Knewton Alta Lesson 5 Assignment

Find the median of the following set of data. 7,26,7,9,11,4,15,22

10 median = 10 It helps to put the numbers in order. 4,7,7,9,11,15,22,26 Now, because the list has length 8, which is even, we know the median number will be the average of the middle two numbers, 9 and 11. So the median is 10.

Jon loves to go bird watching at a nearby animal sanctuary. Find the mean of the following numbers of birds he spotted at the sanctuary in the last few days. 14,10,17,11,9,15,6,14

12 mean = 12 birds Remember that the mean is the sum of the numbers divided by the number of numbers. There are 8 numbers in the list. So we find that the mean number of birds spotted is 14+10+17+11+9+15+6+14 = 8 96 = 12 8

Given the following list of values, is the mean or the median likely to be a better measure of the center of the data set? 27, 25, 29, 27, 24, 30, 28, 24, 25, 28 Select the correct answer below: Mean Median

Mean Most of the values are close together in the range between 24 and 30. There are no very large or very small values in the list, so the mean is a good measure of the center because it takes into account all the values but will not be pulled up or down by any one value.

Given the following list of values, is the mean or the median likely to be a better measure of the center of the data set? 39, 41, 38, 39, 38, 41, 41, 39, 40 Select the correct answer below: Mean Median

Mean Most of the values are close together in the range between 38 and 41. There are no very large or very small values in the list, so the mean is a good measure of the center because it takes into account all the values but will not be pulled up or down by any one value.

A veterinary researcher is studying a particular type of dog called the Australian Cattle Dog. The researcher has acquired data on a sample of 10 dogs. The data for the weight of these dogs in pounds are reproduced in the table below. Calculate the mean and median using a TI-83, TI-83 plus, or TI-84 graphing calculator (round your answers to two decimal places). Australian Cattle Dog Weights in Pounds 36.1,38.7,39.3,39.4,39.9,40.3,40.9,41.9,43,43

Mean = 40.25, Median = 40.10, Mode = 43.00 The mean, median, and mode can be calculated using a TI-83, TI-83 plus, or TI-84 calculator. 1. Press STAT and then ENTER to get to the list editing screen. 2. Enter the data into list L1, and then press 2nd followed by MODE to return to the home screen. 3. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 3 for mean(. 4. On the home screen after mean(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 5. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 4 for median(. 6. On the home screen after median(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 7. Press the STAT key, and then press 2 for SortA(. 8. On the home screen after sortA(, press 2nd and then 1 to write L1, and then press ) and ENTER to sort the data in L1. 9. Press the STAT key, and then press 1 to get to the list edit screen. Scroll through the list of values under L1 and under L2, and write each unique number in order from least to greatest. Next to each value in L2, write under L3 the number of times each unique value occurs in L1. 10. Find the largest number in L3. The corresponding number(s) in L2 is/are the mode. If there is no largest number in L3, there is no mode. The result of this process applied to the dataset is that rounded to two decimal places the mean is 40.25, the median is 40.10, and the mode is 43.00.

Given the following list of values, is the mean or the median likely to be a better measure of the center of the data set? 29, 56, 27, 29, 27, 28, 28, 30, 30, 27 Select the correct answer below: Mean Median

Median Most of the values are close together in the range between 27 and 30, but because there is one number, 56, which is much larger than the rest of the values, the mean would not be a good measure because that one large value would pull the mean up. Therefore, the median is probably a better measure of the center of this data set.

Given the following list of data, What is the five-number summary? 4, 4, 4, 5, 5, 7, 8, 9, 10, 10, 10, 10, 11, 12, 13 Select the correct answer below: MinQ1MedianQ3Max 4591013 MinQ1MedianQ3Max 4681213 MinQ1MedianQ3Max 467813 MinQ1MedianQ3Max 4561013 MinQ1MedianQ3Max 4591113

MinQ1MedianQ3Max 4591013 We can immediately see that the minimum value is 4 and the maximum value is 13.There are 15 values in the list, so the median value is the one where there are 7 values below it and 7 values above it. We see that this happens at the value 9, so that is the median.Now, looking at the lower half of the data, there are 7 values there, and so the median value of that half of the data is 5. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 10.So the five-number summary is MinQ1MedianQ3Max 4591013

The following frequency table summarizes a set of data. What is the five-number summary? Value 7 8 9 10 13 15 16 17 Frequency 1 1 3 1 3 3 2 1

