Number Properties

अब Quizwiz के साथ अपने होमवर्क और परीक्षाओं को एस करें!

To estimate the root of an imperfect square

compare the two nearest perfect squares on either side

A number is a perfect square, if its prime factorization

contains only even powers of primes

A number is a perfect cube, if its prime factorization

contains only primes whose powers are multiples of 3

How to find the sum of consecutive integers:

1. Average the first and last to find the mean. 2. Count the number of terms. 3. Multiply the mean by the number of terms.

All evenly spaced sets are fully defined if: 1. _____ 2. _____ 3. _____ are known.

1. The smallest or largest element 2. The increment 3. The number of items in the set

2^(1/2) = approximately

1.4

√2≈

1.4

3^(1/2) = approximately

1.7

√3≈

1.7

121^(1/2) =

11

169^(1/2) =

13

196^(1/2) =

14

256^(1/2) =

16

5^(1/2) = approximately

2.25

6^(1/2) = approximately

2.45

7^(1/2) = approximately

2.65

Fewer factors, more multiples.

Any integer only has a limited number of factors. By contrast, there is an infinite number of multiples of an integer

Creating Remainders

Dividend = Quotient * Divsor + Remainder (from X / N = Q + R / N)

Divisible by 6

Divisible by 2 AND 3

The prime factorization of a perfect square contains only ______ powers of primes.

EVEN

The prime factorization of a perfect SQUARE contains only ____ powers of primes.

Even (90^2 = 2^2 3^4 5^2

In an evenly spaced set, the ____ and the ____ are equal.

In an evenly spaced set, the average and the median are equal.

In an evenly spaced set, the mean and median are equal to the _____ of _________.

In an evenly spaced set, the mean and median are equal to the average of the first and the last number.

Divisible by 4

Last 2 digits divisible by 4 or 2 twice

Divisible by 2

Last Digit is even

Divisible by 10

Last digit 0

Divisible by 5

Last digit 0 or 5

How to solve: If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer n for which 3ⁿ is a factor of p? (a) 10 (b) 12 (c) 14 (d) 16 (e) 18

Look at the numbers from 1 to 30, inclusive, that have at least one factor of 3 and count up how many each has: 3-1; 6-1; 9-2; 12-1; 15-1; 18-2; 21-1; 24-1; 27-3; 30-1 The answer is C. 14.

Divisible by 3

Sum of Digits divisible by 3

LCM

The smallest multiple of two or more integers (Product of all integers in Venn) (Add Fractions)

How to solve: For any positive integer n, the sum of the 1st n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 301? (A) 10,100 (B) 20,200 (C) 22,650 (D) 40,200 (E) 45,150

The sum of EVEN INTEGERS between 99 and 301 is the sum of EVEN INTEGERS between 100 and 300, or the sum of the 50th EVEN INTEGER through the 150th EVEN INTEGER. To get this sum: -Find the sum of the FIRST 150 even integers (ie 2 times the sum of the 1st 150 integers) -Subtract the sum of the FIRST 49 even integers (ie 2 times the sum of the 1st 49 integers)

You can multiply remainders, as long as you

correct excess remainders by dividing the product of the remainders by the divisor, leaving the final remainder

Simple strategy to solve questions about oddness or eveness is

create a table with scenarios as rows, each variable and desired term as columns, fill in boxes with ODD or EVEN

Let N be an integer. If you add two non-multiples of N, the result could be _______.

either a multiple of N or a non-multiple of N

In an evenly spaced set, the arithmetic mean (average) and median are

equal to each other, and equal the average of the first and last terms

gcd(m,n)*lcm(m,n) =

gcd(m,n)*lcm(m,n) = mn

An integer has an odd number of total factors iff

it is a perfect square

(The GCF of m and n) x (the LCM of m and n) =

m x n

You can only simplify exponential expressions that are linked by

multiplication or division; You cannot simplify expressions linked by addition or subtraction

Strategy for solving complicated absolute value equations containing two different variables in absolute value expressions is

pick numbers and use a chart with all combos of +/- as rows

Simple strategy to solve questions about positivity or negativity is

pick numbers to test systematically in a table; use each +/- combo as a row, use CRITERION to filter Y/N in column 1, use answer choices as other columns, fill boxes with POS or NEG

The GCF of m and n cannot be larger than

the difference between m and n

The absolute value of a difference (e.g. |x-y|) can be thought of as

the distance between the two numbers

An expression with a negative exponent is

the reciprocal of what that expression would be with a positive exponent.

