HTrig Chapter 2 Review

Evaluate cos 375 degrees

(sqrt2 + sqrt6)/4 OR (1 + sqrt3)/(2sqrt2)

Evaluate sin 195 degrees

(sqrt2 - sqrt6)/4

Evaluate Given tan u = 3/4 where pi < u < (3pi)/2 Find sin (u/2)

+(3sqrt10)/10

Evaluate cos 157.5 degrees

-(sqrt (2 + sqrt2))/2

Evaluate Given sin alpha = -5/13 where pi < alpha < (3pi)/2 & cos beta = 12/13 where (3pi)/2 < beta < 2pi Find sin (alpha - beta)

-120/169

Simplify cos 3x - cos x

-2sin 2x sin x

Evaluate tan (13pi)/12

2 - sqrt3 OR (-1 + sqrt3)/(sqrt3 + 1)

Simplify 6cos (alpha) sin (4alpha)

3(sin (5alpha) + sin (3 alpha))

Simplify the expression sqrt(9+x^2) when x=3tan theta

3sec theta

Evaluate If sin theta = 4/5 where pi/2 < theta < pi a. sin (2theta) b. cos (2 theta) c. tan (2 theta)

a. -24/25 b. -7/25 c. 24/7

Solve on the interval [0, 2pi) 2sin^2 (phi) + 3sin(phi) = -1

phi = (7pi)/6, (3pi)/2, (11pi)/6

Simplify 2sin (theta) cos^3 (theta) + 2 sin^3 (theta) cos (theta)

sin (2theta)

Solve on the interval [0, 2pi) 3cot (2x) = -3

x = (3pi)/8, (7pi)/8, (11pi)/8, (15pi)/8

Solve on the interval [0, 2pi) sin (2x) - sin x = 0

x = 0, pi/3, pi (5pi)/3

Solve on the interval [0, 2pi) cos^2 x - sin^2 x = -1

x = pi/2, (3pi)/2

Solve on the interval [0, 2pi) sec^2 x - 2tan^2 x = 0

x = pi/4, (3pi)/4, (5pi)/4, (7pi)/4