MinQ1MedianQ3Max 79131517 We can immediately see that the minimum value is 7 and the maximum value is 17.If we add up the frequencies in the table, we see that there are 15 total values in the data set. Therefore, the median value is the one where there are 7 values below it and 7 values above it. By adding up frequencies, we see that this happens at the value 13, so that is the median.Now, looking at the lower half of the data, there are 7 values there, and so the median value of that half of the data is 9. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 15.7, 8, 9, 9, 9, 10, 13, 13, 13, 15, 15, 15, 16, 16, 17So the five-number summary is MinQ1MedianQ3Max 79131517

The owner of a large cattle ranch decides to look at the weights in kilograms of a random sample of 10 of his steers. The data are reproduced in the table below. Calculate the mode(s) using a TI-83, TI-83 plus, or TI-84 graphing calculator. Weights of steers in kilograms 1021,1058,1113,1117,1079,1250,1037,1285,1067,1229 Select the correct answer below: There are two modes. The modes are 1,067 and 1,058. There is one mode. The mode is 1,229. There is one mode. The mode is 1,067. There is no mode.

There is no mode. The mode can be calculated using a TI-83, TI-83 plus, or TI-84 calculator. 1. Press STAT and then ENTER to get to the list editing screen. 2. Enter the data into list L1, and then press 2nd followed by MODE to return to the home screen. 3. Press the STAT key, and then press 2 for sortA(. 4. On the home screen after sortA(, press 2nd and then 1 to write L1, and then press ) and ENTER to sort the data in L1. 5. Press the STAT key, and then press 1 to get to the list edit screen. Scroll through the list of values under L1, and write each unique number in order from least to greatest under L2. Next to each value in L2, write under L3 the number of times each unique value occurs in L1. 6. Find the largest number in L3. The corresponding number(s) in L2 is/are the mode. If there is no largest number in L3, there is no mode. Noting that L2 is identical to L1 or observing that every entry in L3 is 1 verifies that there is no most frequently occurring entry. No entry occurs more than once. Therefore, there is no mode.

Given the following list of the number of pencils randomly selected students used in a school year, find the median. 10,22,6,7,19,5,27

10 median = 10 pencils It helps to put the numbers in order. 5,6,7,10,19,22,27 Now, because the list has length 7, which is odd, we know the median number will be the middle number. In other words, we can count to item 4 in the list, which is 10. So the median number of pencils randomly selected students used in a school year is 10.

Find the mode of the following amounts of exercise (in hours) randomly selected runners completed during a weekend. 2,14,14,4,2,4,1,14,4,4,8

4 mode = 4 hours Value 1 2 4 8 14 Frequency 1 2 4 1 3 Note that 4 occurs 4 times, which is the greatest frequency, so 4 is the mode of the amount of exercise (in hours) randomly selected runners completed during a weekend.

A student would like to find the mean number of people living in households in a neighborhood. She collects data from 65 homes in the area. The graph shows the frequency for the number of people living in the homes. Find the mean number of people living in the 65 homes, and round your answer to the nearest tenth. Record your answer by dragging the purple point to the mean.

4.9 The frequency graph shows the frequency for each data value. So, we can compute the mean by added up all the data values and dividing by the total number of data 3⋅1+6⋅2+7⋅3+8⋅4+12⋅5+14⋅6+15⋅7 = 65 317 ≈ 4.88 65 Rounding to the nearest tenth, we have the mean is 4.9.

The Bureau of Labor Statistics compiles and makes publicly available data from a range of different sectors of the economy. One value that is reported is a weighted average of the costs of certain goods, called the Consumer Price Index (CPI). The CPI is related to the price but is not a dollar amount. The rise in prices is used as a metric of inflation. To make the metric more reliable, a chained CPI was created. The regular CPI does not update the types of goods it averages often enough to reflect the market trends, like a switch from apples to oranges resulting from a rise in apple prices. The chained CPI is a measure of price that takes this into account, and there are several bills that are tied to the chained CPI index in order to determine the payout the bill allots each year. The monthly average chained CPI for urban apparel for all urban consumers for 10 consecutive months is provided below. The data are not seasonally adjusted. Construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator to choose the correct plot below. All plots have the following window settings: Xmin=88, Xmax=100.5, Xscl=0.5, Ymin=−0.5, Ymax=3.5, Yscl=1, Xres=1. Chained CPI - Appare 89.02 89.10 90.06 90.54 91.31 91.69 91.85 94.76 95.18 99.51

91.5 To construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator, follow these steps: 1. Enter the data into list L1. To do this, press STAT and then ENTER or 1 to get to the list editing screen. 2. Press 2nd and then Y= to get to the STAT PLOT menu, and then press ENTER to edit the first plot. Set the plot to On. Then, navigate the plot types with the LEFT and RIGHT buttons. Select the fifth type, which is the box plot without outlier identification. Then set Xlist to L1. 3. Now press ZOOM and then 9 to activate 9: ZoomStat. 4. Press the TRACE button and then RIGHT and LEFT to move the cursor to each of the five values of the five-number summary: the minimum, Q1, the median, Q3, and the maximum. The box and whisker plot looks like the following image.

