RATIONAL EQUATIONS

What are two possible solutions that would make the bottoms zero or extraneous in this problem? m/m+1 + 5/m-1 = 1

-1 (-1+1=0) and 1 (1-1=0)

LCD stands for

Least common denominator

Which solution is the extraneous solution in this problem? 4/k²-8k+12 = k/k-2 + 1/k-6

6 is the extraneous solution

If you cancel out both solutions because they are extraneous, what is the answer to your problem?

No solution

What is the solution to 1/x-2 + 1/x+2 = 4/(x-2)(x+2) ? Are there any extraneous solutions?

No solution // yes, x=2 and 2-2 = 0

To get the solution(s) from factors, what do you do?

Set them equal to zero and get x by its self

What is the LCD for 6/x+2 + 5/x-2 = 20/x²-4 ?

The LCD is (x-2)(x+2)

What is the LCD for this problem? 3/5x + 7/2x = 1

The LCD is 10x.

What is the LCD for this equation? 4/x − 7/3x = 2/5 ?

The LCD is 15x.

How do you check for extraneous solutions?

You plug in the solutions to x into the x in the denominator. If the answer is equal to zero, then it is an extraneous solution

What is the LCD for 5k/k+2 + 2/k = 5 ?

k(k+2)

What is the solution to x/x-2 = 2/5

x= -4/3

What is the solution to 5/2x-1 − 7/3x+2 = 9/6x² +x-2 ? Are there any extraneous solutions?

x=-3 // no

What is the solution to 3x/8 + 1/2 = x/4 + 2 ?

x=12

What solution would make the bottom extraneous or equal to zero 8 + 6/x-5 = x-13/x-5 ?

x=5 (5-5=0)