Apologia Exploring Creation with Chemistry Module 2 test

You are told that a molecule contains a total of 17 atoms. If the formula is C5H10Clx. What must x be?

2

How many total atoms are in this molecule: C6H12OH?

20

What is an ionic compound?

A metal and a nonmetal atoms bonded together

Which of the following compounds would conduct electricity when dissolved in water? C3H6ClF C6H5CH3 CS2 BaSO4

BaSO4

What type of compound uses the naming system that has -ide as the ending on the nonmetals?

Both ionic and covalent

What is the name of Ca3N2

Calcium nitride

What type of compound uses the naming system consisting of prefixes like mono-, di-, and tri-?

Covalent

What is the name of N203

Dinitrogen trioxide

True or false Manganese, Mn, is a nonmetal

False

Which of the following is a heterogeneous mixture?

Italian salad dressing

The law of mass conservation

Matter cannot be created or destroyed; it can only change forms.

A substance that contains more than one type of individual atom or molecule is a

Mixture

How can you experiment to determine if a compound is covalent?

None of the above will prove a compound is covalent

A substance that contains only one type of atom or molecule is a

Pure substance

What is the chemical formula of sulfur trioxide?

SO3

In an experiment to determine how to make sulfur trioxide, a chemist combines 32.0 grams of salt per with 50.0 grams of oxygen. She finds that she made 80.0 grams of sulfur trioxide and had 2.0 grams of leftover oxygen. How would the chemist make 100 grams of sulfur trioxide so that she has no leftovers

Since 2.0 grams of oxygen were left over, the chemist needed only 48.0 g of oxygen to make 80.0 g of sulfur trioxide. Since there was no leftover sulfur, the chemist needed all 32.0 g of sulfur. Thus, to make 80.0 g of sulfur trioxide, she needs 32.0 g of sulfur and 48.0 g of oxygen. To make 100 g of sulfur trioxide, she simply needs to scale up by 100.0 ÷ 80.0 = 1.25. Thus, she needs 1.25 * 32.0 g = 40.0 g of sulfur and 1.25 * 48.0 g = 60.0 g of oxygen.

The law of multiple proportions

The principle that if elements combine in different proportions, they produce different compounds

True or false Xenon, Xe, is a nonmetal

True

state the law of definite proportions in your own words

a compound is always made up with the same proportions of its elements

Dalton's atomic theory

1) elements are composed of atoms. 2) atoms of same element have identical properties 3) different elements have different properties. 4) since atoms are indivisible, elements can mix together only in simple, whole number ratios

a chemist measures the mass of a chunk of wood to be 49.8 g. When the wood is decomposed, 15.0 g of water and 12.0 g of ash, and some carbon dioxide are produced. How many grams of carbon dioxide were produced?

22.8 g

A chemist does two experiments in one experiment he finds that 14.0 g of nitrogen combined with 16.0 grams of oxygen to make 30.0 g of a compound he calls compound A. In another experiment the chemist finds that 48.0 g of oxygen combine with 42.0 g of nitrogen to make 90.0 g of a compound he calls compound B. The chemist states that the law of definite proportions tells him that compound A and compound B are two completely different compounds. Why is he wrong?

Compounds A & B are really the same compound. In order to make two different compounds the elements would have to combine in different proportions. Since 48.0 g of oxygen + 42.0 g of nitrogen is just 3 times 16.0 g of oxygen and 14.0 g of nitrogen, the elements have combined in the same proportion, so they make the same compound

To make 44.0 g of carbon dioxide, you must combine 12.0 g of carbon with 32.0 grams of oxygen. If a chemist combines 120.0 g of carbon with 160.0 g of oxygen, how many grams of carbon dioxide will be made? If a substance is left over, indicate whether its carbon or oxygen, and also determine how many grams are left over.

Based on the recipe given, the chemist has 10 times as much carbon and five times as much oxygen. Thus, he can only make five times as much carbon dioxide as in the recipe because he will run out of oxygen long before the carbon. This means he will make 5 * 44.0 = 2.20 * 10 squared grams of carbon dioxide. This will use up all the oxygen, but a lot of carbon will be left over. Since he can only make five times the amount of carbon dioxide as it says in the recipe, he will only use 5 * 12.0 = 60.0 grams of carbon. Since he started with 120 grams of carbon and used only 60.0, there are 60.0 grams of leftover carbon.