The following data set provides wage information of Seattle by subdivisions. Arrange the Departments in ascending order of the maximum hourly rate. City Auditor, City Budget, Arts and Culture Arts and Culture, City Budget, City Auditor City Budget, Arts and Culture, City Auditor Arts and Culture, City Auditor, City Budget

Arts and Culture, City Auditor, City Budget The maximum hourly rate for the three departments in ascending order is: Arts and Culture ($62.59), City Auditor ($72.84), and City Budget ($86.83).

The following data set provides wage information of Seattle by subdivisions. Background: You are interviewing for the job of Compensation Specialist for the city of Seattle. The hiring manager shows you the database for wage and classification information from February 2017. She asks you: What are the job titles of the two persons with the highest hourly rates in the second quartile of the Arts and Culture Department? Select the correct answer below: Manager and Strategic Advisor Public Relations Specialist and Administrative Staff Analyst Administrative Staff Assistant and Stage Tech,Lead Accountant and Arts Program Specialist

Administrative Staff Assistant and Stage Tech,Lead When separating the jobs into the quartiles, you see that the two job titles with the highest hourly rates in the second quartile of the Arts and Culture Department are Administrative Staff Assistant and Stage Tech,Lead.

Given the following frequency table of values, is the mean or the median likely to be a better measure of the center of the data set? Value 32 33 34 35 36 37 Frequency 2 3 6 2 2 1 Select the correct answer below: Mean Median

Mean Most of the values are close together in the range between 32 and 37. There are no very large or very small values in the list, so the mean is a good measure of the center because it takes into account all the values but will not be pulled up or down by any one value.

Find the mode of the following number of states randomly selected travelers at a service plaza visited in the past three years. 18,13,8,8,13,10,13,10,9,18

13 mode = 13 states Value 8 9 10 13 18 Frequency 2 1 2 3 2 Note that 13 occurs 3 times, which is the greatest frequency, so 13 is the mode of the number of states randomly selected travelers at a service plaza visited in the past three years.

Given the following list of the number of pens randomly selected students purchased in the last semester, find the median. 13,7,8,37,32,19,17,32,12,26

18 median = 18 pens It helps to put the numbers in order. 7,8,12,13,17,19,26,32,32,37 Now, because the list has length 10, which is even, we know the median number will be the average of the middle two numbers, 17 and 19. So the median number of pens randomly selected students purchased in the last semester is 18.

A manager at a shoe factory would like to find the mean number of breaks taken by employees on a particular Friday. He collects data from 15 fellow coworkers in the factory. The graph shows the frequency for the number of breaks taken during this time period. Find the mean number of breaks for the 15 coworkers, and round your answer to the nearest tenth. Record your answer by dragging the purple point to the mean.

2.8 The frequency graph shows the frequency for each data value. So, we can compute the mean by added up all the data values and dividing by the total number of data values. 3⋅1+5⋅2+3⋅3+2⋅4+1⋅5+0⋅6+1⋅7 = 15 42 = 2.8 15

Find the median of the following list of dollars spent per customer at a cheese shop in the last hour. 32,19,21,16,27,15

20 median = 20 dollars 15,16,19,21,27,32 Now, because the list has length6, which is even, we know the median number will be the average of the middle two numbers,19and21. So the median number of dollars spent per customer at a cheese shop in the last hour is20.

A company sells classes on its speed-reading technique, which it advertises to customers through a free, online survey. The results of 10 of these tests are included below. Use a TI-83, TI-83 Plus, or TI-84 calculator to construct a box and whisker plot for the dataset. What is the value of the first quartile? Words per minute 203 227 212 158 158 254 319 277 263 325

203 To construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator, follow these steps: 1. Enter the data into list L1. To do this, press STAT and then ENTER or 1 to get to the list editing screen. 2. Press 2nd and then Y= to get to the STAT PLOT menu, and then press ENTER to edit the first plot. Set the plot to On. Then, navigate the plot types with the LEFT and RIGHT buttons. Select the fifth type, which is the box plot without outlier identification. Then set Xlist to L1. 3. Now press ZOOM and then 9 to activate 9: ZoomStat. 4. Press the TRACE button and then RIGHT or LEFT to move the cursor to the first quartile, which is where the left whisker intersects with the left side of the box, to get Q1=203.

