Solving Linear-Quadratic Systems Assignment 100% (+Quiz [Different Quizzes For All] 100%)

Solve this system of equations algebraically: y - 10 = 11x + x2 y - 12x = 30 The first solution is (-4, -18). The second solution is ( , ).

(5,90)

Assignment

(All questions you will encounter)

Quiz

(Some questions you may encounter)

Solve this system of equations algebraically: y + x = 19 - x2 x + y = 80 1. Isolate one variable in the system of equations.y = -x2 - x + 19 y = -x + 802. Use substitution to create a one-variable equation.-x + 80 = -x2 - x + 193. Solve to determine the unknown variable in the equation. The system has _ real number solution(s).

0

The first two steps in determining the solution set of the system of equations, y = x2 - 2x - 3 and y = -x +3, algebraically are shown in the table. Which represents the solution(s) of this system of equations? (3, 0) and (-2, 5) (-6, 9) and (1, 2) (-3, 6) and (2, 1) (6, -3) and (-1, 4)

A. (3, 0) and (-2, 5)

The first two steps in determining the solution set of the system of equations, y = x2 - 6x + 12 and y = 2x - 4, algebraically are shown in the table. Which represents the solution(s) of this system of equations? (4, 4) (-4, -12) (4, 4) and (-4, 12) (-4, 4) and (4, 12)

A. (4, 4)

Consider this system of equations: y = x2 y = x + k For which value of k does the system have no real number solutions? For which value of k does the system have one real number solution? For which value of k does the system have two real number solutions?

A. -2 C. -0.25 D. 2

Jordan is solving this system of equations: y = 2x2 + 3 and y - x = 6. Which statements are true about Jordan's system? Check all that apply. The quadratic equation is in standard form. Using substitution, the system of equations can be rewritten as 2x2 - x - 3 = 0. There are two real number solutions. There are no real number solutions. A solution of the system of equations is (-1, 1.5).

A. The quadratic equation is in standard form. B. Using substitution, the system of equations can be rewritten as 2x2 - x - 3 = 0. C. There are two real number solutions.

Which systems of equations have no real number solutions? Check all that apply. y = x2 + 4x + 7 and y = 2 y = x2 - 2 and y = x + 5 y = -x2 - 3 and y = 9 + 2x y = -3x - 6 and y = 2x2 - 7x y = x2 and y = 10 - 8x

A. y = x2 + 4x + 7 and y = 2 C. y = -x2 - 3 and y = 9 + 2x D. y = -3x - 6 and y = 2x2 - 7x

Which represents the solution(s) of the graphed system of equations, y = x2 + 2x - 3 and y = x - 1? (1, 0) and (0, -1) (-2, -3) and (1, 0) (0, -3) and (1, 0) (-3, -2) and (0, 1)

B. (-2, -3) and (1, 0)

Which represents the solution(s) of the graphed system of equations, y = x2 + x - 2 and y = 2x - 2? (-2, 0) and (0, 1) (0, -2) and (1, 0) (-2, 0) and (1, 0) (0, -2) and (0, 1)

B. (0, -2) and (1, 0)

One of the solutions of the system of equations shown in the graph has an x-value of -4. What is its corresponding integer y-value? -1 -3 0 3

B. -3

David wants to find the solutions of this system of equations: -4x - 7 = y x2 - 2x - 6 = y Which statement is true? There are no real number solutions. There is one unique real number solution at (-1, -3). There is one unique real number solution at (1, -3). There are two real number solutions at (-1, -3) and (1, -7).

B. There is one unique real number solution at (-1, -3).

Which represents the solution(s) of the system of equations, y = -x2 + 6x + 16 and y = -4x + 37? Determine the solution set algebraically. (3, 25) (-3, 49) (3, 25) and (7, 9) (-3, 49) and (-7, 65)

C. (3, 25) and (7, 9)

Which graph most likely shows a system of equations with no solutions?

C. (U with / under it, not touching)

Use the graphing calculator to locate the solutions of this system of equations: y = x2 + x - 2 y = -x + 1 What are the solutions? (-3, 4) and (0,1) (-3, 4) and (-1,0) (3, -4) and (1,0) (-3, 4) and (1,0)

D. (-3, 4) and (1,0)

Which graph most likely shows a system of equations with two solutions?

D. (n with / going through it)

Which represents the solution(s) of the system of equations, y = x2 - 4x - 21 and y = -5x - 22? Determine the solution set algebraically. (-1, -17) (1, -27) (-1, -17) and (1, -27) no solutions

D. no solutions

Which parabola will have one real solution with the line y = x - 5? y = x2 + x - 4 y = x2 + 2x - 1 y = x2 + 6x + 9 y = x2 + 7x + 4

D. y = x2 + 7x + 4

Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and the other is quadratic-without graphing the system of equations.

Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.