Connect HW Questions

the test stat for the JB test for normality follows the chi square distribution with degrees of freedom equal to

2

A binomial experiment is a series of n independent trials of a random experiment where each trial has

2 possible outcomes

A chi square test of a contingency table is a test of independence for...

2 qualitative variables

when testing if two populations differ, we use a

2 tailed test

In order to determine if there is a difference between the means of 3 or more populations we use ...

ANOVA

For a goodness of fit test for normality, the null and alt hypotheses are...

H0: data are normal HA: data are not normal

When testing if two population proportions differ, the competing hypotheses are

H0: p1-p2=0 vs HA: p1-p2 does not equal 0

As compared to Fisher's LSD method, _______ is more powerful multiple comparison technique

Turkey's HSD method

statistical inference concerning the mean difference based on matched pairs sampling requires one of 2 conditions

both x1 and x2 are normally distributed; the sample size n >or equal to 30

matched pairs sampling is an example of

dependent sampling

Suppose the competing hypotheses for a test are H0: muD greater than or = to 0 vs HA: muD < 0. If the value of the test stat is -1.6 and the critical value at the 5% sig level is -1.711, then the correct conclusion is:

do not reject the null; -1.6 > -1.711

Turkey's HSD method ensures that the probability of a type 1 error equals alpha

for any # of pairwise comparisons

In a binomial experiment the probability of success is ____ and the probability of failure is ____.

p, 1-p

In anova testing, if the ratio of the between treatment variability to within treatment variability is significantly greater than one, then we

reject the null hypothesis and conclude that not all population means are equal

The point estimate for the difference between two population means is represented by the difference between two

sample means

A 95% confidence interval for the mean difference mud is 1.5 +- .5, indicating that at the 5% significance level, the mean difference is

significant and the mean difference differs from zero

A binomial experiment is a series of n identical trials of a random experiment where each trial has two possible outcomes, labeled _____.

success and failure

One of the disadvantages of Fisher's least difference (LSD) method is that the probability of a committing a_____

type 1 error increases as the number of pairwise comparisons increases

In most applications, the hypothesized difference between 2 population means is ...

0

In a 2 way ANOVA without interaction, we partition the Toal sum of squares SST into _____ distinct components.

3

For the chi square test for normality, the expected frequencies for each interval must be:

5 or more

Consider a Jarque Bear test for normality with a null hypothesis of H0: S=0 and K=0. The value of the test statistic is 3.75 with a p value of .1534. At the 5% sig level, the correct decision is to...

Do not reject H0; we conclude that the data follow a normal distribution (.1534>.05 so don't reject)

The competing hypotheses for a one way anova test that compares the means of three populations are defined as

H0: mu1=mu2=mu3 HA: not all population means are equal

For a matched pairs test, the null and alt hypotheses to test whether the mean difference muD differs from a given hypothesized value d0 are...

H0: muD=d0 HA:muD does not equal d0

What are the competing hypotheses if it was thought that the proportion in group 1 watched TV 20% more than those in group 2

H0: p1-p2 less than equal to .20 HA: p1-p2 > .20

the hypotheses for a statistical test of independence are...

H0: the 2 classifications are independent HA: the 2 classifications are dependent

At the 5% significance level, can we conclude that the row means differ?

No because .0939 > .05

A multinomial experiment can set each population proportion equal to a different predetermined hypothesized value so long as the population proportions sum to one (t/f)

TRUE

Which is not a chi square test for normality?

The Kruskal Wllis test

a matched pairs sample looks to find

a natural pairing between one observation in the first sample and one observation I the second sample

Which of the following is NOT used to analyze two qualitative variables

a t(df) test comparing two means (used for quantitative variables)

in one way ANOVA, between treatments variability is based on

a weighted sum of squares differences between the sample means and the grand mean

a multinomial experiment is a generalization of a ...

binomial experiment

In a goodness of fit test for normality the test stat follows the

chi square distribution

independent random samples are

completely unrelated to one another

A test of independence is also called a chi square test of a

contingency table

Suppose the competing hypotheses for a test are H0: MUd=0 vs HA: mud does not equal 0. if the p value for the hypothesis test is .065 and the chosen level of significance is .05, then the correct conclusion is :

do not reject the null; the mean difference does not differ from zero (.065>.05)

Consider a goodness of fit yes for normality with a null hypothesis of H0: data is normal with mu=10 and sigma=2. The value of the test stat is 4.34 and its p value is .1142. At the 5% sig level, the correct decision is to...

don't reject the null; conclude that the data follows a normal distribution with mu=10 and sigma=2

Suppose you want to perform a test to compare the mean GPA of all freshman with the mean GPA of all sophomores in a college. What type of sampling is required for this test?

independent sampling with quantitative data

the test stat for the goodness of fit test for normality follows the chi square distribution with df equal to ______, where k is the number of categories of the frequency distribution.

k-3

for matched pairs sampling, the parameter of interest is referred to as the

mean difference

A one way analysis of variance (ANOVA) test compares population ______ based on one categorical variable or factor

means

In a customer service survey the service is rated as excellent, good, fair, or poor. This survey is an example of a

multinomial experiment

In a 2 way ANOVA, if units within each block are randomly assigned to each of the treatments then the design of the experiment is referred to as the

random block design

performing a one way anova instead of performing a series of two sample t test, ______ the risk of incorrectly rejecting the null hypothesis

reduces

Consider a multinomial experiment with a null hypothesis of H0: p1=.4, p2=.1, p3=.35,p4=.15. The value of the test statistic is 9.65 and its p value is .0218. At the 5% sig level, the correct decision is to...

reject null; conclude that not all population proportions are equal to their hypothesized values

Which of the following are assumed for performing a one way anova?

the samples are selected independently the populations are normally distributed the population standard deviation are unknown but assumed equal

For a multinomial experiment, which of the following is NOT accurate?

there are a series of n dependent trials

in a one way anova, within treatments variability is based on a

weight sum of the samples variance of each treatment