The following data set provides wage information of Seattle by subdivisions. In how many different quartiles would you find people with the job classification of Strategic Advisor 2, Exempt, in the City Budget Department?

3

Find the mode of the following number of times each machine in a car factory needed to be fixed within the last year. 2,5,6,12,14,12,6,2,5,3,14,5

5 mode = 5 repairs Value 2 3 5 6 12 14 Frequency 2 1 3 2 2 Note that 5 occurs 3 times, which is the greatest frequency, so 5 is the mode of the number of times a machine in a car factory needed to be fixed within the last year.

A large, multi-company construction workers union is gathering data on the number of workplace injuries that occurred last year. It gathers the number of injuries from 10 randomly chosen companies among the hundreds of construction companies at which the members work. The data are provided below. Use a TI-83, TI-83 Plus, or TI-84 calculator to construct a box and whisker plot for the dataset. What is the value of the median of the dataset? Number of injuries last year 6,2,5,10,7,5,4,20,11,0

5.5 To construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator, follow these steps: 1. Enter the data into list L1. To do this, press STAT and then ENTER or 1 to get to the list editing screen. 2. Press 2nd and then Y= to get to the STAT PLOT menu, and then press ENTER to edit the first plot. Set the plot to On. Then, navigate the plot types with the LEFT and RIGHT buttons. Select the fifth type, which is the box plot without outlier identification. Then set Xlist to L1. 3. Now press ZOOM and then 9 to activate 9: ZoomStat. 4. Press the TRACE button and then RIGHT and LEFT to move the cursor to the median, the dividing line inside the box, which is 5.5.

An organization that monitors the average annual salaries of different professions collects data on bacteriologist's salaries from both the academic and the corporate sectors. The annual salary in U.S. dollars of 10 bacteriologists is given below. Use a TI-83, TI-83 Plus, or TI-84 calculator to construct a box and whisker plot for the dataset. What is the value of the first quartile? Salary of Bacteriologists (dollars per year) 99922 80832 77933 57599 62600 57547 93007 55022 79257 74923

57599 To construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator, follow these steps: 1. Enter the data into list L1. To do this, press STAT and then ENTER or 1 to get to the list editing screen. 2. Press 2nd and then Y= to get to the STAT PLOT menu, and then press ENTER to edit the first plot. Set the plot to On. Then, navigate the plot types with the LEFT and RIGHT buttons. Select the fifth type, which is the box plot without outlier identification. Then set Xlist to L1. 3. Now press ZOOM and then 9 to activate 9: ZoomStat. 4. Press the TRACE button and then RIGHT and LEFT to move the cursor to the first quartile, where the left whisker intersects with the left side of the box, to get Q1=57599.

Find the mode of the following hourly wages (in dollars) of randomly selected employees at a coffee shop. 8,17,14,11,17,13,11,17,8,8,8

8 mode = 8 dollars If we count the number of times each value appears in the list, we get the following frequency table: Value 8 11 13 14 17 Frequency 4 2 1 1 3 Note that 8 occurs 4 times, which is the greatest frequency, so 8 is the mode of the hourly wages (in dollars) of randomly selected employees at a coffee shop.

A total of 14 different people were randomly surveyed and asked how many hours per day they worked the week before. Their answers are included below. Construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator. All plots below have the following window settings: Xmin=7.95, Xmax=8.25, Xscl=0.01, Ymin=−0.5, Ymax=3.5, Yscl=1, Xres=1. Average Work Hours Per Day 8.08 8.08 8.04 8.12 8.05 8.05 7.97 8.00 8.10 8.22 8.09 8.18 8.06 8.15

8.08 To construct a box and whisker plot using a TI-83, TI-83 Plus, or TI-84 graphing calculator, follow these steps: 1. Enter the data into list L1. To do this, press STAT and then ENTER or 1 to get to the list editing screen. 2. Press 2nd and then Y= to get to the STAT PLOT menu, and then press ENTER to edit the first plot. Set the plot to On. Then, navigate the plot types with the LEFT and RIGHT buttons. Select the fifth type, which is the box plot without outlier identification. Then set Xlist to L1. 3. Now press ZOOM and then 9 to activate 9: ZoomStat. 4. Press the TRACE button and then RIGHT and LEFT to move the cursor to each of the five values of the five-number summary: the minimum, Q1, the median, Q3, and the maximum. The box and whisker plot looks like the following image

The following data set provides wage information of Seattle by subdivisions. What is the lowest hourly rate in the fourth quartile of the Arts and Culture Department?