You can simplify exponential expressions linked by multiplication or division if

they have a base or exponent in common, e.g.:

To find a GCF of two small numbers

use a Venn diagram: find all prime factors of the numbers, place common factors (including copies) into intersection, non-commons (including copies) outside.

To find an LCM of two small numbers

use a Venn diagram: find all prime factors of the numbers, place common factors (including copies) into intersection, non-commons (including copies) outside.

To find the GCF of large numbers, or of more than two numbers

use a chart with prime columns: the NUMBERS as rows, the PRIME FACTORS as columns, fill boxes with the factor to the right exponent (e.g. in the 5 column, 5^3).

To find the LCM of large numbers, or of more than two numbers

use a chart with prime columns: the NUMBERS as rows, the PRIME FACTORS as columns, fill boxes with the factor to the right exponent (e.g. in the 5 column, 5^3).

Simple ways to find all factors of a small number is

use a table of factor pairs (SMALL and LARGE as columns)

Strategy for keeping track of factors of consecutive integers is

use prime boxes (e.g., for x, x+1, x+2)

Simple strategy for using the Factor Foundation Rule is

use prime boxes, or partial prime boxes for constrained unknowns

GCF>?

|m-n|

gcd(m,n) ≥ ______

|m-n|

Prime Numbers: 0x

2,3,5,7

If the problem states/assumes that a number is an integer, check to see if you can use _______.

prime factorization

If estimating a root with a coefficient, _____ .

put the coefficient under the radical to get a better approximation

The product of k consecutive integers is always divisible by

k, and in fact by k factorial (k!)

GCF (m&n) x LCM (m&n)

mXn

If 2 cannot be one of the primes in the sum, the sum must be _____.

If 2 cannot be one of the primes in the sum, the sum must be even.

How to test for sufficiency: If p is an integer, is p/n an integer? (1) k₁p/n is an integer (2) k₂p/n is an integer

If gcd(k₁,n) ≠ 1 or gcd(k₂,n) ≠ 1, this proves insufficiency.

Prime Columns

To calculate the GCF we take the SMALLEST count (the lowest power) in any column. To calculate the LCM we take the LARGEST count (the highest power) in any column.

Positive integers with only two factors must be ___.

prime

In an evenly spaced set, the sum of the elements in the set equals

the arithmetic mean / median (average) number in the set times the number of items in the set.

In an evenly spaced set, the sum of the terms is equal to ____.

the average of the set times the number of elements in the set

In an evenly spaced set, the average can be found by finding ________.

the middle number

The sum of the integers in a set of consecutive integers is a multiple of the number of items iff

the number of items is odd

For ODD ROOTS, the root has ______.

the same sign as the base

The number of terms in an evenly spaced set equals

(Last - First) / Increment + 1

(a^b)x(c^b)

(axc)^b

Prime Numbers: 1x

11,13,17,19

Divisible by 9

Sum of digits divisible by 9

The prime factorization of __________ contains only EVEN powers of primes.

A PERFECT SQUARE

Prime Numbers: 10x

101, 103, 107, 109, 113

The answer choices for data sufficiency problems are

(A) 1 alone is, 2 is not (B) 2 alone is, 1 is not (C) both together are, neither alone is (D) each alone is (E) 1 and 2 together are not

√169=

13

√196=

14

√225=

15

√256=

16

√5≈

2.5

Prime Numbers: 2x

23,29

√625=

25

Prime Numbers: 3x

31,37

ex:// 3ⁿ + 3ⁿ + 3ⁿ = _____ = ______

3·3ⁿ = 3^{n+1}

Prime Numbers: 4x

41,43,47

Prime Numbers: 5x

53,59

Prime Numbers: 6x

61,67

Prime Numbers: 7x

71,73,79

Prime Numbers: 8x

83,89

Prime Numbers: 9x

97

N! is _____ of all integers from 1 to N.

A MULTIPLE

Any integer with an EVEN number of total factors cannot be ______.

A PERFECT SQUARE

Any integer with an ODD number of total factors must be _______.

