole: 11.2g NaCl x 1mol NaCl / 58.5g NaCl

0.191 moles of NaCl

Mass to Moles for Calcium Hydroxide: Hydrogen

0.675 g H x (1 mol H / 1.01 g H) = 0.668 mol H

MC Mole to Particles: 0.191 mol NaCl x (6.02 x 1023 / 1mol)

1.15 x 1023

Mass to Moles for Calcium Hydroxide: Oxygen

10.8 g O x (1 mol O / 16.0 g O) = 0.675 mol O

Mass to Moles for Calcium Hydroxide: Calcium

13.5 g Ca x (1 mol Ca / 40.1 g Ca) = 0.337 mol Ca

MC Mole to Mass: 2.50mol NaCl x (58.5g NaCl/ 1 mol NaCl)

146g NaCl

%C for H2O elements: Oxygen

16.00/ 18.02 x 100= 88.79

%C Example 1: molar mass of H2O

18.02 g/mol

Calcium Hydroxide: 0.668 mol H / 0.337 (Ca)

2.00 mol H

Calcium Hydroxide: 0.675 mol O / 0.337 (Ca)

2.00 mol O

%C for H2O elements: Hydrogen

2.02/18.02 x 100= 11.21

%C of Calcium Nitrate Ca(NO3)2: %Nitrogen

28.02/164.10 x 100= 17.08

MF of vitamin C (C3H4O3): Molar Mass C

3(12.0)= 36.0

MF of vitamin C (C3H4O3): Molar Mass O

3(16)= 48.0

Mass of vitamin C (C3H4O3): Add up the Molar Masses

36.0+48.0+4.04= 88.04 (round to 88.0)

MF of vitamin C (C3H4O3): Molar Mass H

4(1.01)= 4.04

%C of Calcium Nitrate Ca(NO3)2: %Calcium

40.08/164.10 x 100= 24.42

Empirical Formula of AgNO3

63.50% Ag 8.25% N 28.25% O

%C of Calcium Nitrate Ca(NO3)2: %Oxygen

96.00/164.10 x 100= 58.50

MF of vitamin C (C3H4O3): 2 x C3H403

C6H8O6

Molar Mass of Ca(NO3)2

Ca(NO3)2 = 40.08 + 28.02 + 96.00 = 164.10

Molar Mass Ca(NO3)2: Calcium

Ca= 40.08 x 1 = 40.08 g/mol

Molecular Formula: MF

Gives the total # of atoms in each element in a molecule

%C Formula

Molar Mass of element/Mass of compound x 100

Molar Mass Ca(NO3)2: Nitrogen

N = 14.01 x 2 = 28.02 g/mol

Molar Mass Ca(NO3)2: Oxygen

O = 16.00 x 6 = 96.00 g/mol

Percent Composition: %C

Tells you which types of atoms (elements) are present in a molecule and their levels.

Empirical Formula

The ratio of elements in the compound, but not the number of atoms in the molecule.

Molar Conversion: MC

Uses the molar mass to find the total moles in a compound.