$40.93 The lowest hourly rate in the fourth quartile of the Arts and Culture Department is $40.93.

A student of statistics and fan of baseball is looking over the player stats for a list she is compiling of "top ten players nobody remembers." The data for the batting averages of these 10 players are reproduced in the table below. Calculate the mean, median, and mode using a TI-83, TI-83 plus, or TI-84 graphing calculator (round your answers to three decimal places). Baseball player batting averages 0.272 0.272 0.212 0.293 0.322 0.262 0.285 0.250 0.243 0.277

Mean = 0.269, Median = 0.272, Mode = 0.272 The mean, median, and mode can be calculated using a TI-83, TI-83 plus, or TI-84 calculator. 1. Press STAT and then ENTER to get to the list editing screen. 2. Enter the data into list L1, and then press 2nd followed by MODE to return to the home screen. 3. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 3 for mean(. 4. On the home screen after mean(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 5. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 4 for median(. 6. On the home screen after median(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 7. Press the STAT key, and then press 2 for SortA(. 8. On the home screen after sortA(, press 2nd and then 1 to write L1, and then press ) and ENTER to sort the data in L1. 9. Press the STAT key, and then press 1 to get to the list edit screen. Scroll through the list of values under L1 and under L2, and write each unique number in order from least to greatest. Next to each value in L2, write under L3 the number of times each unique value occurs in L1. 10. Find the largest number in L3. The corresponding number(s) in L2 is/are the mode. If there is no largest number in L3, there is no mode. The result of this process applied to the dataset is that, rounded to three decimal places, the mean is 0.269, the median is 0.272, and the mode is 0.272.

The owners of a hedge maze determine that customers want to be challenged but not frustrated. To determine if their maze is challenging enough and not too challenging, they decide to look at the completion time of 10 randomly selected customers. The data are reproduced in the table below. Calculate the mean, median, and mode using a TI-83, TI-83 plus, or TI-84 graphing calculator (round your answers to one decimal place). Time to complete maze in seconds 199 190 175 191 195 195 173 172 205 192

Mean = 188.7, Median = 191.5, Mode = 195.0 The mean, median, and mode can be calculated using a TI-83, TI-83 plus, or TI-84 calculator. 1. Press STAT and then ENTER to get to the list editing screen. 2. Enter the data into list L1, and then press 2nd followed by MODE to return to the home screen. 3. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 3 for mean(. 4. On the home screen after mean(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 5. Press 2nd followed by STAT for the LIST menu. Then press the right arrow twice to get to the MATH tab of the LIST menu, and then press 4 for median(. On the home screen after median(, press 2nd and then 1 to write L1, and then press ) and ENTER to obtain the value. 7. Press the STAT key, and then press 2 for SortA(. 8. . On the home screen after sortA(, press 2nd and then 1 to write L1, and then press ) and ENTER to sort the data in L1. 9. Press the STAT key, and then press 1 to get to the list edit screen. Scroll through the list of values under L1 and under L2, and write each unique number in order from least to greatest. Next to each value in L2, write under L3 the number of times each unique value occurs in L1. 10. Find the largest number in L3. The corresponding number(s) in L2 is/are the mode. If there is no largest number in L3, there is no mode. The result of this process applied to the dataset is that, rounded to one decimal place, the mean is 188.7, the median is 191.5, and the mode is 195.0.

Given the following list of values, is the mean or the median likely to be a better measure of the center of the data set? 25, 29, 23, 26, 25, 27, 10, 26, 23, 23, 26 Select the correct answer below: Mean Median

Median Most of the values are close together in the range between 23 and 29, but because there is one number, 10, which is much smaller than the rest of the values, the mean would not be a good measure because that one small value would pull the mean down. Therefore, the median is probably a better measure of the center of this data set.

Given the following frequency table of values, is the mean or the median likely to be a better measure of the center of the data set? Value 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 Frequency 1 0 0 0 0 0 0 0 0 0 0 0 0 3 4 3 3 1 Select the correct answer below: Mean Median

Median Most of the values are close together in the range between 33 and 37, but because there is one number, 20, which is much smaller than the rest of the values, the mean would not be a good measure because that one small value would pull the mean down. Therefore, the median is probably a better measure of the center of this data set.

