Sets, functions and counting

Pataasin ang iyong marka sa homework at exams ngayon gamit ang Quizwiz!

How many 10 diget license plates can you make with no repetition from the numbers {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}?

10!

How many ways can you make a 10 diget license plate from the numbers {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}?

10^10

How many ways can you make a 6 diget license plate from the numbers {0, 1, 2, 3, 4, 5, 6, 7 ,8, 9}?

10^6

A coach must choose five starters from a team of 12 players. How many different ways can the coach choose the starters?

12C5

How many 5 diget numbers with exactly one 3?

1x9x9x9x9=9^4=6,561

How many 6 diget license plates have exactly one 4? With repetition and range from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

1x9x9x9x9x9=9^5=59,049 multiply by 6 places=59,049x6=354,294

In how many ways can 3 different vases be arranged on a tray?

3!=3x2x1=6

How many ways to get a straight hand (same suit in order)?

4 suits 10 cards choose a suit =4C1 choose 5 cards from that suit 10C5

How many flush suits (all the same suit)?

4 suits 13 cards in each suit choose a suit 4C1 then choose 5 cards from that suit 13C5 4C1x13C5

How many different 4 letter words can be formed from the letters in the word MATH ?

4x3x2x1=24

How many 5 card poker hands are there?

52C5 = 2,598,960

If you have 6 distinct apples how many ways can you put them in 5 boxes?

5x5x5x5x5x5=5^6

How many 5 diget numbers have no 3's?

8x9x9x9x9=8x9^4=52,488

How many 5 diget numbers are there?

9x10x10x10x10=90,000

How many 5 diget numbers with at least one 3?

9x10x10x10x10=90,000 8x9x9x9x9=52,488 90,000-52,488=37,512

Domain

Set of all first coordinates

Codomain

Set of all possible outcomes

Range

Set of all the actual outcomes

How many poker hands with at least one 3?

count ones with no 3's= 48C5 total amount minus 48C5= 52C5-48C5 =886,656

nC1

n

nP1

n

nPn

n!

Combination Formula

nCr=n!/r!(n-r)!

Permutation Formula

nPr=n!/r!

How many hands with exactly 3?

out of 4 (3's) choose 1= 4C1 for the rest choose 4 out of 48 =48C4 multiply 4C1x48C4

How many hands with exactly two 3's?

out of 4(3's) choose 2=4C2 for the rest choose 3 out of 48 = 48C3 4C2 x 48C3

Why do we study functions?

to analyze the relationships between functions

How many domains are in a function?

1

nCn

1

There are fourteen juniors and twenty-three seniors in the Service Club. The club is to send four representatives to the State Conference. If the members of the club decide to send two juniors and two seniors, how many different groupings are possible?

Choose 2 juniors and 2 seniors 14C2x23C2

There are fourteen juniors and twenty-three seniors in the Service Club. The club is to send four representatives to the State Conference. How many different ways are there to select a group of four students to attend the conference?

Choose 4 students from the total number of students. Order is not important. 37C4

Selecting three students to attend a conference in Washington, D.C. permutation or combination?

Combination, order doesn't matter

A teacher is making a multiple choice quiz. She wants to give each student the same questions, but have each student's questions appear in a different order. If there are twenty-seven students in the class, what is the least number of questions the quiz must contain?

If there were two questions on the quiz, we could prepare two quizzes with the questions in different order -- 2•1 = 2. If there were three questions, we could get 3•2•1 = 6 different orders. If there were four questions, we could get 4•3•2•1 = 24 different orders -- not quite enough for the class of 27 students. If there were five questions, we could get 5•4•3•2•1 = 120 different orders. The teacher will need at least 5 questions on the quiz.

Permutation

Order DOES matter

Assigning students to their seats on the first day of school. Combination or permutation?

Permutation

Selecting a lead and an understudy for a school play. Combination or permutation?

Permutation

Function

Relationship between two quantities First coordinate appears only once Every first element is assigned a second


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