Physics 201 Exam 1 Chapter 3

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Let A =(2m)i +(6m)j-(3m)k and B = (4m)i+(2m)j+(1m)k. The vector difference D=A-B is:

(02m)i+(4m)j-(4m)k

if A= (2m)i-(3m)j and B=(1m)i-(2m)j, then A-2b =

(1mj)

The two vectors (3m)i-(2m)j and (2m)i + (3m)j -(2m)k define a plane. It is the plane of the triangle with both tails at one vertex and each head at one of the other vertices. Which of the following vectors is perpendicular to the plane?

(4m)i+(6m)j+(13m)k

Let A= (2m)i+(6m)j-(3m)k and B=(4m)i+(2m)j+(1m)h. The vector sum s= A+B is:

(6m)i+(8m)j-(2m)k

The value of i*(jXK) is:

+1

A vector has a magnitude of 12. when its tail is at the origin it lies between the positive x axis and the negative y axis and makes an angle of 30 degrees with the x axis. Its y component is:

-6

The angle between A=(-25m)i+(45m)j and the positive x axis is:

119

A vector of magnitude 20 is added to a vector magnitude 25. the magnitude of this sum might be:

12

In the diagram, A has magnitude 12m and B has magnitude 8m. The x component of A+B is about:

12m

Two vectors have magnitudes of 10m and 15m. The angle between them when they are drawn with their tails at the same point is 65 degrees. The component of the longer vector along the line perpendicular to the shorter vector, in the plane of the vectors, is:

14m

A vector has a component of 10m in the +x direction, a component of 10m in the +y direction, and a component of 5m in the +z direction. The magnitude of this vector is?

15 m

Let A= (2m)i + (6m)j -(3m)k and B= (4m)i +(2m)j +(1m)k. Then A*B =

17m^2

Two vectors lie with their tails at the same point. When the angle between them is increased by 20 degrees the magnitude of their vector product doubles. The original angle between them was about:

18 degrees

If the x component of a vector A, in the xy plane, is half as large as the magnitude of the vector, the tangent of the angle between the vector and the x-axis is:

3/2

If A=(6m)i-(8m)j then 4A has magnitude:

40m

Two vectors have magnitudes of 10 m and 15 m. The angle between them when they are drawn with their tails at the same point is 65 degrees. The component of the longer vector along the line of the shorter is:

6.3m

A vector in the xy plane has a magnitude of 25m and an x component of 12m. The angle it makes with the positive x axis is:

61

The angle between A=(25m)i+(45m)j and the positive x axis is:

61

Let V= (2mi)i +(6m)j-(3m)k. The magnitude of V is:

7 m

A certain vector in the xy plane has an x component of 4m and a y component of 10m. It is then rotated in the xy plane so its x component is doubled. Its new y component is about:

7.2 m

Two vectors lie with their tails at the same point. When the angle between them is increased by 20 degrees their scalar product has the same magnitude but changes from positive to negative. The original angle between them was:

80 degrees

If [A-B] = A+B and neither A nor B vanish, then:

A and B are parallel and in opposite directions

if [A+B] = A+B and neither A nor B vanish, then:

A and B are parallel and in the same direction

Vectors A and B lie in the xy plane. We can deduce that A=B if:

Ax=Bx and Ay = By

Four vectors (A,B,C,D) all have the same magnitude. The angle theta between adjacent vectors is 45 degrees. The correct vector equation is :

B+D-sqrt(2C) = c

The vector a,b, and c are related by c=b-a. Which diagram below illustrates this relationship?

D

Let R=SXT and theta not equal to 90. Where theta is the angle between S and T when they are drawn with their tails at the same point. Which of the following is NOT true?

S*T=0

Let S = (1m)i +(2m)j+(2m)k and T= (3m)i+(4m)k. The angle between these two vectors is given by:

cos-1(11/15)

The vector -A is:

in the direction opposite to A

A vector S of magnitude 5 and another vector T have a sum of magnitude 12. The vector T:

must have a magnitude of at least 6 but no more than 18

If the magnitude of the sum of two vectors is greater than the magnitude of either vector, then:

none of the above

If A+B = A^2 + B^2, then:

none of the above is true

Why say that the displacement of a particle is a vector quantity. Our best justification for this assertion is:

operating with displacements according to the rules for manipulating vectors leads to results in agreement with experiments

Vectors A and B each have magnitude L. When drawn with their tails at the same point, the angle between them is 60 degrees. The magnitude of the vector product AXB is:

sqrt(3)L^2/2

Vectors A and B each have magnitude L. When drawn with their tails at the same point. the angle between them is 30 degrees, The value of A*B is:

sqrt(3)L^2/2

If the magnitude of the sum of two vectors is less than the magnitude of either vector, then:

the scalar product of the vectors must be negative

the vector V3 in the diagram is equal to:

v2-v1

A vector of magnitude 3 cannot be added to vector of magnitude 4 so that the magnitude of the resultant is:

zero

The value of k*(kxi)is:

zero


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