The following frequency table summarizes a set of data. What is the five-number summary? Value 12 13 14 15 17 18 19 21 Frequency 2 1 1 4 5 2 3 1 Select the correct answer below: MinQ1MedianQ3Max 1214161821 MinQ1MedianQ3Max 1215171821 MinQ1MedianQ3Max 1215182021 MinQ1MedianQ3Max 1213142021 MinQ1MedianQ3Max 1215161821

MinQ1MedianQ3Max 1215171821 We can immediately see that the minimum value is 12 and the maximum value is 21.If we add up the frequencies in the table, we see that there are 19 total values in the data set. Therefore, the median value is the one where there are 9 values below it and 9 values above it. By adding up frequencies, we see that this happens at the value 17, so that is the median.Now, looking at the lower half of the data, there are 9 values there, and so the median value of that half of the data is 15. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 18.12, 12, 13, 14, 15, 15, 15, 15, 17, 17, 17, 17, 17, 18, 18, 19, 19, 19, 21So the five-number summary is MinQ1MedianQ3Max 1215171821 A new cafe can use a five-number summary to see the layout of number of drinks sold per night. The lowest number of drinks sold was 12, the most 21 with a median score of 17. The median of the lower half 15, and upper half 18. This could tell the cafe if they should keep their liquor license or not.

The following frequency table summarizes a set of data. What is the five-number summary? Value 2 3 4 5 7 8 10 11 12 Frequency 2 2 2 1 2 4 3 1 2

MinQ1MedianQ3Max 2481012 We can immediately see that the minimum value is 2 and the maximum value is 12.If we add up the frequencies in the table, we see that there are 19 total values in the data set. Therefore, the median value is the one where there are 9 values below it and 9 values above it. By adding up frequencies, we see that this happens at the value 8, so that is the median.Now, looking at the lower half of the data, there are 9 values there, and so the median value of that half of the data is 4. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 10.2, 2, 3, 3, 4, 4, 5, 7, 7, 8, 8, 8, 8, 10, 10, 10, 11, 12, 12So the five-number summary is MinQ1MedianQ3Max 2481012 Plant Director can use a five-number summary to see the layout of number of projects completed per manager. The lowest number of projects completed was 2, the most 12 with a median score of 8. The median of the lower half 4, and upper half 10. This could tell the plant director if projects should be distributed differently among managers.

The following data set provides wage information of Seattle by subdivisions. The range of salaries is greater in the Arts and Culture Department than in the City Auditor Department. Select the correct answer below: True False

True Salaries in the Arts and Culture Department go from from $16.12 to $62.59, a range of $46.47. Salaries in the City Auditor Department go from $43.86 to $72.84, a range of $28.98.

Given the following list of data, What is the five-number summary? 2, 5, 7, 7, 9, 9, 9, 10, 10, 11, 12 Select the correct answer below: MinQ1MedianQ3Max 245712 MinQ1MedianQ3Max 2791012 MinQ1MedianQ3Max 25101112 MinQ1MedianQ3Max 257812 MinQ1MedianQ3Max 2781012

MinQ1MedianQ3Max 2791012 We can immediately see that the minimum value is 2 and the maximum value is 12.There are 11 values in the list, so the median value is the one where there are 5 values below it and 5 values above it. We see that this happens at the value 9, so that is the median.Now, looking at the lower half of the data, there are 5 values there, and so the median value of that half of the data is 7. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 10.So the five-number summary is MinQ1MedianQ3Max 2791012 A restaurant can use a five-number summary to see the layout of customer satisfaction scores about their service. For this, a scale of least 1 - most 12 could have been used with 1 not being selected. The lowest satisfaction score used was 2, the most 12 with a median score of 9. The median of the lower half 7, and upper half 10. This could tell the restaurant whether to train employees more or keep with their standards.

Given the following list of data, What is the five-number summary? 4, 4, 5, 5, 6, 6, 6, 8, 8, 10, 11 Select the correct answer below: MinQ1MedianQ3Max 4791011 MinQ1MedianQ3Max 456811 MinQ1MedianQ3Max 457811 MinQ1MedianQ3Max 456711 MinQ1MedianQ3Max 468911

MinQ1MedianQ3Max 456811 We can immediately see that the minimum value is 4 and the maximum value is 11.There are 11 values in the list, so the median value is the one where there are 5 values below it and 5 values above it. We see that this happens at the value 6, so that is the median.Now, looking at the lower half of the data, there are 5 values there, and so the median value of that half of the data is 5. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 8.So the five-number summary is MinQ1MedianQ3Max 456811 A small business can use a five-number summary to see the layout of customer satisfaction scores. For this, a scale of least 1 - most 12 could have been used with 1−3 and 12 not being selected. The lowest satisfaction score used was 4, the most 11 with a median score of 6. The median of the lower half 5, and upper half 8. This could tell the business whether or not they need to make improvements.