A PERFECT SQUARE

ex:// ³√216 =

Break the number into prime powers: 216 = 2 * 2 * 2 * 3 * 3 * 3 = 2³ · 3³ = 6³, so ³√216 = ³√6³ = 6

How to solve: If k, m, and t are positive integers and k/6 + m/4 = t/12, do t and 12 have a common factor greater than 1? 1. k is a multiple of 3 2. m is a multiple of 3

Express as 2k + 3m = t. 1. If k is a multiple of 3, then so is t and we have a yes. => S 2. If m is a multiple of 3, we don't know. => I A/1 Alone.

On data sufficiency, ALWAYS _______ algebraic expressions when you can. ESPECIALLY for divisibility.

FACTOR

Consecutive multiples of n Have _____

GCF of n

Prime factors of _____ must come in pairs of three.

PERFECT CUBES

ADD 2 NON-multiples of N

Multiple of N || NON-multiple of N Except when N = 2 (Two ODDs = EVEN)

NI is a ____

Multiple of all the integers from 1 to N.

The prime factorization of a perfect CUBE contains only powers of primes that are ___

Multiples of 3 (90^3 = 2^3 3^6 5^3)

If N is a divisor of x and y, then _______.

N is a divisor of x+y

The two statements in a data sufficiency problem will _______________.

NEVER CONTRADICT ONE ANOTHER

Multiple of N +||- NON-multiple of N

NON-multiple of N. Except when N = 2 (Two ODDs = EVEN)

Divisible by 8

Number formed by last 3 digits is divisible by 8

All perfect squares have a(n) _________ number of total factors.

ODD

The total number of factors of a perfect square is always

ODD

When we take an EVEN ROOT, a radical sign means ________. This is _____ even exponents.

ONLY the nonnegative root of the number UNLIKE

Perfect Squares have an ___ number of total factors

Odd (ie 4 = 4 1 & 2 2) 1 2 4 are factors

Factor (FF)

Positive integer that divides evenly into an LARGER integer (1 2 4 8 are ___ of 8)

Total Factors

Prime Factor then (PowerA + 1) (PowerB + 1) 2000 = 5^3 * 2^4 therefore (3+1) (4+1) = 20

+/- multiple of N

Result is a multiple of N

Quotient

Result of Dividing 2 Integers

How to solve: Is the integer z divisible by 6? (1) gcd(z,12) = 3 (2) gcd(z,15) = 15

Set up prime columns. -- z 6 12 15 2 --2¹ 2² 3 --3¹ 3¹ 3¹ 5 ---------5¹

The PRODUCT of n consecutive integers is divisible by ____.

The PRODUCT of n consecutive integers is divisible by n!.

The SUM of n consecutive integers is divisible by n if ____, but not if ______.

The SUM of n consecutive integers is divisible by n if n is odd, but not if n is even.

The average of an EVEN number of consecutive integers will ________ be an integer.

The average of an EVEN number of consecutive integers will NEVER be an integer.

The average of an ODD number of consecutive integers will ________ be an integer.

The average of an ODD number of consecutive integers will ALWAYS be an integer.

Divisible by 11

The difference between the ODD digits (SUM) - EVEN digits (SUM) is divisible by 11 (includes 0). Ex. 5181. (5+8)-(1+1) divisible by 11

GCF

The largest divisor of two or more integers (Product of Overlap in Venn) (Reduce Fractions)

The sum of any two primes will be ____, unless ______.

The sum of any two primes will be even, unless one of the two primes is 2.

Integer

Whole Number: -3 -2 -1 0 1 2 3 (Non-Fraction/Non-Decimal)

Factor Foundation Rule: If x is a factor of y, and y is a factor of z, then...

X is a factor z

The formula for finding the number of consecutive multiples in a set is _______.

[(last - first) / increment] + 1

Let N be an integer. If you add a multiple of N to a non-multiple of N, the result is ________.

a non-multiple of N.

To find the number of factors of a number whose prime factorization is a^b x c^d x

add one to each exponent and multiply the results, as in: (b+1) x (d+1)...

GCF of multiple consecutive mulltiples of n is

n

gcd(k₁n, k₂n) = ______ for integers k₁, k₂

n

Positive integers with more than two factors are ____.

never prime


संबंधित स्टडी सेट्स

multiplication rule for dependent events

View Set

MARK Chapter 13 and Short Answers

View Set

Cricket Wireless Original Prices

View Set

WGS Unit 3: Gender and the Body!

View Set