The following frequency table summarizes a set of data. What is the five-number summary? Value 5 6 7 9 11 13 15 16 Frequency 3 2 1 1 3 3 1 1 Select the correct answer below: MinQ1MedianQ3Max 5891116 MinQ1MedianQ3Max 56111316 MinQ1MedianQ3Max 57111516 MinQ1MedianQ3Max 5691316 MinQ1MedianQ3Max 59101516

MinQ1MedianQ3Max 56111316 We can immediately see that the minimum value is 5 and the maximum value is 16.If we add up the frequencies in the table, we see that there are 15 total values in the data set. Therefore, the median value is the one where there are 7 values below it and 7 values above it. By adding up frequencies, we see that this happens at the value 11, so that is the median.Now, looking at the lower half of the data, there are 7 values there, and so the median value of that half of the data is 6. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 13.5, 5, 5, 6, 6, 7, 9, 11, 11, 11, 13, 13, 13, 15, 16So the five-number summary is MinQ1MedianQ3Max 56111316

Given the following list of data, What is the five-number summary? 7, 7, 8, 8, 8, 10, 10, 11, 12, 12, 13, 13, 13, 13, 17 Select the correct answer below: MinQ1MedianQ3Max 79111517 MinQ1MedianQ3Max 78151617 MinQ1MedianQ3Max 79111617 MinQ1MedianQ3Max 79151617 MinQ1MedianQ3Max 78111317

MinQ1MedianQ3Max 78111317 We can immediately see that the minimum value is 7 and the maximum value is 17.There are 15 values in the list, so the median value is the one where there are 7 values below it and 7 values above it. We see that this happens at the value 11, so that is the median.Now, looking at the lower half of the data, there are 7 values there, and so the median value of that half of the data is 8. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 13.So the five-number summary is MinQ1MedianQ3Max 78111317 An owner of multiple stores can use a five-number summary to see the layout of how much each store sells men's cologne. The lowest number of men's cologne being sold was 7, the most 17 with a median score of 11. The median of the lower half 8, and upper half 13. This could tell him whether to sell more men's cologne or not.

The following frequency table summarizes a set of data. What is the five-number summary? Value 7 8 10 11 13 14 16 17 Frequency 2 3 2 1 2 2 1 2 Select the correct answer below: MinQ1MedianQ3Max 78111417 MinQ1MedianQ3Max 711121317 MinQ1MedianQ3Max 78131517 MinQ1MedianQ3Max 79121317 MinQ1MedianQ3Max 7891617

MinQ1MedianQ3Max 78111417 We can immediately see that the minimum value is 7 and the maximum value is 17.If we add up the frequencies in the table, we see that there are 15 total values in the data set. Therefore, the median value is the one where there are 7 values below it and 7 values above it. By adding up frequencies, we see that this happens at the value 11, so that is the median.Now, looking at the lower half of the data, there are 7 values there, and so the median value of that half of the data is 8. This is the first quartile. Similarly, the third quartile is the median of the upper half of the data, which is 14.7, 7, 8, 8, 8, 10, 10, 11, 13, 13, 14, 14, 16, 17, 17So the five-number summary is MinQ1MedianQ3Max 78111417 A new T-Shirt shop can use a five-number summary to see the layout of number of sweaters sold per day. The lowest number of sweaters sold was 7, the most 17 with a median score of 11. The median of the lower half 8, and upper half 14. This could tell the shop if they should keep selling sweaters or look at another item.

A food truck owner in the city of Chicago is interested in the monthly average temperatures to plan accordingly in the high demand spots. According to U.S. climate data, the monthly average high temperatures, in degrees Fahrenheit, for the city of Chicago are listed below. 32,34,43,55,65,75,81,79,73,61,47,36 Find the five-number summary for this data. Select the correct answer below: Sample minimum: 32, Sample maximum: 36 Q1: 49, Median: 78, Q3: 67 Sample minimum: 32, Sample maximum: 81 Q1: 43, Median: 58, Q3: 73 Sample minimum: 32, Sample maximum: 81 Q1: 39.5, Median: 58, Q3: 74 Sample minimum: 32, Sample maximum: 81 Q1: 39.5, Median: 61, Q3: 74

Sample minimum: 32, Sample maximum: 81 Q1: 39.5, Median: 58, Q3: 74 The five-number summary must be found using a data set that is ordered from least to greatest. Once ordered, the sample minimum is the smallest value, and the sample maximum is the largest value. The median is the middle value, which separates the data set into a lower half and an upper half. Q1 is the median of the lower half of the data set, and Q3 is the median of the upper half of the data set. In this case, putting the data in order gives: 32,34,36,43,47,55,61,65,73,75,79,81 Now, we can easily identify the sample minimum and maximum as the smallest value, 32, and the largest value 81, respectively. Because the list has an even number of values, we take the average of the middle two values, 55 and 61, to find the median: 58. The lower half of the data also has an even number of values, so taking the average of the middle values, 36 and 43, gives Q1: 39.5.Finally, the upper half of the data also has an even number of values, so taking the average of the middle values, 73, and 75, gives Q3: 74.

John is the owner of a flower shop in New York City.The changes in weather and temperature are key factors for his inventory. The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40,40,48,61,72,78,84,84,76,65,54,42

Sample minimum: 40, Sample maximum: 84 Q1: 45, Median: 63, Q3: 77 The five-number summary must be found using a data set that is ordered from least to greatest. Once ordered, the sample minimum is the smallest value, and the sample maximum is the largest value. The median is the middle value, which separates the data set into a lower half and an upper half. Q1 is the median of the lower half of the data set, and Q3 is the median of the upper half of the data set.

John is the owner of a flower shop in New York City.The changes in weather and temperature are key factors for his inventory. The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40,40,48,61,72,78,84,84,76,65,54,42 Select the correct answer below: Sample minimum: 42, Sample maximum: 78 Q1: 45, Median: 63, Q3: 77 Sample minimum: 40, Sample maximum: 84 Q1: 45, Median: 63, Q3: 77 Sample minimum: 40, Sample maximum: 42 Q1: 54.5, Median: 81, Q3: 70.5 Sample minimum: 40, Sample maximum: 84 Q1: 40, Median: 61, Q3: 76

Sample minimum: 40, Sample maximum: 84 Q1: 45, Median: 63, Q3: 77 The five-number summary must be found using a data set that is ordered from least to greatest. Once ordered, the sample minimum is the smallest value, and the sample maximum is the largest value. The median is the middle value, which separates the data set into a lower half and an upper half. Q1 is the median of the lower half of the data set, and Q3 is the median of the upper half of the data set.

A production facilitator at a textile plant would like to find the mean number of rugs produced on a particular Monday. He collects data from 38 production lines in the textile plant. The graph shows the frequency for the number of rugs produced during this time period. Find the mean number of rugs produced for the 38 production lines, and round your answer to the nearest tenth. Record your answer by dragging the purple point to the mean.

The frequency graph shows the frequency for each data value. So, we can compute the mean by added up all the data values and dividing by the total number of data values. 7⋅1+10⋅2+8⋅3+4⋅4+6⋅5+2⋅6+1⋅7 = 38 116 ≈ 3.0526 38 Rounding to the nearest tenth, we have the mean is 3.1.

The following data set provides wage information of Seattle by subdivisions. Select all the statements that are true: Select all that apply: The lowest hourly rate in the Arts and Culture Department is the same as the lowest hourly rate in the City Budget Department. The lowest hourly rate in the Arts and Culture Department is the same as the lowest hourly rate in the City Auditor Department. The first quartile hourly rates in the City Auditor Department are within the pay range of the fourth quartile hourly rates in the Arts and Culture Department. The number of people in the second quartile in the City Auditor Department is different than the number of people in the third quartile of that department. The higest pay in the second quartile of the City Auditor employee hourly rate are within a dollar of the lowest pay in the third quartile.

The lowest hourly rate in the Arts and Culture Department is the same as the lowest hourly rate in the City Budget Department. The first quartile hourly rates in the City Auditor Department are within the pay range of the fourth quartile hourly rates in the Arts and Culture Department. The higest pay in the second quartile of the City Auditor employee hourly rate are within a dollar of the lowest pay in the third quartile. Three statements are true: A. The lowest hourly rate in the Arts and Culture Department is the same as the lowest hourly rate in the City Budget Department. Both are $16.12. C. The first quartile hourly rates in the City Auditor Department ($43.86 to $52.10) are within the pay range of the fourth quartile hourly rates in the Arts and Culture Department ($40.45 to $62.59). E. The highest pay in the second quartile of the City Auditor employee hourly rate ($56.07) is within a dollar of the lowest pay in the third quartile ($56.24). Two statements are false: B. The lowest hourly rate in the Arts and Culture Department ($16.12) is not the same as the lowest hourly rate in the City Auditor Department ($43.86). D. The number of people in the second quartile in the City Auditor Department is not different than the number of people in the third quartile of that department. Both quartiles have wage information on two people.